. A clothes 800 W iron is designed to be used with a 220 V outlet. How much current will flow in the circuit if the iron is plugged into a 110 V outlet instead of a 220 V outlet?
. A clothes 800 W iron is designed to be used with a 220 V outlet. How much current will flow in the circuit if the iron is plugged into a 110 V outlet instead of a 220 V outlet?
Chapter19: Special-purpose Outlets-water Pump, Water Heater
Section19.2: Water Heater Branch Circuit
Problem 17R: a. If both elements of the water heater in this residence are energized at the same time, how much...
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![### Electrical Current Calculation for a Clothes Iron
**Problem Statement:**
A clothes 800 W iron is designed to be used with a 220 V outlet. How much current will flow in the circuit if the iron is plugged into a 110 V outlet instead of a 220 V outlet?
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**Solution:**
**Step 1:** Determine the resistance of the iron using the power (P) and voltage (V) for which it was designed.
\[ P = \frac{V^2}{R} \]
Where:
- \( P \) is the power (800 W)
- \( V \) is the designed voltage (220 V)
- \( R \) is the resistance
Rearranging the formula to solve for resistance:
\[ R = \frac{V^2}{P} = \frac{(220 \, \text{V})^2}{800 \, \text{W}} \]
\[ R = \frac{48400}{800} \]
\[ R = 60.5 \, \Omega \]
**Step 2:** Use the resistance to find the current (\( I \)) when the iron is plugged into a 110 V outlet.
\[ V = IR \]
\[ I = \frac{V}{R} = \frac{110 \, \text{V}}{60.5 \, \Omega} \]
\[ I \approx 1.82 \, \text{A} \]
So, the current flowing through the iron when plugged into a 110 V outlet will be approximately 1.82 A.
---
**Explanation of Concepts:**
- **Power (P):** The rate at which electrical energy is being used by a device. Measured in Watts (W).
- **Voltage (V):** The electrical potential difference which, when applied across a device, drives an electric current through it. Measured in Volts (V).
- **Resistance (R):** A measure of how much a device opposes the flow of electric current. Measured in Ohms (Ω).
- **Current (I):** The flow of electric charge through a device, measured in Amperes (A).
Understanding these fundamental electrical concepts can help solve various problems related to electric circuits and devices.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdf83f524-335e-40cf-92c0-f811e33ace40%2F28a698c3-0e74-44a9-9c92-2d85ab75ca36%2Fk03jgd8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Electrical Current Calculation for a Clothes Iron
**Problem Statement:**
A clothes 800 W iron is designed to be used with a 220 V outlet. How much current will flow in the circuit if the iron is plugged into a 110 V outlet instead of a 220 V outlet?
---
**Solution:**
**Step 1:** Determine the resistance of the iron using the power (P) and voltage (V) for which it was designed.
\[ P = \frac{V^2}{R} \]
Where:
- \( P \) is the power (800 W)
- \( V \) is the designed voltage (220 V)
- \( R \) is the resistance
Rearranging the formula to solve for resistance:
\[ R = \frac{V^2}{P} = \frac{(220 \, \text{V})^2}{800 \, \text{W}} \]
\[ R = \frac{48400}{800} \]
\[ R = 60.5 \, \Omega \]
**Step 2:** Use the resistance to find the current (\( I \)) when the iron is plugged into a 110 V outlet.
\[ V = IR \]
\[ I = \frac{V}{R} = \frac{110 \, \text{V}}{60.5 \, \Omega} \]
\[ I \approx 1.82 \, \text{A} \]
So, the current flowing through the iron when plugged into a 110 V outlet will be approximately 1.82 A.
---
**Explanation of Concepts:**
- **Power (P):** The rate at which electrical energy is being used by a device. Measured in Watts (W).
- **Voltage (V):** The electrical potential difference which, when applied across a device, drives an electric current through it. Measured in Volts (V).
- **Resistance (R):** A measure of how much a device opposes the flow of electric current. Measured in Ohms (Ω).
- **Current (I):** The flow of electric charge through a device, measured in Amperes (A).
Understanding these fundamental electrical concepts can help solve various problems related to electric circuits and devices.
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