Strain Rosette Data REVISED
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INTRODUCTION
One of the most important fundamentals in the engineering world is understanding how applied forces, both internally and externally, can affect a system. Failing to properly evaluate the load (with the resultant stress/strain) a material can handle can have a potentially colossal amount of damage. Entire structures like bridges and buildings could collapse under a heavier than usual load. Trucks or cars might bend
or break under an extreme load or while towing a heavy object. The purpose of this experiment was to better understand how an applied load can place stresses on a beam
along different planes. This experiment also shows how different gages and their positioning can yield different results, a critical factor in an engineer’s decision making. After taking the readings, proper computations and calculations must be performed and analyzed accordingly.
For this experiment strain is analyzed with the use of Rosette strain gage. 6 gages were placed along a beam and recorded data of a 10,000-lb. load at 45 and 60 degrees on the beam.
Using the following equations, the physical properties of the beam can be computed along with the stress and strain:
𝜎
x = [E/(1-v^2)](ɛ
x
+ vɛ
y
)
𝜎
y = [E/(1-v^2)](ɛ
y
+ vɛ
x
)
These equations relate the Modulus of Elasticity, E, and Poisson’s Ratio, v, to compute the stress of in any direction, either in the x or y planes.
This data taken for the normal and shear stresses are then compiled into data tables below and used to generate Mohr’s circle. Mohr’s circle from this data is then compared with a plot computed from theoretically calculated data. Looking at Mohr’s circle, several
data points can be taken where the combined stresses from the applied load can be seen and used for further analysis. The accuracy and validity of the experimental values
are then assessed by comparing them with theoretically computed values which can be taken from the information we have. The following equations are used in the theoretical computations:
M = PL/2
I = (1/2)bh^3 σ
x = -My/I
Τ
xy = (3V/2A)[1-y^2/c^2]
σ
MAX
= (
σ
x + σ
y
)/2
+ [((
σ
x + σ
y
)/2
)^2+(
Τ
xy
)^2]^(1/2)
σ
MIN
= (
σ
x + σ
y
)/2
- [((
σ
x + σ
y
)/2
)^2+(
Τ
xy
)^2]^(1/2)
The theoretically computed values are then compared with the experimentally calculated values to prove the precision and validity of the data. If the results fall within a reasonable percent difference, it is safe to assume that the data is indeed correct and the Rosette strain gages are a useful tool in stress and strain measurements. DATA
Table 1
Stress x 10 ^ 6
Gage
No.
Theoretical
Experimental
stress
(
experiment
)
stress
(
theoretical
)
Stress (psi)
Strain
Stress (psi)
1
σ
x
-1875
ε
x
-187
σ
x
-1911.01
σ
y
0
ε
y
65.67
σ
y
0
τ
xy
468.75
γ
xy
132.79
τ
xy
544.44
σ
max
110.66
σ
max
144.224
σ
min
-1985.66
σ
min
-2055.23
Table 2
Gage
No.
Theoretical
Experimental
stress
(
experiment
)
stress
(
theoretical
)
Stress (psi)
Strain
Stress (psi)
2
σ
x
0
ε
x
4
σ
x
0
σ
y
0
ε
y
-15
σ
y
0
τ
xy
625
γ
xy
167
τ
xy
684.70
σ
max
625
σ
max
684.70
σ
min
-625
σ
min
-684.70
Table 3
Gage
No.
Theoretical
Experimental
stress
(
experiment
)
stress
(
theoretical
)
Stress (psi)
Strain
Stress (psi)
3
σ
x
1875
ε
x
195
σ
x
1972.96
σ
y
0
ε
y
-73.67
σ
y
0
τ
xy
468.75
γ
xy
-123.55
τ
xy
-506.57
σ
max
1985.66
σ
max
2094.76
σ
min
-110.66
σ
min
-122.5
Table 4
Gage
No.
Theoretical
Experimental
stress
(
experiment
)
stress
(
theoretical
)
Stress (psi)
Strain
Stress (psi)
4
σ
x
-3750
ε
x
-449
σ
x
-3976.90
σ
y
1667
ε
y
318
σ
y
1963.02
τ
xy
468.75
γ
xy
125
τ
xy
512.50
σ
max
100.625
σ
max
σ
min
-2183.63
σ
min
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Table 5
Gage
No.
Theoretical
Experimental
stress
(
experiment
)
stress
(
theoretical
)
Stress (psi)
Strain
Stress (psi)
5
σ
x
0
ε
x
-35
σ
x
-77.79
σ
y
833
ε
y
85.67
σ
y
856.70
τ
xy
625
γ
xy
167.43
τ
xy
686.47
σ
max
1167.65
σ
max
1178.68
σ
min
-334.56
σ
min
-399.77
Table 6
Gage
No.
Theoretical
Experimental
stress
(
experiment
)
stress
(
theoretical
)
Stress (psi)
Strain
Stress (psi)
6
σ
x
3750
ε
x
352
σ
x
3778.79
σ
y
555.6
ε
y
-76
σ
y
464.20
τ
xy
-468.75
γ
xy
-136
τ
xy
-557.60
σ
max
4356.04
σ
max
4315.04
σ
min
-50.44
σ
min
-72.054
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Collage of Engineering\Al-Musayab
Department of Automobile
Engineering
Under Grad/Third stage
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2- Q4 Must be Answered
3-Assume any missing data.
4 تسلم الأسئلة بعد الامتحان مع الدفتر
Subject: Mechanical
Element Design I
Date: 2022\01\25
2022-2023
Time: Three Hours
Course 1
Attempt 1
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a. Which two graphs show materials that follow Hooke's law?
A
B
b. Which two graphs show materials that become less stiff as
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force
force
D
C. Which graph shows a material that maintains the same
stiffness throughout?
force
force
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spring constant 400N/cm.
a.
Determine the force through the spring on each wheel.
b. Calculate the compression of each spring when the car rests on the ground.
6.In a spring experiment the results were as follows:
Force (N)
Length (mpm
1
2
4
6.
7
50
58
70
74
82
9n
102
125
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PS: If you have answered this already, don’t answer it again; give chance to other experts to answer it. I want to verify if all of you will arrive in the same final answer; thats why I ask it multiple times. If you answer it again, i'll dislike all your entries/answers.
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Topics:
Statics of Rigid Bodies, Equilibrium of Rigid Bodies, Equilibrium in Two Dimensions, etc.
I will rate you with “LIKE/UPVOTE," if it is COMPLETE STEP-BY-STEP SOLUTION.
If it is INCOMPLETE SOLUTION and there are SHORTCUTS OF SOLUTION, I will rate you with “DISLIKE/DOWNVOTE.”
THANK YOU FOR YOUR HELP.
PS: If you have answered this already, don’t answer it again; give chance to other experts to answer it. I want to verify if all of you will arrive in the same final answer; thats why I ask it multiple times. If you answer it again, i'll dislike all your entries/answers.
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