Unit 1
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University of Manitoba *
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Course
2000
Subject
Statistics
Date
Feb 20, 2024
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Pages
21
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Unit 1
1. We take a simple random sample of 16 adults and ask them how long they sleep on a
typical night. The sample mean is calculated to be 7.2 hours. Suppose it is known that
the number of hours adults sleep at night follows a normal distribution with standard
deviation 1.8 hours. An 88% confidence interval for the true mean time adults sleep at
night is:
(A) (6.80, 7.60)
(B) (6.30, 8.10)
(C) (6.60, 7.80)
(D) (6.70, 7.70)
(E) (6.50, 7.90)
2. The average daily calcium intake for a sample of 10 Canadian adults is calculated to be
615 mg. Daily calcium intake is known to follow a normal distribution with standard
deviation 112 mg. An 83% confidence interval for the true mean daily calcium intake of
all Canadian adults is:
(A) (566.48, 663.52)
(B) (564.45, 665.55)
(C) (568.17, 661.83)
(D) (565.73, 664.27)
(E) (567.84, 662.16)
3. A random variable
X
follows a normal distribution with standard deviation
σ
= 8. We
take a random sample of 25 individuals from the population and we calculate a confidence
interval for
μ
to be
(36.7136, 43.2864)
. What is the confidence level of this interval?
(A) 90%
(B) 95%
(C) 96%
(D) 98%
(E) 99%
4. We select a random sample of ten oranges from trees grown in a large orchard.
The
standard deviation of weights of these ten oranges is calculated to be 19 grams. Based
on this sample, a confidence interval for the true mean weight of all oranges grown in the
orchard is calculated to be (126
.
41
,
153
.
59). What is the confidence level of this interval?
(A) 80%
(B) 90%
(C) 95%
(D) 96%
(E) 98%
5. The Manitoba Department of Agriculture would like to estimate the average yield per
acre of a new variety of corn for farms in southwestern Manitoba. It is desired that the
final estimate be within 5 bushels per acre of the true mean yield. Due to cost restraints,
a sample of no more than 65 one-acre plots of land can be obtained to conduct an
experiment. The population standard deviation is known to be 17.33 bushels per acre.
What is (approximately) the maximum confidence level that could be attained for a
confidence interval that meets the Agriculture Department’s specification?
(A) 90%
(B) 95%
(C) 96%
(D) 98%
(E) 99%
6. We would like to construct a confidence interval to estimate the true mean systolic blood
pressure of all healthy adults to within 3 mm Hg (millimetres of mercury). We have a
sample of 36 adults available for testing. Systolic blood pressures of healthy adults are
known to follow a normal distribution with standard deviation 14.04 mm Hg. What is
the maximum confidence level that can be attained for our interval?
(A) 80%
(B) 90%
(C) 95%
(D) 96%
(E) 98%
7. The sizes of farms in a U.S. state follow a normal distribution with standard deviation
30 acres. Suppose we measure the sizes of a random sample of farms and calculate a
98% confidence interval for
μ
to be (295, 305). What is the correct interpretation of this
interval?
(A) Approximately 98% of farms have a size between 295 and 305 acres.
(B) Approximately 98% of samples of 30 farms will have a mean size between 295 and
305 acres.
(C) The probability that the population mean is between 295 and 305 acres is 98%.
(D) In repeated samples of the same size, 98% of similarly constructed intervals will
contain the sample mean.
(E) In repeated samples of the same size, 98% of similarly constructed intervals will
contain the population mean.
2
8. We would like to estimate the true mean amount of coffee that is sold at a certain coffee
shop per day. It is know that the amount of coffee sold daily follows a normal distribution
with standard deviation
σ
. Which of the following combinations of confidence level and
sample size would result in the narrowest confidence interval?
(A) 90% confidence level,
n
= 5
(B) 90% confidence level,
n
= 20
(C) 95% confidence level,
n
= 10
(D) 99% confidence level,
n
= 5
(E) 99% confidence level,
n
= 20
9. We would like to estimate the true mean height of all trees in a large forest.
It is
calculated that, in order to estimate the true mean height to within 4 feet with 98%
confidence, we require a sample of 400 trees.
What sample size would be required to
estimate the true mean height to within 5 feet with 98% confidence?
(A) 256
(B) 320
(C) 500
(D) 625
(E) 750
10. Annual salaries of workers in a large union follow a normal distribution with standard
deviation $10,000. What sample size is required if we want to estimate the true mean
salary to within $2,000 with 93% confidence?
(A) 82
(B) 85
(C) 88
(D) 94
(E) 97
11. In order to estimate the true mean GPA of all students in the University of Manitoba
to within 0.10 with 96% confidence, we require a sample of 100 students. GPAs at the
University follow a normal distribution with known standard deviation
σ
. What sample
size would be required in order to estimate the mean GPA of all University of Manitoba
students to within 0.04 with 96% confidence?
(A) 40
(B) 250
(C) 375
(D) 400
(E) 625
3
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12. The durations of professional men’s tennis matches are known to follow a normal dis-
tribution. It is calculated that, in order to estimate the true mean duration to within
3 minutes with 95% confidence, a sample of 77 matches is required. What sample size
is required in order to estimate the true mean duration to within 2 minutes with 95%
confidence?
(A) 35
(B) 52
(C) 95
(D) 116
(E) 174
13. We would like to estimate the true mean amount (in $) consumers spent last year on
Christmas gifts. We record the amount spent for a simple random sample of 30 consumers
and we calculate a 95% confidence interval for
μ
to be (500, 545), i.e., the length of the
interval is 45. The standard deviation
σ
of the amount spent by consumers is known.
Suppose we had instead selected a simple random sample of 90 consumers and calculated
a 95% confidence interval for
μ
. What would be the length of this interval?
(A) 5.00
(B) 12.99
(C) 15.00
(D) 25.98
(E) 77.94
14. A statistician conducted a test of H
0
:
μ
= 100 vs. H
a
:
μ
6
= 100 for the mean
μ
of some
normally distributed population. Based on the gathered data, the statistician calculated
a sample mean of ¯
x
= 110 and concluded that H
0
could be rejected at the 5% level of
significance. Using the same data, which of the following statements
must
be true?
(I)
A test of H
0
:
μ
= 100 vs. H
a
:
μ >
100 at the 5% level of significance would also
lead to rejecting H
0
.
(II)
A test of H
0
:
μ
= 90 vs. H
a
:
μ
6
= 90 at the 5% level of significance would also
lead to rejecting H
0
.
(III)
A test of H
0
:
μ
= 100 vs. H
a
:
μ
6
= 100 at the 1% level of significance would also
lead to rejecting H
0
.
(A) I only
(B) II only
(C) I and II
(D) I and III
(E) I, II and III
4
15. A statistician conducted a test of H
0
:
μ
= 1 vs. H
a
:
μ >
1 for the mean
μ
of some
population.
Based on the gathered data, the statistician concluded that H
0
could be
rejected at the 1% level of significance.
Using the same data, which of the following
statements must be true?
(I)
A test of H
0
:
μ
= 1 vs. H
a
:
μ >
1 at the 10% level of significance would also
lead to rejecting H
0
.
(II)
A test of H
0
:
μ
= 0 vs. H
a
:
μ >
0 at the 1% level of significance would also
lead to rejecting H
0
.
(III)
A test of H
0
:
μ
= 1 vs. H
a
:
μ
6
= 1 at the 1% level of significance would also
lead to rejecting H
0
.
(A) I only
(B) I and II only
(C) I and III only
(D) II and III only
(E) I, II and III
16. We would like to conduct a hypothesis test to examine whether there is evidence that
the true mean amount spent on textbooks by a U of M student in one semester differs
from $400. A random sample of 50 students is selected and the mean amount they spent
on textbooks for one semester is calculated to be $430. Assume the population standard
deviation is known to be $165. What is the P-value for the appropriate hypothesis test?
(A) 0.1970
(B) 0.1112
(C) 0.0630
(D) 0.0985
(E) 0.1260
17. A candy manufacturer sells boxes of its candy with an advertised weight of 50 grams.
Weights of candy per box are known to follow a normal distribution with standard
deviation 2.2 grams. A random sample of five boxes has a mean weight of 51.8 grams.
We conduct a hypothesis test to determine if there is evidence that the true mean weight
of all boxes of candy differs from the advertised weight. The P-value for the appropriate
test of significance is:
(A) 0.0336
(B) 0.0427
(C) 0.0548
(D) 0.0672
(E) impossible to determine, since the level of significance is not given.
5
18. Prior to distributing a large shipment of bottled water, a beverage company would like
to determine whether there is evidence that the true mean fill volume of all bottles differs
from 600 ml, which is the amount printed on the labels. Fill volumes are known to follow
a normal distribution with standard deviation 2.0 ml. A random sample of 25 bottles is
selected. The sample has a mean of 598.8 ml and a standard deviation of 3.0 ml. What
is the P-value of the appropriate test of significance?
(A) 0.0162
(B) 0.0013
(C) 0.0456
(D) 0.0026
(E) 0.0228
19. High levels of arsenic in drinking water can cause dangerous health effects.
Drinking
water is considered safe if the mean arsenic concentration is 0.010 mg/L or lower.
A
random sample of ten specimens of water from a well has a mean arsenic concentration
of 0.011 mg/L. Arsenic concentrations of water from the well are known to follow a
normal distribution with standard deviation 0.0025 mg. A hypothesis test is conducted
at the 5% level of significance to determine whether there is evidence that the well’s
water supply is unsafe. We conclude that:
(A) there is sufficient evidence that the well’s water supply is safe.
(B) there is insufficient evidence that the well’s water supply is safe.
(C) there is proof that the well’s water supply is unsafe.
(D) there is sufficient evidence that the well’s water supply is unsafe.
(E) there is insufficient evidence that the well’s water supply is unsafe.
20. A professor believes she saw a student copying someone else’s answers in an exam. The
student is brought before a disciplinary committee, who are tasked with deciding whether
the student is guilty, and what (if any) disciplinary action should be taken.
Suppose
they use a 5% level of significance to test the hypotheses
H
0
: The student did not cheat vs. H
a
: The student did cheat
After the hearing, the committee determines a P-value of 0.10. They conclude that:
(A) the probability the student cheated is 0.10.
(B) the probability the student cheated is 0.90.
(C) there is sufficient evidence to conclude that the student cheated.
(D) there is insufficient evidence to conclude that the student cheated.
(E) there is sufficient evidence to conclude that the student did not cheat.
6
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21. The mean height of a random sample of 25 Major League Baseball (MLB) players is
calculated to be 183 cm. We conduct a hypothesis test of H
0
:
μ
= 180 vs. H
a
:
μ >
180
to determine whether the true mean height of all MLB players is greater than 180 cm.
The P-value of the test is calculated to be 0.15. What is the correct interpretation of
this P-value?
(A) If the true mean height of all MLB players was 180 cm, the probability of rejecting
the null hypothesis would be 0.15.
(B) If we took repeated samples of 25 MLB players and conducted the test in a similar
manner, 15% of all samples would have means at least as high as 180 cm.
(C) The probability that the true mean height of all MLB players is greater than 180
cm is 0.15.
(D) If the true mean height of all MLB players was 180 cm, the probability of observing
a sample mean at least as high as 183 cm would be 0.15.
(E) Given that the sample mean height is 183, the probability that the true mean height
of all MLB players is greater than 180 cm is 0.15.
22. A test of H
0
:
μ
= 100 vs. H
a
:
μ
6
= 100 is conducted for the mean
μ
of some population.
We take a sample of ten individuals and calculate a sample mean of 104. A 98% confi-
dence interval for
μ
is calculated to be (101, 107). Which of the following statements is
true
?
(A) We fail to reject H
0
at a 4% level of significance, since 100 is not contained in the
98% confidence interval.
(B) We fail to reject H
0
at a 2% level of significance, since 104 is contained within the
98% confidence interval.
(C) We reject H
0
at the 1% level of significance, since 100 is not contained within the
98% confidence interval.
(D) We fail to reject H
0
at the 4% level of significance, since 104 is contained within the
98% confidence interval.
(E) We reject H
0
at a 2% level of significance, since 100 is not contained within the 98%
confidence interval.
7
23. We would like to conduct a hypothesis test to determine whether the true mean rent
amount for all one-bedroom apartments in Winnipeg differs from $850.
We take a
random sample of 50 one-bedroom apartments and calculate the sample mean to be
$900. A 98% confidence interval for
μ
is calculated to be
(830, 970)
. The conclusion
for our test would be to:
(A) fail to reject H
0
at the 2% level of significance since the value 850 is contained in
the 98% confidence interval.
(B) fail to reject H
0
at the 1% level of significance since the value 900 is contained in
the 98% confidence interval.
(C) reject H
0
at the 1% level of significance since the value 850 is contained in the 98%
confidence interval.
(D) reject H
0
at the 2% level of significance since the value 850 is contained in the 98%
confidence interval.
(E) fail to reject H
0
at the 4% level of significance since the value 900 is contained in
the 98% confidence interval.
24. For which of the following tests would a Type II Error have more serious consequences
than a Type I Error?
(I)
You are deciding whether to go for a skate on the frozen river.
H
0
: The ice will not break.
H
a
: The ice will break.
(II)
You are deciding whether to go for a swim in the ocean.
H
0
: There are no sharks in the water.
H
a
: There are sharks in the water.
(III)
You are wearing an expensive suit and you have to walk to work. You are
deciding whether to take an umbrella with you.
H
0
: It will not rain.
H
a
: It will rain.
(A) II only
(B) I and II only
(C) I and III only
(D) II and III only
(E) I, II and III
8
25. In which of the following cases would making a Type I Error have more serious conse-
quences than making a Type II Error?
(I)
You are deciding whether to ride a roller coaster at an amusement park.
H
0
: The ride is safe.
H
a
: The ride is not safe.
(II)
The morning you are supposed to leave for a road trip to Grand Forks, North
Dakota, The Weather Channel says there is a 50% chance of a blizzard.
You are deciding whether or not to go on the trip.
H
0
: There will not be a blizzard.
H
a
: There will be a blizzard.
(III)
You are having a surprise birthday party for your 80 year-old grandma.
You are deciding whether to yell “Surprise!” when she walks in.
H
0
: Grandma will have a heart attack.
H
a
: Grandma will not have a heart attack.
(A) I only
(B) II only
(C) III only
(D) I and III only
(E) II and III only
26. We would like to conduct a hypothesis test to determine whether the true mean breaking
strength of a particular type of rope differs from 300 pounds. Breaking strengths are
known to follow a normal distribution with standard deviation 12.5 pounds.
We will
measure the strengths of a random sample of 20 pieces of rope. It is decided that the
null hypothesis will be rejected if
¯
X
≤
294
.
75 or
¯
X
≥
305
.
25. What is the significance
level of the test?
(A) 0.03
(B) 0.04
(C) 0.05
(D) 0.06
(E) 0.07
9
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27. A farmer will measure the yields of a random sample of 15 of his tomato plants and
conduct a hypothesis test to determine whether the true mean yield of all of his tomato
plants is less than 20 pounds. Yields per plant are known to follow a normal distribution
with standard deviation 4 pounds. The farmer decides to reject the null hypothesis if
¯
X
≤
18
.
3 pounds. What is the probability of making a Type II error if the true mean
yield of all of the farmer’s tomato plants is actually 17 pounds?
(A) 0.0553
(B) 0.1038
(C) 0.1469
(D) 0.1736
(E) 0.2090
28. A hypothesis test of H
0
:
μ
= 75 vs. H
a
:
μ >
75 is conducted at the 2% level of significance
for some normally distributed variable
X
. It is calculated that, using a random sample
of 25 individuals, if the true mean was in fact equal to 80, the power of the test would be
equal to 0.90.
All other things remaining the same
, which of the following would
result in a higher power?
(I)
taking a sample of 30 individuals
(II)
using a 1% level of significance
(III)
if the true mean was 85
(A) I only
(B) II only
(C) I and II only
(D) I and III only
(E) I, II and III
29. In a hypothesis test, 1
-
α
is the probability of:
(A) rejecting H
0
when H
0
is true.
(B) rejecting H
0
when H
a
is true.
(C) failing to reject H
0
when H
0
is true.
(D) failing to reject H
0
when H
a
is true.
(E) concluding that H
0
is true when H
a
is true.
10
30. The owner of a chemical fertilizer plant would like to conduct a hypothesis test at the 1%
level of significance to determine whether the true mean amount of fertilizer produced
at the plant is greater than 1000 pounds per day. He will record the amount of fertilizer
produced at the plant for a random sample of 28 days. Fertilizer production at the plant
is known to follow a normal distribution with standard deviation 189 pounds per day.
What is the power of the test if the true mean amount of fertilizer produced is actually
1100 pounds per day?
(A) 0.3192
(B) 0.4737
(C) 0.5263
(D) 0.6808
(E) 0.7760
The next
two
questions (
31
and
32
) refer to the following:
The systems department of the Texaco Oil Company runs a large number of simulation
programs on their mainframe computer.
A manufacturer of new simulation software
claims their program will run the simulation faster than the current mean of 30 minutes.
The new program will be run 20 times. A hypothesis test of H
0
:
μ
= 30 vs. H
a
:
μ <
30
is to be conducted, and it is decided that H
0
will be rejected if ¯
x
≤
28
.
3 minutes. Run
times for the new program are known to follow a normal distribution with standard
deviation 3.7 minutes.
31. The level of significance of the test is closest to:
(A) 0.01
(B) 0.02
(C) 0.03
(D) 0.04
(E) 0.05
32. What is the probability of making a Type II error if the true mean run time for the new
program is actually 27 minutes?
(A) 0.0192
(B) 0.0244
(C) 0.0384
(D) 0.0475
(E) 0.0582
33. We would like to conduct a hypothesis test at the 5% level of significance to determine
whether there is evidence that the true mean age of first-time brides in 2017 has increased
since 1997, when the true mean age was 25.4 years. We will take a random sample of
21 first-time brides.
Ages of first-time brides in 2017 are known to follow a normal
distribution with standard deviation 2.8 years. What is the power of the test if the true
mean age of first-time brides in 2017 is 27 years?
(A) 0.7881
(B) 0.8340
(C) 0.8962
(D) 0.9474
(E) 0.9738
34. Bottles of a certain brand of apple juice are supposed to contain 300 ml of juice. There
is some variation from bottle to bottle because of imprecisions in the filling machinery.
11
A consumer advocate inspector selects a random sample of 36 bottles and tests the
hypotheses H
0
:
μ
= 300 vs. H
a
:
μ <
300 at the 10% level of significance. Fill volumes
are known to follow a normal distribution with standard deviation 3 ml. What is the
power of the test if the true mean fill volume is actually 298 ml?
(A) 0.9925
(B) 0.9943
(C) 0.9957
(D) 0.9967
(E) 0.9977
The next
two
questions (
35
and
36
) refer to the following:
The weights of apples in a large orchard are known to follow a normal distribution with
a standard deviation of 12.2 grams. A random sample of 15 apples is selected from the
orchard. We would like to conduct a hypothesis test at the 5% level of significance to
determine whether the true mean weight of all apples in the orchard is greater than 150
grams.
35. What is the power of the hypothesis test if the true mean weight of all apples in the
orchard is actually 160 grams?
(A) 0.9115
(B) 0.9370
(C) 0.9500
(D) 0.9726
(E) 0.9918
36. In the previous question, all else remaining the same, which of the following would have
resulted in a higher power?
(I)
selecting a random sample of 25 apples
(II)
if the true mean weight of all apples was actually 170 grams
(III)
using a 10% level of significance
(A) I only
(B) II only
(C) III only
(D) I and II
(E) I, II and III
37. We will measure the speeds of a random sample of 40 cars driving on a highway, and
conduct a hypothesis test at the 5% level of significance to determine whether the true
mean speed of all cars driving on the highway is greater than the posted limit of 100
km/h.
The population standard deviation of speeds is known to be 17 km/h.
What
is the probability of making a Type II Error if the true mean speed of all cars on the
highway is actually 110 km/h?
(A) 0.0188
(B) 0.0274
(C) 0.0392
(D) 0.0446
(E) 0.0537
12
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38. The
Winnipeg Free Press
reported that the average size of all Manitoba farms in 2012
was 1135 acres. We take a random sample of 100 Manitoba farms in 2017 and conduct
a hypothesis test of H
0
:
μ
= 1135 vs. H
a
:
μ >
1135 at the 5% level of significance to
determine whether the true mean size of Manitoba farms has increased over the last five
years.
Suppose it is known that farm sizes in Manitoba follow a normal distribution
with standard deviation 252 acres. What is the probability of making a Type II error if
the true mean size of farms in 2017 is 1200 acres?
(A) 0.0427
(B) 0.0721
(C) 0.1093
(D) 0.1446
(E) 0.1762
39. We would like to conduct a hypothesis test for the mean
μ
of some population. We are
trying to decide whether to use a level of significance of 1%, 5% or 10%. If we know
that making a Type I error would have much more serious consequences than making a
Type II error, then we should use:
(A) a 1% level of significance, which will result in a higher power.
(B) a 1% level of significance, which will result in a lower power.
(C) a 5% level of significance, which will result in a power of 0.95.
(D) a 10% level of significance, which will result in a higher power.
(E) a 10% level of significance, which will result in a lower power.
40. We will take a random sample of 30 vehicles of a certain make and model and measure
the fuel efficiency in miles per gallon (mpg) of each of them. We will conduct a hypothesis
test at the 10% level of significance to determine whether there is evidence that the true
mean fuel efficiency of all cars of this make and model differs from 32 mpg. What is the
probability of failing to reject H
0
if the true mean is in fact 32 mpg?
(A) 0.10
(B) 0.95
(C) 0.05
(D) 0.90
(E) 0.20
13
41. We conduct a hypothesis test of H
0
:
μ
= 20 vs. H
a
:
μ
6
= 20 for the mean
μ
of some
population at the 5% level of significance. Using a sample of size 30, we determine that
H
0
should be rejected if ¯
x <
17 or ¯
x >
23. The power of the test against the alternative
H
a
:
μ
= 25 is calculated to be 0.8621.
Which of the following statements is
true
?
(A) If we had instead used a sample size of 50, the probability of a Type II error would
increase.
(B) The power of the test against the alternative H
a
:
μ
= 26 is less than 0.8621.
(C) The power of the test against the alternative H
a
:
μ
= 15 is 0.1379.
(D) If we had instead used a 1% level of significance, the probability of a Type II error
would decrease.
(E) If we had instead used a 10% level of significance, the power of the test would
increase.
42. A consumer advocate suspects the true mean weight per bag of a certain brand of potato
chips differs from 50 grams, the amount stated on the label. He will take a random sample
of 25 bags of chips and conduct a hypothesis test at the 5% level of significance to test
his suspicion. Weights per bag are known to follow a normal distribution. What is the
probability of making a Type I Error if the null hypothesis is true?
(A) 0.025
(B) 0.050
(C) 0.100
(D) impossible to determine without the value of ¯
x
(E) impossible to determine without the value of
σ
14
43. We take a random sample of 30 individuals from some population and we plan to conduct
a test of H
0
:
μ
= 10 vs. H
a
:
μ <
10 at the 5% level of significance. The probability
of making a Type II Error if the true mean is actually 9.5 is calculated to be 0.7. This
probability is much too high, as a Type II Error for this test will have more serious
consequences than a Type I Error.
What can be done to reduce the probability of a
Type II Error?
(A) Use a 1% level of significance, which will increase the power of the test.
(B) Use a 1% level of significance, which will decrease the power of the test.
(C) Use a 10% level of significance, which will increase the power of the test.
(D) Use a 10% level of significance, which will decrease the power of the test.
(E) Take a sample of size 20, which will reduce the probability of a Type II Error.
44. The Sweetstuff Sugar Factory’s 5kg sugar package production process has a mean of
5.05kg and a standard deviation of 0.0333kg. Once per hour they take a sample of 4
packages and use these to produce an ¯
x
control chart. What are the LCL, CL and UCL?
(A) 4.95, 5.00, 5.05
(B) 5.00, 5.05, 5.10
(C) 4.90, 5.00, 5.01
(D) 4.95, 5.05, 5.15
(E) none of the above.
45. Which of the following statements comparing the standard normal distribution and the
t
distributions is
false
?
(A) The density curve for
Z
is taller at the center than the density curve for
T
.
(B) The
t
distributions have more area in the tails than the standard normal distribution.
(C) In tests of significance for
μ
,
Z
should be used as the test statistic when the distri-
bution of
X
is normal, and
T
should be used in other cases.
(D) As the sample size increases, the
t
distribution approaches the standard normal
distribution.
(E) In tests of significance for
μ
,
T
should be used as the test statistic only when the
population standard deviation is unknown.
46. A simple random sample of six male patients over the age of 65 is being used in a
blood pressure study. The standard error of the mean blood pressure of these six men
15
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was calculated to be 7.8.
What is the standard deviation of these six blood pressure
measurements?
(A) 2.8
(B) 3.2
(C) 14.4
(D) 19.1
(E) 46.8
16
47. We take a random sample of 12 observations from a normally distributed population.
These 12 observations have a mean of 71.3 and standard deviation of 5.9. A confidence
interval for
μ
is calculated to be
(67.335, 75.265)
. The confidence level of this interval
is closest to:
(A) 90%
(B) 95%
(C) 96%
(D) 98%
(E) 99%
48. The Winnipeg Transit Commission claims that the average time taken by the Number
60 bus to travel from the University of Manitoba to downtown is 27 minutes. A student
who often takes this route believes that the true mean time is greater than 27 minutes.
The student records the times for a sample of five trips. These trips have a mean time of
30 minutes and a standard deviation of 4 minutes. Suppose it is known that trip times
follow a normal distribution. The P-value for the appropriate test of significance to test
the student’s suspicion is:
(A) between 0.01 and 0.02.
(B) between 0.02 and 0.025.
(C) between 0.025 and 0.05.
(D) between 0.05 and 0.10.
(E) between 0.10 and 0.15.
49. The dean of the Faculty of Science at a large university would like to conduct a hypothesis
test to determine if the true mean GPA of science students at the university is less than
3.25. A random sample of 22 science students has a mean GPA of 3.18 and a standard
deviation of 0.47. The P-value for the appropriate test of significance is:
(A) between 0.15 and 0.20.
(B) between 0.20 and 0.25.
(C) between 0.40 and 0.50.
(D) between 0.75 and 0.80.
(E) The P-value cannot be calculated, as the level of significance was not given.
17
50. The heights (in inches) of all 24 players on the Winnipeg Jets hockey team are ordered
and shown below:
69
70
70
71
72
72
73
73
73
74
74
75
75
75
75
75
75
75
75
76
77
77
77
80
We would like to determine if the true mean height of Winnipeg Jets hockey players
differs from 75 inches. Which of the following statements is
true
?
(A) We should conduct a
z
test, as it is reasonable to assume heights follow a normal
distribution.
(B) We should conduct a
t
test, as we have no idea of the form of the distribution of
heights.
(C) We should conduct a
z
test, as the sample size is fairly high, so
¯
X
will have an
approximate normal distribution.
(D) We should conduct a
t
test, as the population standard deviation is unknown.
(E) A hypothesis test is unnecessary in this situation.
51. A horticulturist wishes to estimate the true mean growth of seedlings in a large timber
plot last year. A random sample of 20 seedlings is selected and the one-year growth for
each of them is measured. The sampled seedlings have a mean growth of 6.4 cm and
a standard deviation of 1.5 cm. One-year seedling growth is known to follow a normal
distribution with standard deviation 2.0 cm. We wish to conduct a hypothesis test at the
10% level of significance to determine whether the true mean one-year seedling growth
differs from 6.0 cm. The rejection region for the test is:
(A)
|
z
|
>
1
.
645
(B)
t >
1
.
328
(C)
z >
1
.
282
(D)
|
t
|
>
1
.
729
(E)
|
z
|
>
1
.
282
18
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The next
two
questions (
52
and
53
) refer to the following:
An experimenter is concerned about radiation levels in her research laboratory. A room
is only considered safe if the mean radiation level is 400 or less. A random sample of
12 radiation measurements is taken at different locations in the laboratory.
These 12
measurements have a mean of 414 and a standard deviation of 17. Radiation levels in
the lab are known to follow a normal distribution with standard deviation 22. We would
like to conduct a hypothesis test at the 5% level of significance to determine whether
there is evidence that the laboratory is unsafe.
52. The test statistic for the appropriate test of significance is:
(A)
t
=
-
2
.
20
(B)
z
=
-
2
.
20
(C)
z
=
-
2
.
85
(D)
t
= 2
.
85
(E)
z
= 2
.
20
53. What is the correct conclusion for the test?
(A) Reject H
0
. There is sufficient evidence that the lab is safe.
(B) Fail to reject H
0
. There is insufficient evidence that the lab is unsafe.
(C) Reject H
0
. There is sufficient evidence that the lab is unsafe.
(D) Fail to reject H
0
. There is insufficient evidence that the lab is safe.
(E) Reject H
0
. There is insufficient evidence that the lab is unsafe.
54. We would like to conduct a hypothesis test at the 10% level of significance to determine
whether the true mean score of all players in a bowling league differs from 150.
The
mean and standard deviation of the scores of 12 randomly selected players are calculated
to be 162 and 17, respectively. Scores of all players in the league are known to follow a
normal distribution. Using the critical value method, the decision rule is to reject H
0
if
the value of the test statistic is:
(A) less than
-
1
.
796 or greater than 1.796.
(B) less than
-
2
.
445 or greater than 2.445.
(C) less than
-
1
.
282 or greater than 1.282.
(D) less than
-
1
.
363 or greater than 1.363.
(E) less than
-
1
.
645 or greater than 1.645.
19
55. We will measure the weekly coffee consumption of a random sample of 15 Canadians, and
we will conduct a hypothesis test at the 5% level of significance to determine whether
the population mean differs from 3.0 litres per week. Coffee consumption is known to
follow a normal distribution with unknown standard deviation
σ
. Using the critical value
approach, the decision rule is to reject H
0
if the test statistic is:
(A) less than
-
1
.
761 or greater than 1.761.
(B) greater than 1.645.
(C) less than
-
2
.
145 or greater than 2
.
145.
(D) greater than 1.761.
(E) less than
-
1
.
960 or greater than 1
.
960.
20
Answers
1. E
31. B
2. A
32. E
3. C
33. B
4. C
34. D
5. D
35. B
6. A
36. E
7. E
37. A
8. B
38. E
9. A
39. B
10. A
40. D
11. E
41. E
12. E
42. B
13. D
43. C
14. C
44. B
15. B
45. C
16. A
46. D
17. D
47. C
18. D
48. D
19. E
49. B
20. D
50. E
21. D
51. A
22. E
52. E
23. A
53. C
24. E
54. A
25. C
55. C
26. D
27. B
28. D
29. C
30. D
21
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