Unit 4B Project(3)
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School
Bellevue University *
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Course
215
Subject
Statistics
Date
Apr 3, 2024
Type
xlsx
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14
Uploaded by BailiffApeMaster1116
Congrats on making it to the final project! I hope you have found this class interesting and valuable. Our last project is focused on the last 3 chapters of our textbook dealing mostly with testing hypotheses. We are very skilled now in estimating the population parameter for mean or proportion based on our sample data. Now we want to take it one step further and test our sample data against what we might expect to see. For instance, if the average course grade in MA215 is generally 85%, but changes were made to the class to improve that grade, we would collect a sample and compare it to the 85% that we expect to see. In your Hawkes coursework you will determine how best to do this.
One thing to keep in mind throughout the project is that I want you to create confidence intervals that correspond to your hypothesis test. Many get confused when determining the correct level of confidence. Here is what you should keep in mind:
If I perform a left-tailed test using an alpha level of 0.05, then to create a corresponding confidence interval to give us the values we might expect to see, we would need to think about putting the same area on the right of our model, as well. So instead of creating a 95% confidence interval (which is what we would normally do with an alpha level of 0.05), we would create a 90% interval, leaving 5% in each tail.
However, if I performed a 2-tailed test (where the alternative hypothesis is "not equal to") with an alpha level of 0.05, then I would use a 95% interval to back up my results.
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A
Sample Proportion (p-hat)
0.364667747 Formula
Expected Proportion (p)
0.32Data Entry
1 - p
0.68 Formula
Sample Size (n)
1234Data Entry
1 pt
Z-Score
3.363738171 Formula
1 pt
Probability (right tailed)
0.000384472 Function
Inputs 1 pt
e sure you are paying attention to what is expected in each cell. For instance, lets say I wanted to answer the uestion:
We expect 32% of plain M&M's to be brown. In a sample of 1234 M&M's, we found 450 to be brown. Is this vidence that the M&M factory produces more than 32% brown M&M's?
or our sample proportion (formula), I would enter =450/1234. Notice that the cell contains the solution to tha
vision problem, but if I click on it, I can see that I entered 450/1234. For a formula we will enter = and then so
alue to be calculated.
or expected proportion (data entry), I simply enter 0.32 from the question, as that is what we expect.
or 1-p (formula), I use =1-Y3, which gives me 0.68 as a solution.
or sample size (data entry) I enter 1234, which is the size of the sample.
ow, for z-score I am going to use all of the inputs I just entered. So intead of typing them all in again, I will sim
ut =(Y2-Y3)/SQRT(Y3*Y4/Y5) and let Excel calulate the z-score for me.
or probability (right tailed), which is a function, I will enter 1-NORM.S.DIST(Y6,1). Remember a function uses omething like NORM.S.DIST or STANDARDIZE or some other Excel function.
e sure you are utilizing the inputs, even if they aren't graded, and paying attention to what I will be looking for
ach cell: formula, data entry or function.
so, recall that non-graded cells are locked so that all items to be graded are contained within the cell itself
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Name
Drop (ft)
Speed (mph)
Millennium Force 300
93
Goliath 255
85
Titan 255
85
Phantom's Revenge 228
82
Xcelerator 130
82
Desperado 225
80
HyperSonic XLC 133
80
Nitro 215
80
Phantom's Revenge 225
80
Son Of Beast 214
78.4
Superman - Ride Of Steel 221
77
X
215
76
Mamba 205
75
Steel Force 205
75
Wild Thing 196
74
Apollo's Chariot 210
73
Raging Bull 208
73
Rattler 166.5
73
Superman - Ride Of Steel 205
73
Magnum XL-200 194.6
72
Viper 171
70
Volcano The Blast Coaster
80
70
Great American Scream Machine 155
68
Alpengeist 170
67
Incredible Hulk 105
67
Manhattan Express 144
67
Boss 150
66.3
American Eagle 147
66
Wildfire 155
66
Deja Vu 177
65.6
Batman Knight Flight 148
65
Hercules 151
65
Kraken 144
65
Mean Streak 155
65
Medusa 150
65
Orient Express 115
65
Rattler 124
65
Riddler's Revenge 146
65
Steel Eel 150
65
Texas Giant 137
65
Beast 141
64.8
Chang 144
63
Scream! 141
63
Tennessee Tornado 128
63
Colossus 115
62
Screamin' Eagle 92
62
Hangman 95
55
Hurricane 100
55
Invertigo 138
55
Iron Wolf 90
55
Kong 95
55
Mind Eraser 95
55
Silver Bullet 75
55
Starliner 76
55
T2 95
55
Thunderbolt 95
55
Timber Wolf 95
53
Wild One 88
53
Cheetah 90
52
Cannon Ball 70
50
Coaster Thrill Ride 52
50
Comet 78
50
1 pt
A
Null Hypothesis
µ
=
0
Data Entry
1 pt
Alternative Hypothesis
µ
>
0
Alt Hyp (choose)
1 pt
Sample Mean (x-bar)
3.01
Data Entry
1.4
Data Entry
Sample Size (n)
40
Data Entry
alpha-level
0.02
Data Entry
1 pt
z-Score
1.17456027377683
Formula
1 pt
p-value
0.12008534230535
Function
2 pts
1 pt
B
Critical Value
2.05374891063182
Function
Margin of Error
0.45461670097803
Formula
Confidence Interval
2.55538329902197 3.464616700978
(Lower Limit,
Upper Limit)
2 pts
Population Standard Deviation (σ)
With p=0.120 > a=0.02, we fail to reject the null hypothesis. With 98% Confidence there is insufficent evidence to suggest that the mean wait time exceeds 2.75 Minutes
WE are 98% confident that the Mean wait time will fall between 2.55 minutes and 3.45 minutes. Since 2.75 minutes falls in the interval, it suports failing to reject the null hypothesis
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The first 2-part question of your project will require you to use concepts learned in a z-test. This includes means were the population standard deviation is known and proportions. As usual, fill in the values in the colored boxes and write your conclusion in the space provided.
Fill in the values from the question for "Data Entry" cells, a formula for "Formula" cells and a function (like =NORM.DIST) for "Function" cells. A. The board of a major credit card company requires that the mean wait time for customers when they call customer service is 2.75 minutes. To make sure that the mean wait time is not exceeding the requirement, an assistant manager tracks the wait times of 40 randomly selected calls. The mean wait time was calculated to be 3.01 minutes. Assuming the population standard deviation is 1.4 minutes, is there sufficient evidence that the mean wait time for customers is longer than 2.75 minutes with a 98% level of confidence? (7 points)
B. For the same problem as part A, construct an appropriate confidence interval based on the alpha level in A to support your conclusion from part A. Recall, if you rejected the null in part A, then your expected mean should not be included in the interval. If you failed to reject the null hypothesis, then the hypothesized mean should be in the interval. You should only need the appropriate critical value and margin of error in addition to values from part A. Correctly round your results to two decimal places in your conclusion sentence and be sure to state that it supports your decision to reject or fail to reject based on whether the hypothesized value falls in the interval. (3 points)
1 pt
A
Null Hypothesis
µ
=
0
Data Entry
1 pt
Alternative Hypothesis
µ
>
0
Alt Hyp (choose)
1 pt
Sample Mean (x-bar)
27.9
Data Entry
3.4
Data Entry
Sample Size (n)
11
Data Entry
Degrees of Freedom (df)
10
Formula
alpha-level
0.025
Data Entry
1 pt
t-Score
2.8288858506
Formula
1 pt
p-value
0.00894302354
Function
2 pts
1 pt
B
Critical Value
2.22813885199
Function
Margin of Error
2.28415107997
Formula
Confidence Interval
25.61584892
30.18415107997
(Lower Limit,
Upper Limit)
2 pts
Sample Standard Deviation (s)
With p=0.0089 < a= 0.025, we Reject the null hypothesis. With 97.5% confidence, there is sufficient evidence to support the Alternative hypothesis, that Cox Communcations takes longer than 25 minutes to arrive.
With 97.5% confidence, we can claim that the true arrival time falls between 25.62 minutes and 30.18 minutes. Since the hypothesized time of 25 minutes falls outside this interval this supports rejecting the null hypothesis
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This is another 2-part question. It is important to understand how onfidence intervals and hypothesis tests support one another! This test deals with t-testing, which is the test we must perform when dealing with means data and the population standard deviation is unknown.
A. Cox Communications, the primary cable provider in Omaha, NE, claims to have excellent customer service. In fact, the company advertises that a echnician will arrive approximately 25 minutes after a service call is placed. One frustrated customer believes this is not accurate, claiming it takes onger than 25 minutes for a technician to arrive. The customer puts a urvey on the Nextdoor app asking other Cox customers what their experience has been. Only 11 people responded, with a mean of 27.9 minutes and standard deviation of 3.4 minutes. Test the customer's claim with a 0.025 level of significance. (7 points)
B. For the same problem as part A, construct an appropriate confidence nterval based on the alpha level in A to support your conclusion from part A. Recall, if you rejected the null in part A, then your expected mean should not be included in the interval. If you failed to reject the null hypothesis, hen the hypothesized mean should be in the interval. You should only need he appropriate critical value and margin of error in addition to values from part A. Correctly round your results to one decimal place in your conclusion entence and be sure to state that it supports your decision to reject or fail o reject based on whether the hypothesized value falls in the interval. (3 points)
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1 pt
A
Null Hypothesis (enter hypothesized diff)
p1-p2
=
0
1 pt
Alternative Hypothesis
p1-p2
>
0
Proportion 1 x (Last Year's Data)
1500
Proportion 1 n (Last Year's Data)
2126
Proportion 1 p-hat
0.705550329
Proportion 2 x (This Year's Data)
1512
Proportion 2 n (This Year's Data)
2020
Proportion 2 p-hat
0.748514851
p-bar
0.726483357
1-(p-bar)
0.273516643
alpha-level
0.05
1 pt
z-Score
-3.102043898
1 pt
p-value
0.999039053
2 pts
1 pt
B
Point Estimate
-0.042964522
Critical Value
1.644853627
Margin of Error
0.022726769
Confidence Interval
-0.065691292
(Formulas)
Lower Limit
2 pts
Inputs 1 pt
With p= 0.999 > a = 0.05, we Fail to Reject the null hypothesis. This indicat
insufficient evidence at the 0.05 level of signicicance to say that the changes be
improved retention rates.
With a 5% level of significance, we can say that the rate has decreased between
0 does not fall in this interval, this supports failing to reject the Null h
Data Entry
Alt Hyp (choose)
Data Entry
Data Entry
Formula
Data Entry
Data Entry
Formula
Formula
Formula
Data Entry
Formula
Function
Formula
Function
Formula
-0.02023775277278
Upper Limit
tes that there is ellevue has made has n 6.6% and 2%. Since hypothesis.
Yup. Another 2-part question. This time we are dealing with 2-samples.
A. Officials at Bellevue University hope that changes they have made have improved the retention rate. Last year a sample of 2126 freshmen showed that 1500 returned as sophomores. This year 1512 of 2020 freshmen returned as sophomores. Determine if there is sufficient evidence at the 0.05 level to say that the retention rate has improved. (7 points)
B. For the same problem as part A, construct an appropriate confidence interval based on the alpha level in A to support your conclusion from part A. Recall, if you rejected the null in part A, then your expected mean should not be included in the interval. If you failed to reject the null hypothesis, then the hypothesized mean should be in the interval. You should only need the appropriate critical value and margin of error in addition to values from part A. Correctly round your percentage to one decimal place in your conclusion sentence and be sure to state that it supports your decision to reject or fail to reject based on whether the hypothesized value falls in the interval. (3 points)
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Paste your scatterplot with the regression equation and r-squared value below:
For your last question on
you. The data set in colu
speed in mph and drop d
this data, do the followin
A. Create a scatterplot o
title "Rollercoaster Spee
be sure to add both axis
B. Use the "Add chart el
and r-squared value on y
Keep in mind that you o
one line of regression. If
you will earn 0 points.
0
50
100
150
200
250
300
350
0
10
20
30
40
50
60
70
80
90
100
f(x) = 0.164066026489507 x + 42.0083816111709
R² = 0.786577490946543
Rollercoaster Speed (mph) vs. Drop Distance
Drop Distance
Speed (MPH)
n your last project, I am going to take it easy on umns A-C of the Data Set page give the name, top distance of several popular roller coasters. Using ng:
of the data (4 pts). The scatterplot should have the ed vs. Drop Distance" (1 pts). Using the Design tab, s titles (1 pts) and a trendline (2 pts).
lements" option to display both the LSRL equation your scatterplot. (2 points)
only have one set of data, so you should only have f you submit a scatterplot with two separate lines,
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