Due to a certain horizontal force frame shown below, the moments are Follows MAB = 5 kN.m (Anti clockwise) MBA = 10 kN.m (Anti clockwise) McD = 6 kN.m (Anti clockwise) he force 'P' is B P om s 11 5m od lliw Cons 2 m C 3 m D M- (6) SVM (0)
Due to a certain horizontal force frame shown below, the moments are Follows MAB = 5 kN.m (Anti clockwise) MBA = 10 kN.m (Anti clockwise) McD = 6 kN.m (Anti clockwise) he force 'P' is B P om s 11 5m od lliw Cons 2 m C 3 m D M- (6) SVM (0)
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
![. Due to a certain horizontal force 'P' on the
frame shown below, the moments are as
follows
MAB=5 kN.m (Anti clockwise)
MBA = 10 kN.m (Anti clockwise)
McD = 6 kN.m (Anti clockwise)
The force 'P' is
B
om 8
P
5 m
A
2 m
C
3 m
D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4c33952a-6cfa-42e4-b301-0ae6f03d6dc7%2Fe9facfb7-accd-40d0-9a50-1f3a42320d63%2Fver0vkn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:. Due to a certain horizontal force 'P' on the
frame shown below, the moments are as
follows
MAB=5 kN.m (Anti clockwise)
MBA = 10 kN.m (Anti clockwise)
McD = 6 kN.m (Anti clockwise)
The force 'P' is
B
om 8
P
5 m
A
2 m
C
3 m
D
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