LAB 4 bottle jack

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School

Centennial College *

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Course

226

Subject

Mechanical Engineering

Date

Oct 30, 2023

Type

pdf

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Uploaded by MagistrateElectronOctopus11

Course Name: Robo 226 Section: 002 Lab No.: 4 Lab report must be handed in at the beginning of your next lab class. Any late submission will be deducted 10% each business day. Student Name: Kathrotiya Parin (Last name) (First Name) Student No. _ 301305308 Date: 2023-01-26___ Instructor: Prof. Pavel Konstantinov Instructor’s Signature: Abstract: The primary purpose of this experiment is to understand the construction and operation of Hydraulic Bottle Jack and to do the necessary calculations for calculating the maximum lifting load using hand force of 50 Lbs with and without the mechanical lever.

Circuit Schematic: Observations: . The maximum lift of the jack in Ibs Fmax =26455.5 lbs . The system pressure required to produce the maximum lift P=Fmax = 4 x 26455.5 =12304.9 psi Aliftcyl 3.14x1.655x 1.655 . The bore of the lift cylinder d1 =1.655 in . The stroke of the lift cylinder SL = 8.304 in . The volume of the lift cylinder V1 V1 =n/4 * d12 * SL=0.785 x (1.655)* x 8.304 = 17.86 in’ . The bore of the pump cylinder d2 = 0.464 in . The stroke of the pump cylinder SP = 2.375 in

8. The volume of the pump cylinder V2 V2 =n/4 * 422 * Sp = 0.785 x (0.464)* x 2.375 = 0.40 in® 9. The arm distance from the pivot to the pumping piston (IP) =1 in 10. The hydraulic amplification factor AH AH=Areg (liftingcyl) =m/4 * d1% =d12 = (1.655)2 = 12.72 AH Areq (pumping cyl) a4 *d22 d22 (0.464) 11. The mechanical amplification factor AM AM =7.044 =7.044 AM 1 12. The number of strokes to achieve the maximum lift stroke. number of strokes = volume of the lift cylinder V1 =17.86 =44.65 = 45 volume of the pump cylinder V2 0.40 13. Calculate the maximum lifting load [Ibs.] using hand force (50 Lbs) with and without the mechanical lever. With mech lever == Amp” total = AH * AM =12.72 * 7.044 = 89.6 FO =FI * Amp"total = 50 x 89.6 = 4480 lbs Without mech lever => Amp“total = AH * AM =12.72 * 1 =12.72 FO =FI * Amp"total = 50 x 12.72 = 636 lbs 14. Q&A: 1. What device limits the cylinder extension? The frictional body near the piston body limits the cylinder extension. . What device allows for the cylinder retraction? The retracting of the cylinder based on the lowering valve. . Where is the reservoir? Reservoir is located in-between outer surface of piston and inner surface of piston cylinder. It is used to store fluid. . What methods are used for cylinder and piston sealing? Visor 1s used in bottle jack to seal the cylinders and pistons.

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5. Does the system have a relief valve? Explain A relief valve is included in the bottle jack. Retracting the lifting cylinder requires the usage of the relief valve. Therefore, all of the lifting cylinder's fluid flows to thereservoir while the relief valve is in the passing condition.