. A microscope is sharply focused on a mark at 5.7 cm. If a parallel plate of glass is placed over the mark, Where will the focus be if the index of refraction of the glass is 1.52?
Refraction of Light
Refraction is a change in the direction of light rays when they travel from one medium to another. It is the bending of light when it goes through different media.
Angle of Refraction
Light is considered by many scientists to have dual nature, both particle nature and wave nature. First, Particle nature is one in which we consider a stream of packets of energy called photons. Second, Wave nature is considering light as electromagnetic radiation whereas part of it is perceived by humans. Visible spectrum defined by humans lies in a range of 400 to 700 nm wavelengths.
Index of Refraction of Diamond
Diamond, the world’s hardest naturally occurring material and mineral known, is a solid form of the element carbon. The atoms are arranged in a crystal structure called diamond cubic. They exist in a huge variety of colours. Also, they are one of the best conductors of heat and have a very high melting point.
M11
A case problem is attached.
1. A microscope is sharply focused on a mark at 5.7 cm. If a parallel plate of glass is placed over the mark, Where will the focus be if the index of refraction of the glass is 1.52?
Answer = 8.66 cm
Please show the solution
![APPARENT DEPTH
Formula:
Apparent Depth = n2
Actual Depth
n1
Where:
Apparent Depth: is the distance due to refraction
Actual Depth: originates distance from the surface
n2: index of refraction of the 2d medium
n1: index of refraction of the 1ª medium (where the incident ray comes from)
Example Case Problem
Given:
Actual Depth: 6 inches
n2= 1.33 water
n1- 1.0 air
ni1.0 air
na-1.33 water](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbdf3e054-ee56-4377-b23d-32ae48b1250c%2Fce675cda-7c57-47b1-a028-3165855aa3f1%2Fsw5dmf_processed.png&w=3840&q=75)
![APPARENT DEPTH
Formula:
Apparent Depth = n2
Actual Depth
n1
Where:
Apparent Depth: is the distance due to refraction
Actual Depth: originates distance from the surface
n2: index of refraction of the 2d medium
n1: index of refraction of the 1ª medium (where the incident ray comes from)
Example Case Problem
Given:
Actual Depth: 6 inches
n2= 1.33 water
n1- 1.0 air
ni1.0 air
na-1.33 water](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbdf3e054-ee56-4377-b23d-32ae48b1250c%2Fce675cda-7c57-47b1-a028-3165855aa3f1%2Fu2tf0k_processed.png&w=3840&q=75)
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