_Lab 5 Document

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University of Texas *

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474

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Statistics

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Apr 3, 2024

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5

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Assessment This section summarizes information regarding the assessment of Post-Lab 5. The worksheets for this lab should be scanned or photographed and uploaded as part of the post-lab assignment in the college Canvas course. The Post-Lab is worth 100 points, distributed as follows: - 40 pts for Canvas-based Post-Lab questions, and - 60 pts for for parts of the worksheets assessed using the rubrics that will be uploaded. Please make sure that you are familiar with each scientific ability that we are looking for, and check that your work addresses them.
- Describe how your determined equilibrium and state the equilibrium point of your meter stick and construct a diagram Procedure #1 1) Put your meter stick at the edge of the table; preferably at the 50 centimeter mark 2) Look at your meter stick to see if it is at its almost tipping point at the 50 cm mark. 3) If so, record 50 cm as your center of mass for your meter stick. 4) If not, continuously adjust the meter stick little by little until you’re about to reach the tipping point of the meter stick. 5) Record the number on the edge of the table as your center of mass. Diagram Data x m = 50.0 cm Center of mass = 50.0 cm
List procedures, draw diagrams, and create a data table and collect data for multiple trials and then compare your average value with the actual mass. You will also need to determine if your calculations are within a 95% accuracy. Procedure #2 1) Create a Data table to record your data ( include x m, m c, x c , x f r m, r c, m m ) 2) Place your meter stick on the table on its x m. 3) Choose a lab weight to be your m c. ( Tip: choose a smaller weight unlike me ) 4) Weigh your lab weight ,if it is not listed on the weight, using the scale and record the mass as m c . 5) Set your weight at a certain point on the meter stick this will be your x c 6) Drag the meter stick slowly until you reach the tipping point. 7) Record that point as your x f. 8) Repeat steps 5- 7 for the next four trials. Data Table Trial x m m c x c x f r m r c m m 1 50.0cm 500g 40cm 42.0cm 8.0 2.0 125.0g 2 50.0cm 500g 35cm 38.7cm 11.3 3.7 163.7g 3 50.0cm 500g 30cm 33.3cm 16.7 3.3 98.8g 4 50.0cm 500g 25cm 29.5cm 20.5 4.5 109.8g 5 50.0cm 500g 20cm 28.4cm 21.5 8.5 197.7g Calculation r m = |x f - x m | |42.0 - 50.0 | = 8.0 , |38.7 - 50.0 | = 11.3, |33.3 - 50.0 | = 16.7, |29.5 - 50.0 | = 20.2, |28.4 - 50.0 | = 21.5 r c = |x f - x c | |42.0 - 40.0 | = 2.0, |38.7 - 35.0 | = 3.7 , |33.3 - 30.0 | = 3.3, |29.5 - 25.0 | = 4.5, |28.4 - 20.0 | = 8.5 m m = (m c x r c ) / r m (500 x 2.0) / 8.0 = 125.0,(500 x 3.7) / 11.3 = 163.7,(500 x 3.3) / 16.7 = 98.8,(500 x 4.5) / 20.5 = 109.8, (500 x 8.5) / 21.5 = 197.7 The average m m is 139.0.
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The standard deviation is 40.989205896187. I believe that I was not accurate in part 2 of the experiment because my standard deviation was so large and it’s mostly through human error which has affected the accuracy. List procedures, draw diagrams, and create a data table and collect data for multiple trials and then compare your average value with the actual mass. You will also need to determine if your calculations are within a 95% accuracy. Procedure #3 9) Create a Data table to record your data ( include x m, m m, x u , x f r m, r u, m u ) 10) Place your meter stick on the table on its x m. 11) Pick up the block to use as your weight. 12) Weigh the block using the scale and record the mass as m m . 13) Set your weight at a certain point on the meter stick this will be your x u 14) Drag the meter stick with the block slowly until you reach the tipping point. 15) Record that point as your x f. 16) Repeat steps 5- 7 for the next four trials. Data Table Trial m m x m x u x f r m r u m u 1 96g 50.0cm 40.0cm 45.2cm 4.8 5.2 88.6 2 96g 50.0cm 35.0cm 43.0cm 7.0 8.0 84.0 3 96g 50.0cm 30.0cm 40.5cm 9.5 10.5 86.9 4 96g 50.0cm 25.0cm 38.0cm 12 13.0 88.6 5 96g 50.0cm 20.0cm 35.8cm 14.2 15.8 86.3 Calculation r m = |x f - x m | |45.2 - 50.0 | = 4.8 , |43.0 - 50.0 | = 7.0, |40.5 - 50.0 | = 9.5, |38.0 - 50.0 | = 12.0, |35.8 - 50.0 | = 14.2 r u = |x f - x u | |45.2- 40.0 | = 5.2, |43.0 - 35.0 | = 8.0 , |40.5 - 30.0 | = 10.5, |38.0 - 25.0 | = 13.0, |35.8 - 20.0 | = 15.8 m u = (m m x r m ) / r u (96 x 4.8)/5.2 = 88.6, (96 x 7.0)/8.0 = 84.0, (96 x 9.5) / 10.5 = 86.9, (96 x 12.0) /13.0 = 88.6,
(96 x 14.2) / 15.8 = 86.3, The average m u is 86.8. The standard deviation is 1.907092027145. I believe that I was accurate in part 3 of the experiment because my standard deviation was so small.