. Ammonia, NH3, is a base and will readily accept a proton in accordance with the following reaction NHlaq) + H,O =NH,* + OH- (a) Calculate the equilibrium constant, K, for this reaction at 25°C. (b) If, at some time, pH reaction at equilibrium? If not, in which direction is the reaction going? 9.0, [NH3} = 10-5 M, and [NH,+] 10-6 M, is the
. Ammonia, NH3, is a base and will readily accept a proton in accordance with the following reaction NHlaq) + H,O =NH,* + OH- (a) Calculate the equilibrium constant, K, for this reaction at 25°C. (b) If, at some time, pH reaction at equilibrium? If not, in which direction is the reaction going? 9.0, [NH3} = 10-5 M, and [NH,+] 10-6 M, is the
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
Transcribed Image Text:6. Ammonia, NH3, is a base and will readily accept a proton in accordance
with the following reaction
NHxaq) + H,O=NH,+ + OH-
(a) Calculate the equilibrium constant, K, for this reaction at 25°C.
(b) If, at some time, pH
reaction at equilibrium? If not, in which direction is the reaction going?
9.0, [NH3}
= 10-5 M, and [NH,*}
10-6 М, is the
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