23. Answer must code. 12 Integer base conversion algorithm34 int_to_base(5, 2) return '101'.5 base_to_int('F', 16) return 15.678911 T1011121314151617181920212223242526272829303132333435363738394041424344454647484911 11 11import stringdef int_to_base(num, base):|| || ||:type num: int:type base: int:rtype: stris_negative = Falseif num == 0:return '0'if num < 0:is_negative = Truenum *= -1digit = string.digits + string.ascii_uppercaseres =while num > 0:11res += digit [num % base]num //= baseif is negative:111111return '-' + res[::-1]return res[::-1]def base_to_int (str_to_convert, base):Note: You can use int() built-in function instead of this.:type str_to_convert: str:type base: int:rtype: intdigit = {}for ind, char indigit [char]multiplier = 1res = 0for char in str_to_convert[::-1]:res +=digit[char] * multipliermultiplier *= basereturn resenumerate(string.digits+string.ascii_uppercase):= ind

The code provided contains two functions: int_to_base and base_to_int, which perform integer base…

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Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Concept explainers

LUP Decomposition

LU decomposition stands for Lower-Upper decomposition. LU decomposition is the factorization of the lower triangular matrix and an upper triangular matrix. It is very useful in linear algebra and numerical analysis. A permutation matrix is usually included in the product. Gaussian elimination in a matrix form is known as LU decomposition, When inverting a matrix or evaluating its determinant, this is a crucial step. Tadeusz Banachiewicz, a Polish mathematician, first proposed the LU decomposition in 1938.

Question

23. Answer must code.

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import string
def int_to_base(num, base):
|| || ||
:type num: int
:type base: int
:rtype: str
is_negative = False
if num == 0:
return '0'
if num < 0:
is_negative = True
num *= -1
digit = string.digits + string.ascii_uppercase
res =
while num > 0:
11
res += digit [num % base]
num //= base
if is negative:
111111
return '-' + res[::-1]
return res[::-1]
def base_to_int (str_to_convert, base):
Note: You can use int() built-in function instead of this.
:type str_to_convert: str
:type base: int
:rtype: int
digit = {}
for ind, char in
digit [char]
multiplier = 1
res = 0
for char in str_to_convert[::-1]:
res +=
digit[char] * multiplier
multiplier *= base
return res
enumerate(string.digits+string.ascii_uppercase):
= ind

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