. Add Ca(OH)2 to 250.0 mL distilled water with stirring until equilibrium is achieved.

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Chapter1: Chemical Foundations
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pls complete table given the data 

Determination of Ksp and Molar Solubility
1. Add Ca(OH)2 to 250.0 mL distilled water with stirring until equilibrium is achieved. 
2. Filter the undissolved precipitate. Measure out 50.0 mL of the supernate into a 250-mL Erlenmeyer flask 
using a pipette.
3. Add a few drops of phenolphthalein indicator and titrate with standardized HCl solution until endpoint 
is achieved.
4. Record the volume the HCl solution used. Perform two more trials. 

Standardization of Hydrochloric Acid Solution
Answer the concentrations in 3 significant figure.
You can use scientific notation using "e". Example: 0.0010 = 1.0e-3
Primary Standard Used: Na2C03
Formula Mass of 1° standard: 105.99 g/mol
%purity of 1° standard: 95%
Trial
2
3
1° Standard weight, g
0.1005
0.1001
0.0997
Net volume of HCI, mL
9.30
9.00
8.90
M HCI
0.193
0.199
0.200
Average M HCI
0.1980
Transcribed Image Text:Standardization of Hydrochloric Acid Solution Answer the concentrations in 3 significant figure. You can use scientific notation using "e". Example: 0.0010 = 1.0e-3 Primary Standard Used: Na2C03 Formula Mass of 1° standard: 105.99 g/mol %purity of 1° standard: 95% Trial 2 3 1° Standard weight, g 0.1005 0.1001 0.0997 Net volume of HCI, mL 9.30 9.00 8.90 M HCI 0.193 0.199 0.200 Average M HCI 0.1980
Determination of Ksp and Solubility of Ca(OH)2
Answer the concentrations, solubility, and Ksp in 3 significant figure.
You can use scientific notation using "e". Example: 0.0010 = 1.0e-3
Trial
1
3
Volume of filtrate (mL)
50
50
50
Net volume of HCI, mL
11.2
11.2
11.4
[OH:], M
0.0444
0.0444
0.0451 M
[Ca 2+), M
Solubility of Ca(OH)2
Ksp of Ca(OH)2
Average solubility
Average Ksp
Theoretical Ksp
5.50e-6
% error
Please answer all parts of the question.
Transcribed Image Text:Determination of Ksp and Solubility of Ca(OH)2 Answer the concentrations, solubility, and Ksp in 3 significant figure. You can use scientific notation using "e". Example: 0.0010 = 1.0e-3 Trial 1 3 Volume of filtrate (mL) 50 50 50 Net volume of HCI, mL 11.2 11.2 11.4 [OH:], M 0.0444 0.0444 0.0451 M [Ca 2+), M Solubility of Ca(OH)2 Ksp of Ca(OH)2 Average solubility Average Ksp Theoretical Ksp 5.50e-6 % error Please answer all parts of the question.
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