. A test charge of +2µC is placed halfway between a charge of +6µC and another of +4µC separated by distance 2d = 9 cm. +4uC d 91 = +4µC +2μC The free body diagram of q2 from Part 1 should look like this: F3-2 d q2 = +2 μC F₁-2 +6μС F3+2 > F1-2 X 93 = +6 μC The force on q2 due to q₁ is repulsive and acts to the right. The force on q2 due to q3 is repulsive and acts to the left. because 9391. (a) Calculate the force on the test charge by the +6μC charge. Hint: The force in the positive x-direction is positive and the negative x direction is negative.

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(a) Calculate the force on the test charge by the +6μC charge.
Hint: The force in the positive x-direction is positive and the negative x direction is negative.
✔N
(b) Calculate the force on the test charge by the +4µC charge.
N
(c) Calculate the net force on the test charge by both the charges.
35.52
N
Transcribed Image Text:(a) Calculate the force on the test charge by the +6μC charge. Hint: The force in the positive x-direction is positive and the negative x direction is negative. ✔N (b) Calculate the force on the test charge by the +4µC charge. N (c) Calculate the net force on the test charge by both the charges. 35.52 N
1. A test charge of +2µC is placed halfway between a charge of +6µC and another of +4µC separated by
distance 2d = 9 cm.
+4μC
9₁ = +4 µC
d
because 9391.
>
The free body diagram of q2 from Part 1 should look like this:
+2μC
F3-2
d
q2 = +2 μC
F1-2
+6µC
F3+2 > F1+2
X
The force on q2 due to q₁ is repulsive and acts to the right. The force on q₂ due to q3 is repulsive and
acts to the left.
q3 = +6 μC
(a) Calculate the force on the test charge by the +6µC charge.
Hint: The force in the positive x-direction is positive and the negative x direction is negative.
Transcribed Image Text:1. A test charge of +2µC is placed halfway between a charge of +6µC and another of +4µC separated by distance 2d = 9 cm. +4μC 9₁ = +4 µC d because 9391. > The free body diagram of q2 from Part 1 should look like this: +2μC F3-2 d q2 = +2 μC F1-2 +6µC F3+2 > F1+2 X The force on q2 due to q₁ is repulsive and acts to the right. The force on q₂ due to q3 is repulsive and acts to the left. q3 = +6 μC (a) Calculate the force on the test charge by the +6µC charge. Hint: The force in the positive x-direction is positive and the negative x direction is negative.
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