Answered: . A simple harmonic oscillator consists… | bartleby

Related questions

Question

Q11. A simple harmonic oscillator consists of a block of mass 1.45 kg attached to a spring of spring
constant 54.4 N/m. When t=0.670 s, the position of the block is x=0.0565 m (from the equilibrium
position) and its velocity is v=0.342 m/s.
A. What is the angular frequency of the oscillation?
B. What is the amplitude of the oscillation?
C. What is the phase constant for the oscillation?
D. What was the velocity at t=0?

Expert Solution

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

exaplin D E F only
A mass of 0.340kg oscillates up and down on a spring with a spring constant 45.0 N/m. What is the angular frequency of this motion?
An undamped 1.20 kg1.20 kg horizontal spring oscillator has a spring constant of 39.4 N/m.39.4 N/m. While oscillating, it is found to have a speed of 3.86 m/s3.86 m/s as it passes through its equilibrium position. What is its amplitude ?A of oscillation?
What frequency is depicted in the following equation of an oscillator? Assume that the units work out and the amplitude is in millimeters and the time tt is in seconds. x(t)=−2.2sin(40t−π3)x(t)=−2.2sin⁡(40t−π3) a. 6Hz6Hz b. 20πHz20πHz c. 16Hz16Hz d. 180πHz180πHz e. π20Hzπ20Hz f. 80πHz80πHz
You pull a simple pendulum 0.240 m long to the side through an angle of 3.50° and release it. a. How much time does it take the pendulum bob to reach its highest speed? b. How much time does it take if the pendulum is released at an angle of 1.75⁰ instead of 3.50°?
A 50-cm-long spring is suspended from the ceiling. A 250 g mass is connected to the end and held at rest with the spring unstretched. The mass is released and falls, stretching the spring by 20 cm before coming to rest at its lowest point. It then continues to oscillate vertically. a. What is the spring constant?b. What is the amplitude of the oscillation? c. What is the frequency of the oscillation?
The function: y = 6.0 m * cos (5.0 rad/s * t + 1.0 rad) describes the simple harmonic motion for a system. What is the amplitude: m What is the is the angular velocity: rad/s What is the phase constant: rad What is the displacement from equilibrium at t = 3.0 s: m (make sure your calculator is in radian mode)
Your answer is partially correct. A point on the surface of a solid sphere (radius= 0.954 m) is attached directly to a pivot on the ceiling. The sphere swings back and forth as a physical pendulum with a small amplitude. What is the length of a simple pendulum that has the same period as this physical pendulum? Number i 381.6 Units m
7. A spring with a spring constant of 55 N/m² is set up horizontally on a frictionless surface with a 3.5 kg mass attached to the spring. If the mass is stretched 0.125 m from equilibrium and released from rest then determine the following:
4. After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 49.0 cm . The explorer finds that the pendulum completes 90.0 full swing cycles in a time of 145s. What is the magnitude of the gravitational acceleration on this planet?
A mass og 2.42kg is attached to a single spring such that the maximum velocity of the oscillation is 1.57 m/s and period is 1.78 sec. A=0.445m, x= 0.315m. a. What is the velocity of the mass at half the amplitude?
7. A 0.250 kg block oscillates on a spring horizontally on a frictionless surface. The spring has a spring constant of 200 N/m. The amplitude of the oscillations is 24.5 cm. a. What is the period of this mass-spring system (in seconds)? b. What is the maximum speed of the block (in m/s)?