. A microscope is sharply focused on a mark at 5.7 cm. If a parallel plate of glass is placed over the mark, Where will the focus be if the index of refraction of the glass is 1.52?

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Chapter25: Geometric Optics
Section: Chapter Questions
Problem 17PE: Unreasonable Results Suppose light travels from water to another substance, with an angle of...
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A case problem is attached.

1. A microscope is sharply focused on a mark at 5.7 cm. If a parallel plate of glass is placed over the mark, Where will the focus be if the index of refraction of the glass is 1.52?

Answer = 8.66 cm
Please show the solution

APPARENT DEPTH
Formula:
Apparent Depth = n2
Actual Depth
n1
Where:
Apparent Depth: is the distance due to refraction
Actual Depth: originates distance from the surface
n2: index of refraction of the 2d medium
n1: index of refraction of the 1ª medium (where the incident ray comes from)
Example Case Problem
Given:
Actual Depth: 6 inches
n2= 1.33 water
n1- 1.0 air
ni1.0 air
na-1.33 water
Transcribed Image Text:APPARENT DEPTH Formula: Apparent Depth = n2 Actual Depth n1 Where: Apparent Depth: is the distance due to refraction Actual Depth: originates distance from the surface n2: index of refraction of the 2d medium n1: index of refraction of the 1ª medium (where the incident ray comes from) Example Case Problem Given: Actual Depth: 6 inches n2= 1.33 water n1- 1.0 air ni1.0 air na-1.33 water
APPARENT DEPTH
Formula:
Apparent Depth = n2
Actual Depth
n1
Where:
Apparent Depth: is the distance due to refraction
Actual Depth: originates distance from the surface
n2: index of refraction of the 2d medium
n1: index of refraction of the 1ª medium (where the incident ray comes from)
Example Case Problem
Given:
Actual Depth: 6 inches
n2= 1.33 water
n1- 1.0 air
ni1.0 air
na-1.33 water
Transcribed Image Text:APPARENT DEPTH Formula: Apparent Depth = n2 Actual Depth n1 Where: Apparent Depth: is the distance due to refraction Actual Depth: originates distance from the surface n2: index of refraction of the 2d medium n1: index of refraction of the 1ª medium (where the incident ray comes from) Example Case Problem Given: Actual Depth: 6 inches n2= 1.33 water n1- 1.0 air ni1.0 air na-1.33 water
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