. A biker is accelerating when she applies the brakes and then speeds up again. The net horizontal force is shown in the graph. Assume she moves in a 20 straight line and the mass of the biker and bike is 80 kg. The biker was moving at 8 m/s at t = 0. How fast is she moving at t = 20 s? 8 12 time (sec) 16 20 net x-Force (Newtons) 20

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**Problem Statement:**

3. A biker is accelerating when she applies the brakes and then speeds up again. The net horizontal force is shown in the graph. Assume she moves in a straight line and the mass of the biker and bike is 80 kg. The biker was moving at 8 m/s at \( t = 0 \). How fast is she moving at \( t = 20 \, \text{s} \)?

**Graph Description:**

The graph is a plot of net force in the \(x\)-direction (in Newtons) against time (in seconds).

- From \( t = 0 \) to \( t = 5 \, \text{s} \), the force is constant at \( 30 \, \text{N} \).
- From \( t = 5 \, \text{s} \) to \( t = 10 \, \text{s} \), the force drops to \(-30 \, \text{N} \).
- From \( t = 10 \, \text{s} \) to \( t = 15 \, \text{s} \), the force linearly increases back to \( 0 \, \text{N} \).
- From \( t = 15 \, \text{s} \) to \( t = 20 \, \text{s} \), the force increases further to \( 20 \, \text{N} \).
Transcribed Image Text:**Problem Statement:** 3. A biker is accelerating when she applies the brakes and then speeds up again. The net horizontal force is shown in the graph. Assume she moves in a straight line and the mass of the biker and bike is 80 kg. The biker was moving at 8 m/s at \( t = 0 \). How fast is she moving at \( t = 20 \, \text{s} \)? **Graph Description:** The graph is a plot of net force in the \(x\)-direction (in Newtons) against time (in seconds). - From \( t = 0 \) to \( t = 5 \, \text{s} \), the force is constant at \( 30 \, \text{N} \). - From \( t = 5 \, \text{s} \) to \( t = 10 \, \text{s} \), the force drops to \(-30 \, \text{N} \). - From \( t = 10 \, \text{s} \) to \( t = 15 \, \text{s} \), the force linearly increases back to \( 0 \, \text{N} \). - From \( t = 15 \, \text{s} \) to \( t = 20 \, \text{s} \), the force increases further to \( 20 \, \text{N} \).
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