. Answer must
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
23. Answer must code.
![1
2 Integer base conversion algorithm
3
4 int_to_base(5, 2) return '101'.
5 base_to_int('F', 16) return 15.
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11 11 11
import string
def int_to_base(num, base):
|| || ||
:type num: int
:type base: int
:rtype: str
is_negative = False
if num == 0:
return '0'
if num < 0:
is_negative = True
num *= -1
digit = string.digits + string.ascii_uppercase
res =
while num > 0:
11
res += digit [num % base]
num //= base
if is negative:
111111
return '-' + res[::-1]
return res[::-1]
def base_to_int (str_to_convert, base):
Note: You can use int() built-in function instead of this.
:type str_to_convert: str
:type base: int
:rtype: int
digit = {}
for ind, char in
digit [char]
multiplier = 1
res = 0
for char in str_to_convert[::-1]:
res +=
digit[char] * multiplier
multiplier *= base
return res
enumerate(string.digits+string.ascii_uppercase):
= ind](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F57bcf795-7b7b-45fd-a8ab-7fc3e4f54e2e%2F26b33b4b-584d-4836-8ce5-f503f157afdd%2Fm30irt_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1
2 Integer base conversion algorithm
3
4 int_to_base(5, 2) return '101'.
5 base_to_int('F', 16) return 15.
6
7
8
9
11 T
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12
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11 11 11
import string
def int_to_base(num, base):
|| || ||
:type num: int
:type base: int
:rtype: str
is_negative = False
if num == 0:
return '0'
if num < 0:
is_negative = True
num *= -1
digit = string.digits + string.ascii_uppercase
res =
while num > 0:
11
res += digit [num % base]
num //= base
if is negative:
111111
return '-' + res[::-1]
return res[::-1]
def base_to_int (str_to_convert, base):
Note: You can use int() built-in function instead of this.
:type str_to_convert: str
:type base: int
:rtype: int
digit = {}
for ind, char in
digit [char]
multiplier = 1
res = 0
for char in str_to_convert[::-1]:
res +=
digit[char] * multiplier
multiplier *= base
return res
enumerate(string.digits+string.ascii_uppercase):
= ind
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