. 2y(x + y+2)dx + (y² – x² – 4x – 1)dy = 0 - .xy² + 4xy + 2x² + y³ + y = C .x²y + 4xy+ 2x² + y³ + y = C .xy² + 4xy + 2x² + y² + y = C 1.None of the above A B D
. 2y(x + y+2)dx + (y² – x² – 4x – 1)dy = 0 - .xy² + 4xy + 2x² + y³ + y = C .x²y + 4xy+ 2x² + y³ + y = C .xy² + 4xy + 2x² + y² + y = C 1.None of the above A B D
. 2y(x + y+2)dx + (y² – x² – 4x – 1)dy = 0 - .xy² + 4xy + 2x² + y³ + y = C .x²y + 4xy+ 2x² + y³ + y = C .xy² + 4xy + 2x² + y² + y = C 1.None of the above A B D
2y(x+y+2)dx+(y^2-x^2-4x-1)dy=0 determination of integrating factors by inspection
Transcribed Image Text:1. 2y(x + y + 2)dx + (y² – x² – 4x – 1)dy = 0
a.xy? + 4xy + 2x² + y³ + y = C
b.x²y+ 4xy + 2x² + y³ +y = C
c.xy? + 4xy + 2x² + y² + y = C
d. None of the above
A
O D
With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.
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