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[C6130 MEM23114A Ass 1 (Student)
Assignment Part A - Quiz ] [1 of 4] [September 2019] Student knowledge assessment task
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STUDENT STUDENT - KNOWLEDGE ASSESSMENT TASK Task Number 1 of 4 Task Name Assignment Part A - Quiz National unit/s code MEM23114A National unit/s title Evaluate Thermodynamic Systems & Components National qualification code MEM60112 National qualification title Advanced Diploma of Engineering (Mechanical) RMIT Program code C6130 RMIT Course code MIET7545C Section A - Assessment Information
Duration and/or due date: As notified on CANVAS Task Instructions Summary and Purpose of Assessment This unit applies to the evaluation of thermodynamic systems and components. The evaluation may be undertaken as part of a design or system selection process or to assess system condition, sustainability or efficiency. It is suitable for people working as technicians or system designers and draftspersons, and those pursuing careers and qualifications in engineering or related disciplines. Assessment Instructions to students The student must answer the 15 questions in Section B to demonstrate an understanding of: •
Thermodynamic system and system components to be evaluated •
Stakeholders to be consulted on the evaluation •
Appropriate support, including technical and professional assistance •
WHS and regulatory requirements, risk management and organisational procedures •
Sustainability implications of thermodynamic applications What:
1.
This is an individual assessment and must be submitted online through CANVAS (unless otherwise instructed by you). 2.
You are to answer all 15 questions correctly Where: The student is to refer to “Assignments” on Canvas
How: The student is to upload their scanned copy of this question sheet, complete with their solutions & answers and submit under “Assignments” on CANVAS. Conditions for assessment Instructions to students: • This is an individual assessment and is to be completed in your own time. • You can make arrangements with the assessor at least one week prior to the assessment due date if they require special allowance or allowable adjustment to this task. • Students found in breach of assessment conditions can be charged with academic misconduct, have their results cancelled, be excluded from the program and receive other penalties. Penalties can also apply if a student’s test material is copied by others. • Plagiarism is the presentation of the work, idea or creation of another person as though it is one’s own. It is a form of cheating and is a very serious academic offence that may lead to expulsion from the University. Plagiarised material can be drawn from, and presented in, written, graphic and visual form, including electronic data, and oral
[C6130 MEM23114A Ass 1 (Student)
Assignment Part A - Quiz ] [1 of 4] [September 2019] Student knowledge assessment task
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STUDENT presentations. Plagiarism occurs when the origin of the material used is not appropriately cited. • RMIT special consideration is to enable you to maintain your academic progress despite adverse circumstances. The process for special consideration can be found at http://www1.rmit.edu.au/students/specialconsideration • Students with a disability or long
-term medical or mental health condition can apply for adjustments to their study and assessment conditions (Reasonable Adjustments and Equitable Assessment Arrangements) by registering with the Equitable Learning Services (ELS) at https://www.rmit.edu.au/students/support-and-facilities/student-
support/equitable-learning-services If student already registered with ELS and his /her study plan is approved, please remind the student to inform the teacher if this assessment task is not adjusted in line with approved study plan. • You will be assessed as satisfactory or not yet satisfactory.
• You can appeal the assessment decision according to the RMIT Assessment Appeal Processes
Additional Instructions: 1.
This is an individual assessment 2.
Performance requirement: a.
Satisfactory (S) performance –
Complete all questions correctly
b.
Not Yet Satisfactory (NYS) performance –
unable to complete all questions correctly 3.
Students need to achieve satisfactory (S) results in all assessments for this unit to be deemed Competent Instructions on submitting your knowledge assessment Upload the scanned copy of this question sheet, complete the solutions & answers and submit under “Assignments” on CANVAS. Equipment/resources students must supply: Equipment/resources to be provided by RMIT or the workplace: •
Scientific Calculator •
Pens and Pencils •
This question sheet and teaching resources provided on Canvas
[C6130 MEM23114A Ass 1 (Student)
Assignment Part A - Quiz ] [1 of 4] [September 2019] Student knowledge assessment task
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STUDENT Section B –
Student Answer Sheet Student Name Student ID Students provide your responses in the boxes below each question
Questions Satisfactory Y N Q1. Name FIVE (5) components which individually, or in combination can be used to constitute a thermodynamic system? A: 1.
Energy 2.
Entropy 3.
Pressure 4.
Temperature 5.
Volume Q2. As an engineer involved in the analysis and design of a Thermodynamic System, identify who would be appropriate stakeholders (people/companies/organisations involved) who should be consulted for the project? (List FOUR) A 1.
Client 2.
Thermal Components Company 3.
Energy/Electricity Company 4.
Engineers Organisation Q3. Which of the following choice(s), will ensure that the appropriate Technical and professional support and/or resources is/are provided in order to complete a project. (Choose correct answer): A: a.
Technical specifications b.
Statutory regulation requirements c.
On-line software d.
Manufacturer’s Helpdesk e.
all of the above
Q4. What WHS (Risk analysis), regulation and registration requirements a do you need to consider when embarking on a Thermodynamics project ? A 1.
Environmental impact 2.
Operational safety
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STUDENT 3.
Safety compliance 4.
Legislation compliance Q5. List 4 ways in which a Thermodynamic System can be made more sustainable A: 1.
Energy supplied through sustainable sources 2.
Increased insulation to prevent heat loss 3.
More efficient specific heat capacity materials 4.
Efficient design reducing energy loss Q6. What are the THREE modes of Heat transfer through media and/or space? A: 1.
Convection 2.
Conduction 3.
Radiation Q7. True or False (circle correct answer): Conduction is the transfer of heat that occurs only in fluids as a result of fluid mixing where there is an appreciable displacement of the molecules. A: a. True b. False Q8. True or False (circle correct answer): Radiation is a mode of heat transfer which requires a medium, such as air in order to transmit heat. A: a. True b. False Q9. True or False (circle correct answer): A car “Radiator” uses Conduction, Convection & Radiation to transfer heat and cool the engine. A:
[C6130 MEM23114A Ass 1 (Student)
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STUDENT a. True b. False Q10. True or False (circle correct answer): “Forced Convection” transfers heat at a slower rate than “Free (or Natural) Convection”.
A: a. True b. False Q11. An open cylindrical vessel (both ends) with a diameter of 500 mm and length of 1.5 m is filled with hot liquid at a temperature of 70°C. The outside temperature is 20°C. The overall heat transfer coefficient is 25
2
/
W
m K
. Calculate the surface area of the vessel and thus the heat flow rate from the hot liquid to the surroundings. (Show calculations below & circle the correct answer): A: A = 2*pi*r*h A = 2*pi*(0.5m/2)*1.5 A = 2.356 m^2 Q = U*A*Delta T Q = U*A*(T2-T1) Q = 25*2.356*(70-20) Q = 2945 w Q = 2.945 Kw a.
2.356 m
2
; 2.945 kW b.
5.456 m
2
; 3.964 kW c.
1.387 m
2
; 1.845 kW d.
0.3562 m
2
; 0.725 kW Q12.
The liquid in the cylindrical vessel in the previous problem
has a R.D. of 0.85. and a Specific Heat Capacity (C) of 3.8
/
kJ
kgK
. Calculate: a.
the Volume of the cylinder, b.
its Mass c.
the Heat loss when the liquid cools from 70°C to 69°C (i.e. by 1°C) d.
the time taken for the liquid to cool by 1°C
[C6130 MEM23114A Ass 1 (Student)
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STUDENT (Show calculations below & circle the correct answer)
: A: V = pi*r^2*h V = pi*0.25^2*1.5 V = 0.2945 m^3 m = (RD*1000)*V m = (0.85*1000)*0.2945 m = 250.346 kg Q = m*C*(T2-T1) Q = 250.346*3.8*(70-69) Q = 951.314 kJ t = Q/Q t = 951.314/2.945*60 t = 5.38 minutes a.
0.7945 m
3
; 850.356 kg; 2.51 MJ; 40.58 minutes b.
0.4235 m
3
; 500.576 kg; 1.562 MJ; 20.35 minutes c.
0.1835 m
3
; 150.346 kg; 652 kJ; 3.56 minutes d.
0.2945 m
3
; 250.346 kg; 951.31 kJ; 5.38 minutes Q13.
A brick veneer
wall consists of an outer
Face Brick wall 110mm thick (k
A
= 1.33 W/mK), Fibreglass insulation 80mm thick (k
B
= 0.037 W/mK), and an inner
Plasterboard wall 12mm thick (k
C
= 0.4 W/mK). Calculate the Conduction Heat transfer co-efficient for each material (U
A
, U
B & U
C
) and hence the overall Heat transfer co-
efficient (U) in conduction for the three materials assembled together in SERIES. (Show calculations below & circle the correct answer)
: A: Ua = Brick, Ub = Fibreglass, Uc = Plasterboard Ua = (1.33/110)*1000 Ua = 12.091 W/m^2k Ub = (0.037/80)*1000 Ub = 0.4625 W/m^2k Uc = (0.4/12)*1000 Uc = 33.334 W/m^2k
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[C6130 MEM23114A Ass 1 (Student)
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STUDENT 1/U = 1/Ua + 1/Ub + 1/Uc 1/U = 1/12.091 + 1/0.4625 + 1/33.334 1/U = 2.27486 U = 1/2.7486 U = 0.440 W/m^2k
a.
12.091 W/m
2
K; 0.463 W/m
2
K; 33.33 W/m
2
K; 0.440W/m
2
K b.
10.095 W/m
2
K; 0.673 W/m
2
K; 41.33 W/m
2
K; 0.750W/m
2
K c.
22.083 W/m
2
K; 0.256 W/m
2
K; 28.94 W/m
2
K; 0.540W/m
2
K d.
38.369 W/m
2
K; 0.363 W/m
2
K; 50.33 W/m
2
K; 0.830W/m
2
K Q14
. A motorcycle cylinder has 12 cooling fins (each 200 mm outside diameter and 100 mm inside diameter). The average fin temperature is 600°C and the atmospheric temperature is 20°C. Calculate the total surface area of heat transfer and hence the rate of heat dissipation from the fins by convection if the Convection Heat transfer co-efficient is 75 2
/
W
m K
(forced convection):
(Show calculations below & circle the correct answer)
: A: A = 2*12*pi/4*(0.2^2-0.1^2) A = 0.5655 m^2 Q = U*T*(T2-T1) Q = 75*0.5655*(600-20) Q = 24598.67 W Q = 24.60 kW a.
0.6345 m
2
; 35.70 kW b.
0.5655 m
2
; 24.60 kW c.
0.7486 m
2
; 58.70 kW d.
0.3655 m
2
; 18.60 kW Q15
. A Stainless-Steel component of total surface area 3.5 x 10
-3
m
2
is taken out of a furnace initially at 550°C and allowed to cool. The surrounding temperature is 25°C. Calculate: (i) the heat transfer rate due to Radiation, given that the emissivity of Stainless Steel (
ϵ
) is 0.51 (Stefan- Boltzmann constant is 56.7 x 10
-9
W/m
2
K
4
) (ii) the heat transfer rate due to Convection given that the convection heat transfer co-efficient (h
C
) is 18 W/m
2
K (iii) the total heat transfer due to combined Radiation & Convection
[C6130 MEM23114A Ass 1 (Student)
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STUDENT (Show calculations below & circle the correct answer) A: h = Sigma*e*A*T^4 h = 56.7*10^-9*0.51*0.0035*(550+273.15) h = 46.46 W Q = h*A*(T2-T1) Q = 18*0.0035*(550-25) Q = 33.075 W Total Heat = 46.46 + 33.075 = 79.535 W Rounding error, therefore answer is option a:
a.
45.63 W; 33.08 W; 78.71 W b.
25.64 W; 14.65 W; 40.29 W c.
12.09 W; 45.21 W; 57.30 W d.
18.03 W; 25.27 W; 43.30 W
[C6130 MEM23114A Ass 1 (Student)
Assignment Part A - Quiz ] [1 of 4] [September 2019] Student knowledge assessment task
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STUDENT Section C –
Feedback to Student Criteria for Assessment Satisfactory Comments Y N Q1
Q2
Q3
Q4
Q5
Q6
Q7
Q8
Q9
Q10
Q11 Q12 Q13 Q14 Q15 Overall (S/NYS)
Has the student successfully completed the task?
Yes No Feedback to student:
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- answer with explanationsarrow_forwardChrome File Edit View History Bookmarks People Tab Window Help McGraw-Hill Campus - ALEKS Science - CHM1045 GEN CHEM 1 BLENDED 669113 A bconline.broward.edu/d21/le/content/466883/fullscreen/12868783/View McGraw-Hill Campus - ALEKS Science O GASES Interconverting pressure and force A chemistry graduate student is designing a pressure vessel for an experiment. The vessel will contain gases at pressures up to 470.0 MPa. The student's design calls for an observation port on the side of the vessel (see diagram below). The bolts that hold the cover of this port onto the vessel can safely withstand a force of 2.80 MN. pressure vessel bolts side View port Calculate the maximum safe diameter w of the port. Round your answer to the nearest 0.1 cm. O cm Explanation Check O2021 McGraw-Hill Education. All Rights Reserved. Terms of Use FEBarrow_forwardI need the answer as soon as possiblearrow_forward
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