Arjun Physics Hw

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Physics

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Oct 30, 2023

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Arjun Raj Coomba -60580954 Physics IB Hw Problem I (a) For mass A, the forces acting on A are mAgs the tension of force D and the buoyant ↓ force that displaces the liquid FA i the force diagram For A is: an FD Fovoyant :FD + Fovoyonx - FA = 0 ~ FA (weight of Al For the braker, MB, the Forces will be her weight of B, Eg = MBg, and her weight of the water in the beaker. Against it will be the normal force of the scale. FE N FE ③ FB V ~ Fo (weight of the liquid c) (weig n+of B)
(b) The system is in equilibrium : FAABC: MAS + Mgg + Meg The force excited against is in (mpc) and FE(ME9) : FD + FE = RA + B + c : MD + ME = MA + MB + MC TMA = MA+ME-MB-MC 24 using (a) We have that FD+FOvoyant : FA using the formula for Froyant: Fovoyant = 1.gVA - volume of object in displaced liquid Flooyant : FA-FD = mAg-mdg : Mag-Mdg = x g VA - > a3 90: Mag-Mdg = Ma-Md g. a4 ab (4) since, the buoyant force will rettonger aggly on D: MID = Ma-0 : MA Fr ME, force of weight of A no longer applies 1 : M(E = MB + Ma
(e) Before block A is inside, the scale reads FElg = MEg/g = 7.50kg, and the balance reads MD = 3.50kg based on the values in the question When block A is pulled out, then I looyant will no longer act to influence the scale. i. the tension measured by scale MD will equal the mass of A = mA :Scale = mb = MA using () mA = mD + ME - MB - Mc = 3.5 + 1.5 - 1 - 5 before = 11 - 6 = 5.0kg freed ↓ out weight of the scale (E) For the balance, now his would just be FE = Fz + Fc , i. MIE = MB + MC :ME = 1 + 5 = 6.0kg
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Problem 2 (a) find me velocity fallen in terms of vertical displacemently), and initial velocity (ro) velocity, streamline in vertical direction 0 = 00 + gt - vertical displacement, in terms of equations of motion: y = 80t + 1g + 2 - now, we have to substitute time it from into O after rearranging: v0 3 .u-otsc-ox-o-o-- v =i0 + gy I - us (b) According to the continuity equation, the area & f cross-section will remain constant of the stream, As radius (v) v, velocity (0) :cross-section 4 area [A] by the same rate
Amea = H2 :Ar = R Consol : velocity from (a) 152- 00 + gz) m Cont yo arb. wary [a] For ye and Y.; it and it using the equation for displacement: 12 = 35 = , 00 + 30 + g 3/00 50 y E is greater Ian y 5 by a (C) 80=1 nd 00 = 0.1 factor of ? 00 = y( = 1.ary(3 = 13/3 1 + 1] If - The only differentrator is the numerator
for so... to: yz = . and y 25. to + 1y y + 1] It is greater than by a factor of
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