ph203e_s23_week7_electricpotential

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Oregon State University, Corvallis *

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203

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Physics

Date

Dec 6, 2023

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pdf

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1

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Physics 203 Ecampus Individual Quizbit | Charges and Forces Timed Quizbit | Work individually to produce a handwritten solution on paper or a tablet to ques- tions 1 of this Quizbit during the timed 30-minute Gradescope assignment Timed Quizbit . The quality of your solution and communication is far more important than the final answer! 1. Point P is some distance from a 10 kg sphere of unknown charge. The electric potential at point P is -4.5 V . The sphere and point P are very far from anything else (ignore gravity/friction/drag). (a) What is the sign of the charge on the 10 kg sphere? Explain. A 5 kg sphere with a charge of -3 C is now placed at rest at point P. (b) What is the initial potential energy of the two charge system? (c) The 10 kg sphere is fixed in place and the 5 kg sphere is allowed to move. After a long time has passed, what is the speed of the 5 kg sphere? Final Solution and Sensemaking | After you’ve completed and submitted question 1 to the timed Gradescope assignment, take more time to create a final solution set to all the questions. Use any of the course support systems (LAHHH, Teams, WormHole, … etc.) to produce the best solutions. Submit your work to the Final Solution Gradescope assignment by Sunday. Your final work will be graded on both completeness and correctness. 2. Point S is halfway between the 10 kg sphere and point P . Before the 5 kg sphere has been added to the system, what is the electric potential at point S ? 3. When you add the 5 kg sphere to the system (before either sphere is allowed to move), do you expect the electric potential at point S to increase, decrease, or stay the same? Explain. Hints: The sign on the charge is negative because or and I are Prestine however the electric potential is negative and so q is v = -11.3 = ! 10K · re ~ is e iP* IP Vis=2x, VIS =-9V P -21.5V Vis = 2 VIP The electric potential of Points is double 10K9 I . I · =2 1 4.3) Point P which is why we get-ar V- V- Because the sphere has a negative charge it would decrease the electric BEFORE 5Kg AFTER 3kg potential at Point S. g : Ar 10 S I kG S 3kg: Ar ~Y X -
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