. Calculate AH1000 and AS1000 for the following reaction: Pb (1) + 0.502(g) ---> PbO (s) For Lead: Tm = 600 K, AHm = 4,810 J/mol CP(s) = 23.6+9.75E-3T J/mol CP(I) = 32.4- 3.10E-3T J/mol AH°298 = 0J/mol S298 = 64.9 J/K (298-600K} {600-1200K) For Lead Oxide: Tm = 1158 K, AHm = 27,490 J/mol CP(s) = 37.9+ 26.8E-3T J/mol (298-1200K} AH°298 = -219,000 J/mol S298 = 67.4 J/K For Oxygen: CP(g) = 30.0 +4.18E-3T - 1.7E-5T²J/mol AH°298 = 0 J/mol S298 = 205 J/K
. Calculate AH1000 and AS1000 for the following reaction: Pb (1) + 0.502(g) ---> PbO (s) For Lead: Tm = 600 K, AHm = 4,810 J/mol CP(s) = 23.6+9.75E-3T J/mol CP(I) = 32.4- 3.10E-3T J/mol AH°298 = 0J/mol S298 = 64.9 J/K (298-600K} {600-1200K) For Lead Oxide: Tm = 1158 K, AHm = 27,490 J/mol CP(s) = 37.9+ 26.8E-3T J/mol (298-1200K} AH°298 = -219,000 J/mol S298 = 67.4 J/K For Oxygen: CP(g) = 30.0 +4.18E-3T - 1.7E-5T²J/mol AH°298 = 0 J/mol S298 = 205 J/K
Applications and Investigations in Earth Science (9th Edition)
9th Edition
ISBN:9780134746241
Author:Edward J. Tarbuck, Frederick K. Lutgens, Dennis G. Tasa
Publisher:Edward J. Tarbuck, Frederick K. Lutgens, Dennis G. Tasa
Chapter1: The Study Of Minerals
Section: Chapter Questions
Problem 1LR
Related questions
Question
![1.
Calculate AH1000 and AS1000 for the following reaction:
For Lead:
Tm = 600 K, AHm = 4,810 J/mol
CP(s) = 23.6 +9.75E-3T J/mol
CP(1) = 32.4-3.10E-3T J/mol
AH* 298 = 0 J/mol
S298 = 64.9 J/K
Pb() + 0.502(g) ---> PbO (s)
S298
For Lead Oxide:
Tm = 1158 K, AHm = 27,490 J/mol
CP(S) = 37.9+ 26.8E-3T J/mol (298-1200K}
AH 298 = -219,000 J/mol
= 67.4 J/K
{298-600K)
{600-1200K}
For Oxygen:
CP(g) = 30.0 +4.18E-3T - 1.7E-5T²J/mol
AH°298 = 0 J/mol
S298 = 205 J/K](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8b00a80b-0cea-48b5-891f-9a9beccbf082%2F0d885aca-5498-418c-8de8-a05891427986%2F53l925n_processed.png&w=3840&q=75)
Transcribed Image Text:1.
Calculate AH1000 and AS1000 for the following reaction:
For Lead:
Tm = 600 K, AHm = 4,810 J/mol
CP(s) = 23.6 +9.75E-3T J/mol
CP(1) = 32.4-3.10E-3T J/mol
AH* 298 = 0 J/mol
S298 = 64.9 J/K
Pb() + 0.502(g) ---> PbO (s)
S298
For Lead Oxide:
Tm = 1158 K, AHm = 27,490 J/mol
CP(S) = 37.9+ 26.8E-3T J/mol (298-1200K}
AH 298 = -219,000 J/mol
= 67.4 J/K
{298-600K)
{600-1200K}
For Oxygen:
CP(g) = 30.0 +4.18E-3T - 1.7E-5T²J/mol
AH°298 = 0 J/mol
S298 = 205 J/K
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