Chapter 8 Assignment

xlsx

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Northeast Community College *

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218

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Statistics

Date

Feb 20, 2024

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xlsx

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16

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Chapter 8 Assignment: Complete the following problems from the textbook.  All assignments will be grad credit as long as they are complete, turned in on time, and include use of Excel fun where appropriate. This includes following any prompts added to the problems in Assignments turned in late, incomplete, or without work shown will receive partia Chapter 8 Problems: 3, 9, 15, 18, 25, 27, 35, 39, and 54
ded at full nctions Excel. al credit.
a) 80 15 n = 60 MANUAL 1.9364917 1.959964 MOE = 3.7954539 Interval: EXCEL MOE = 3.7954539 Interval: 76.204546 83.795454 0.05 0.025 a) 80 15 n = 120 MANUAL 1.3693064 1.959964 MOE = 2.6837912 Interval: EXCEL MOE = 2.6837912 Interval: 77.316209 82.683791 0.05 0.025 c) a more precise interval estimate The larger sample size lowers the standard error of the mean which decreases the ma ̅ 7x = σ = σ x7 = z = ± ≤ x̄ ≤ ̅ 7x = σ = σ x7 = z = ± ≤ x̄ ≤
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76.204546 83.795454 77.316209 82.683791 argin of error and the width of the confidence interval. ≤ x̄ ≤ ≤ x̄ ≤
Smoke and Fire Cost 19100 3027 n = 17748 MANUAL 408.1606 1.959964 MOE = 18429 EXCEL MOE = 799.98007 Interval: 18300.02 17312 0.05 0.025 17622 23149 18340 23669 23006 18378 14160 21653 18060 20043 13859 22401 14970 15111 22320 21159 15628 19082 13832 20124 17819 16860 19042 16812 14610 16496 21287 17721 20229 23942 18937 21697 15098 18611 22137 19223 20527 16830 ̅ 7x = σ = σ x7 = z = ± ≤ x̄ ≤ We are 95% sure the damage caused in the case of care considerably higher than the 11389 given as the damage more damage on average t
19854 20499 22607 13561 22031 22128 23200 23221 15096 15978 20768 22036 17678 23910
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55 799.98007 Interval: 18300.02 19899.98 19899.98 ≤ x̄ ≤ eless tobacco usage is between 18300 and 19900; this is e from all home fires. Tobacco caused home fires cause than fires from all causes.
19.5 5.2 n = 65 df = 90% 0.1 0.05 MANUAL 0.644981 1.669013 MOE = 1.076481 Interval: EXCEL MOE = 1.076481 Interval: 18.42352 20.57648 95% 0.05 0.025 MANUAL 0.644981 1.99773 MOE = 1.288497 Interval: EXCEL MOE = 1.288497 Interval: 18.2115 20.7885 ̅ 7x = s = α = α/2 = σ x7 = t = ± ≤ x̄ ≤ α = α/2 = σ x7 = t = ± ≤ x̄ ≤
64 18.42352 20.57648 18.2115 20.7885 ≤ x̄ ≤ ≤ x̄ ≤
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Job Search Time (Weeks) a) 22 11.886213 21 b) 0.05 0.025 14 MANUAL 1.8793752 2.0226909 MOE = 51 EXCEL MOE = 3.8013952 16 c) Interval: 18.198605 25.801395 17 d) it would be skewed to the right 14 16 1.0061978 12 48 0 27 17 32 24 12 10 52 21 26 14 13 24 19 28 26 26 10 21 44 36 22 39 17 17 10 19 16 22 5 22 ̅ 7x = s = α = α/2 = σ x7 = t = ± ≤ x̄ ≤ This data is skewed to the right; a larger sample size might help with this. If that doesn't help, data can be transformed to help deal with skewness but I wouldn't expect BADM 321 students to know that :)
3.801395
Planning Value 6.84 a) 0.05 0.025 z= 1.959964 E= 1.5 n= 80 b) 0.1 0.05 z= 1.6448536 E= 2 n= 32 α = α/2 = α = α/2 =
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0.05 0.025 z= 1.959964 Planning Value 3750 3750 a) E= 500 n= 217 b) E= 200 n= 1351 c) E= 100 n= 5403 d) no, it would require a large sample size α = α/2 =
n = 2000 a) 0.88 b) 0.1 0.05 0.007266 1.644854 MOE = 0.011952 c) Interval: 0.868048 0.891952 d) 0.05 0.025 0.007266 1.959964 MOE = 0.014832 Interval: 0.865758 0.894242  7 𝑝 = α = α/2 = σ 7p = z = ± ≤ p 7 ≤ α = α/2 = σ 7p = z = ± ≤ p 7 ≤
p*= 0.16 1-p* 0.84 a) 0.05 0.025 z= 1.959964 E= 0.03 n= 574 b) 0.01 0.005 z= 2.5758293 E= 0.03 n= 991 α = α/2 = α = α/2 =
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n = 369 a) 0.542005 b) 0.05 0.025 0.025937 1.959964 MOE = 0.050835 c) Interval: 0.49117 0.592841  7 𝑝 = α = α/2 = σ 7p = z = ± ≤ p 7 ≤