Normal Inverse Practice Questions

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Kwantlen Polytechnic University *

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1230

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Statistics

Date

May 28, 2024

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xlsx

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Uploaded by DoctorFerret4200

1. Using NORM.S.INV, find the values of y corresponding to the following lower tail probabilities: -1.1470 0.0003 -0.3585 0.6620 0.0000 1.1031 2. Use the NORM.S.INV function to find the values of y corresponding to the following upper tail probabiliti 1.1470 -0.0003 0.3585 0.0000 3. Using NORM.INV, find the values of y corresponding to the following lower tail probabilities if μ = 32 and 29.2014 32.0006 31.1254 33.6152 32.0000 34.6915 4. Use the NORM.INV function to find the values of y corresponding to the following upper tail probabilities 8.3574 6.1180 5.1000 5. Explain why your answers in questions 1 and 2 have the same value but opposite signs. 211.9073 155.1542 a. P(Z < y) = 0.1257; y = d. P(Z < y) = 0.5001; y = b. P(Z < y) = 0.36; y = e. P(Z < y) = 0.746; y = c. P(Z < y) = 0.50; y = f. P(Z < y) = 0.865; y = a. P(Z > y) = 0.1257; y = d. P(Z > y) = 0.5001; y = b. P(Z > y) = 0.36; y = e. P(Z > y) = 0.746; y = c. P(Z > y) = 0.50; y = f. P(Z > y) = 0.865; y = a. P(X < y) = 0.1257; y = d. P(X < y) = 0.5001; y = b. P(X < y) = 0.36; y = e. P(X < y) = 0.746; y = c. P(X < y) = 0.50; y = f. P(X < y) = 0.865; y = a. P(X > y) = 0.1257; y = d. P(X > y) = 0.5001; y = b. P(X > y) = 0.36; y = e. P(X > y) = 0.746; y = c. P(X > y) = 0.50; y = f. P(X > y) = 0.865; y = 6. Suppose that you are working with a data set that is normally distributed with a mean of 200 and a stand of 47 . Use the NORM.INV function to determine the value of x from the following information: a. 60% of the values are greater than x. b. x is less than 17% of the values. c. 22% of the values are less than x d. x is greater than 55% of the values. 7. The amount of money a typical family of four spends at a McDonald’s restaurant per visit is normally distributed random variable with a mean of $16.40 and a standard deviation of $2.75. What is the amount below which only 10% of families of four spend at McDonald’s? 8. The demand for a daily newspaper at a newsstand at a busy intersection is known to be normally distributed with a mean of 150 and a standard deviation of 25. How many newspapers should the newsstand operator order to ensure that he runs short on no more than 20% of days?

a. What amount of money do the top 10% of spenders spend on clothing in a year? b. What amount of money do the bottom 10% of spenders spend on clothing in a year? c. What amount of money do the middle 50% of spenders spend on clothing in a year? from: to: from: to: 9. The lifetime of televisions produced by the Hishobi Company are normally distributed with a mean of 75 months and a standard deviation of 8 months. If the manufacturer wants to have to replace only 1% of its televsions, for how many months should its warranty be? 10. It is known that amounts of money spent on clothing in a year by students on a particular campus follow distribution with a mean of $380 and a standard deviation of $50. 11. Anticipated consumer demand in a restaurant for free range steaks next month can be modelled by a n variable with mean 1200 kilograms and standard deviation 100 kilograms. a. If the restaurant is willing to run out of steaks in 15% of the months, what is the minimum amount of kilograms of beef they should order? b. If the restaurant is willing to order too many steaks in 10% of the months, what is the maximum amount of kilograms of beef they should order? c. How many kilograms of beef should they order if they are willing to over or under order 1 months?

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