Report_Magnetic_Forces

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University of Ontario Institute of Technology *

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1020

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Physics

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Apr 3, 2024

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docx

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Physics II Laboratory Faculty of Science, Ontario Tech University Report for Experiment PhyII-03: 1Magnetic Forces on Wires Student name: ___Jason Hanna___ CRN____70204_______ Date____10/2/2023_______ Experiment 1: Force vs. Current # of Magnets: 6 Current Loop Length: 1.2cm Table 1 Current Mass Mass difference Force (A) (grams) (grams) (mN) 0 165.15 0 0 0.5 165.3 0.12 1.176 1.0 165.4 0.25 2.45 1.5 165.45 0.3 2.94 2.0 165.59 0.44 4.312 2.5 165.71 0.56 5.488 3.0 165.80 0.65 6.37 3.5 165.91 0.76 7.448 4.0 166 0.85 8.33 4.5 166.13 0.98 9.604 5.0 166.24 1.09 10.682 B = _______1.75*10 5 _T______ Insert the Force vs. Current graph here. 0 1 2 3 4 5 6 0 2 4 6 8 10 12 f(x) = 2.11 x + 0.08 Chart Title Report for Experiment PhyII-03: Magnetic Forces on Wires Page 1 of 4
Physics II Laboratory Faculty of Science, Ontario Tech University Experiment 2: Force vs. Current Loop Length # of Magnets: 6 Current I : 2.75A Mass with I = 0: 165.15 g Table 2 Length Mass Mass difference Force (cm) (grams) (grams) (mN) 1.2 165.35 0.2 1.96 2.2 165.55 0.4 3.92 3.2 165.65 0.5 4.9 4.2 165.85 0.7 6.86 6.4 166.25 1.1 10.78 8.4 166.55 1.4 13.72 B = ________6*10 4 _T_______ Insert the Force vs. Conductor Length graph here. 0 1 2 3 4 5 6 7 8 9 0 2 4 6 8 10 12 14 16 f(x) = 1.64 x + 0.01 Chart Title Report for Experiment PhyII-03: Magnetic Forces on Wires Page 2 of 4
Physics II Laboratory Faculty of Science, Ontario Tech University Experiment 3: Force vs. Magnetic Field Current I : 2.5 Current Loop Length: 4.2 cm Table 3 Magnetic Field Mass m 0 I = 0 Mass m ' I > 0 Mass difference Force (# of magnets) (grams) (grams) m ' m 0 (grams) (mN) 1 99.72 99.85 0.13 1.27 2 112.70 112.96 0.26 2.55 3 125.74 126.07 0.33 3.23 4 138.81 139.26 0.45 4.41 5 151.73 152.28 0.55 5.39 6 164.80 165.42 0.62 6.08 Insert the Force vs. Magnetic Field graph here. 0 1 2 3 4 5 6 7 0 1 2 3 4 5 6 7 f(x) = 0.96 x + 0.45 Chart Title Final Analysis Proportionality expression: _____F = ILB____ Conclusion The goal of this experiment is to find the magnetic force proportionality between current, magnetic field, and conductor length by employing magnets, current loops, and scales. Report for Experiment PhyII-03: Magnetic Forces on Wires Page 3 of 4
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Physics II Laboratory Faculty of Science, Ontario Tech University Magnets are attached to and balanced on a balance. One of the current loops is held in place by the magnets. Prior to any current going through the conducting channel, the balance is used to measure the mass of the magnets. The current is then transferred through the conducting route, producing a force that causes a change in mass and thus a change in the balance reading. The magnetic force between the conductor and the magnetic field can be calculated by dividing the difference in balance mass readings with and without the current by g which is the acceleration due to gravity. To vary the current delivered to the conductor, a power source is used. In this experimental setup, the current direction is always perpendicular to the magnetic field vector, therefore angle = 90°, which ignores the sin component of the expression. To find the mean value of the magnetic field in the first experiment, determine the slope of a Force Vs Current graph and divide it by the length of the loop. In the second experiment, to calculate the mean magnetic field, take the slope of a Force vs Conductor Length graph and divide it by the current. The B value and magnetic field value were similar in both studies, which makes logical given that we used the same magnet in both. This value was expressed in Tesla or NAm units. The magnetic force is shown to be directly proportional to the magnetic field, conductor length, and current in all three trials. This yields the equation F =ILB, where F denotes magnetic force, I denotes current, L denotes conductor length, and B denotes magnetic field. As previously stated in this experiment, the magnetic field's direction is always perpendicular to current. However, because this is not always the case, a modified version of the expression is F= ILB sin(theta), where is the angle between the magnetic field and the wire (current). Report for Experiment PhyII-03: Magnetic Forces on Wires Page 4 of 4