. An automobile of mass M=5400 kg is moving at a speed of 30 m/s.The engine is disengaged suddenly at t= 0 sec. Assume that the equation of motion after t=0 is given by 5400 v= -8.276 v² – 2000 Where v= v(t) is the speed (m/sec) of the car at t. The left side represents Mv (dv/dx).The first term on the right side is the aerodynamics drag, I1 term is the rolling resistance of the tires. Calculate how far the car travels until the speed reduces to 15 m/sec.(hint: the equation of motion may be integrated as land the second 5400 v dv 15 8.276 v2+2000 f dx = x Evaluate the preceding equation using Simpson rule).
. An automobile of mass M=5400 kg is moving at a speed of 30 m/s.The engine is disengaged suddenly at t= 0 sec. Assume that the equation of motion after t=0 is given by 5400 v= -8.276 v² – 2000 Where v= v(t) is the speed (m/sec) of the car at t. The left side represents Mv (dv/dx).The first term on the right side is the aerodynamics drag, I1 term is the rolling resistance of the tires. Calculate how far the car travels until the speed reduces to 15 m/sec.(hint: the equation of motion may be integrated as land the second 5400 v dv 15 8.276 v2+2000 f dx = x Evaluate the preceding equation using Simpson rule).
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
![1. An automobile of mass M=5400 kg is moving at a speed of 30 m/s.The engine is disengaged
suddenly at t= 0 sec. Assume that the equation of motion after t=0 is given by
dv
5400 v = -8.276 v2 – 2000
dx
Where v= v(t) is the speed (m/sec) of the car at t. The left side represents Mv (dv/dx).The first
wMand the second
term on the right side is the aerodynamics drag,
term is the rolling resistance of the tires. Calculate how far the car travels until the speed
reduces to 15 m/sec.(hint: the equation of motion may be integrated as
5400 v dv
30
J15 8.276 v242000
Evaluate the preceding equation using Simpson rule).
f dx = x](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdb1d9a05-f2fb-4e13-a9ed-74ba506de5d2%2F12a1c2cf-41d3-4fef-8efc-5ba279bd7685%2F84w1e7s_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1. An automobile of mass M=5400 kg is moving at a speed of 30 m/s.The engine is disengaged
suddenly at t= 0 sec. Assume that the equation of motion after t=0 is given by
dv
5400 v = -8.276 v2 – 2000
dx
Where v= v(t) is the speed (m/sec) of the car at t. The left side represents Mv (dv/dx).The first
wMand the second
term on the right side is the aerodynamics drag,
term is the rolling resistance of the tires. Calculate how far the car travels until the speed
reduces to 15 m/sec.(hint: the equation of motion may be integrated as
5400 v dv
30
J15 8.276 v242000
Evaluate the preceding equation using Simpson rule).
f dx = x
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