Week 4 Test

Answer A-B

Solve for b

#17

Using your z-score tables, find the area under the curve to the right of z = -1.65.   Question 2 options:   P(z>-1.65) = 0.0495   P(z>-1.65) = 0.0606   P(z>-1.65) = 0.9394   P(z>-1.65) = 0.9505

Suppose the lengths of human pregnancies are normally distributed with =266 days and o-16 days. Complete parts (a) and (b) below (a) The figure to the right represents the normal curve with u=266 days and e-16 days. The area to the right of X-300 is 0.0168. Provide two interpretations of this area Provide one interpretation of the area using the given values. Select the correct choice below and fill in the answer boxes to complete your choice (Type integers or decimals) OA. The proportion of human pregnancies that last more than OB. The proportion of human pregnancies that last less than days is days is Select the correct choice below and fill in the answer boxes to complete your choice days is Provide a second interpretation of the area using the given values (Type integers or decimals) OA. The probability that a randomly selected human pregnancy lasts less than OB. The probability that a randomly selected human pregnancy lasts more than A 4 days is

A graph that plots averages of the DV measured from different replicates (instead of the individual DV values from each replicate)

answer b please <3

6.1.11-T Question Help Find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with mean 0 and standard deviation 1. Z= -0.88 z = 1.21 The area of the shaded region is . (Round to four decimal places as needed.) ce

Using your z-score tables, find the area under the curve between z = 0.40 and z = 2.45.   Question 3 options:   P(0.40<z<2.45) = 0.3375   P(0.40<z<2.45) = 0.9929   P(0.40<z<2.45) = 2.0500   P(0.40<z<2.45) = 0.6554

Find za/2 for a=0.02. Table of normal curve areas. Click the icon to view the table of normal curve areas. Z12= (Round to two decimal places as needed.) Za/2 00 01 .02 03 04 05 06 L07 08 09 0000 0398 .0793 1179 1554 1915 0040 0438 0832 1217 1591 1950 .0080 0478 .0871 1255 0120 0517 0910 1293 1664 2019 0160 .0557 .0948 1331 1700 2054 L0199 0596 0987 1368 1736 2088 0239 0636 .0279 0675 1026 1406 1772 2123 1064 1443 1808 2157 .0319 0714 1103 1480 0359 0753 1141 1517 1879 2224 1628 1985 1844 2190 2257 2580 2881 3159 13413 2357 2673 2291 2611 2910 3186 3438 2324 2642 2939 3212 3461 2389 2704 2995 3264 3508 2422 2734 3023 3289 3531 2454 2764 3051 3315 2486 2794 2549 2852 3078 3340 3577 2517 2823 3106 3365 3599 .8 2967 3238 3485 3133 3389 3621 1.0 3554 3665 3869 4049 4207 4345 3729 13925 4099 4251 4382 3770 3643 3849 4032 4192 4332 3708 3907 4082 4236 4370 13790 3980 4147 3810 3997 4162 .4306 4429 3830 4015 4177 3749 1.1 1.2 1.3 1.4 1.5 3686 3888 4066 4222 4357 3944 4115 4265 4394 3962 4131…

Find the area under the standard normal curve to the left of z = - 2.33. Round your answer to four decimal places, if necessary. Answer © 2021 Hawkes Learning ere to search 52°F

B

II. Direction Find the area under the t- distribution from t = -2.060 to t = 2.060 when n = 26, then illustrate the t- distribution.

Suppose the lengths of human pregnancies are normally distributed with u=266 days and o= 16 days. Complete parts (a) and (b) below (a) The figure to the right represents the normal curve with μ = 266 days and o- 16 days. The area to the right of X = 300 is 0.0168. Provide two interpretations of this area Provide one interpretation of the area using the given values. Select the correct choice below and fill in the answer boxes to complete your choice. (Type integers or decimals.) A. The proportion of human pregnancies that last less than days is B. The proportion of human pregnancies that last more than 300 days is 0168 Provide a second interpretation of the area using the given values Select the correct choice below and fill in the answer boxes to complete your choice (Type integers or decimals.) OA. The probability that a randomly selected human pregnancy lasts more than OB. The probability that a randomly selected human pregnancy lasts less than days is days is A X 266 300 Q

please highlight the correct answer at the end

Score: 0 of 1 pt 12.2.12 Given below is the smoking status Number of Years by level of education for residents of Education 18 years old or older living in a certain country from a random sample of 1064 residents. Complete parts (a) and (b). Smoking Status Current Former Never <12 196 86 177 12 145 81 137 13-15 42 30 42 16 or more 34 40 54 E Click the icon to view the Chi-Square table of critical values. (a) Test whether smoking status and level of education are independent at the a = 0.01 level of significance. What are the hypotheses? O A. Ho: Smoking status and level of education are dependent. H;: Smoking status and level of education are independent. O B. Ho: The three smoking statuses are independent. H;: The three smoking statuses are dependent. C. Hg: Smoking status and level of education are independent. H;: Smoking status and level of education are dependent. Find the test statistic. xổ = (Round to three decimal places as needed.)

Suppose the lengths of human pregnancies are normally distributed with u= 266 days and a= 16 days. Complete parts (a) and (b) below. (a) The figure to the right represents the normal curve with u= 266 days and o= 16 days. The area to the left of X = 245 is 0.0947. Provide two interpretations of this area. Provide one interpretation of the area using the given values. Select the correct choice below and fill i the answer boxes to complete your choice. (Type integers or decimals.) O A. The proportion of human pregnancies that last less than 245 days is 0.0947 B. The proportion of human pregnancies that last more than days is 245 266 Provide a second interpretation of the area using the given values. Select the correct choice below and fill in the answer boxes to complete your choice. (Type integers or decimals.) A. The probability that a randomly selected human pregnancy lasts less than 245 days is 0.0947 B. The probability that a randomly selected human pregnancy lasts more than days is…

Part 2 of 2 (b) Find the area under the standard normal curve to the left of z = -1.52. The area to the left of z = -1.52 is X