MET330_Unit 2 Review Assignment 2.2_

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Feb 20, 2024

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MET330 Applied Fluid Mechanics Instructor: Francie Baker Week 2 Review Assignment - 1 I pledge to support the Honor System of ECPI. I will refrain from any form of academic dishonesty or deception, such as cheating or plagiarism. I am aware that as a member of the academic community, it is my responsibility to turn in all suspected violators of the honor code. I understand that any failure on my part to support the Honor System will be turned over to a Judicial Review Board for determination. I will report to the Judicial Review Board hearing if summoned. Review Assignment Problems NOTE: Handwritten work is not acceptable. All work must be typed and submitted on a Word Document. a. Identify and list all variables from the problem. Page 1
b. W rite the equation(s) you will use that are found in the textbook . Do not use any other equations. c. S ubstitute your variables into the equation. YOU MUST INCLUDE UNITS IN ALL PLACES OF YOUR EQUATIONS. ( m 2 , N m 3 , m s 2 ,kg, psi ,etc ) d. You must show all of your work, even “simple” calculations . During your calculations, please use 3 decimal places or 3 significant decimal places. This does not apply to financial cost calculations. e. Clearly identify your answer with correct units . CORRECT METHOD: p = γ liquid g = 2000 N m 2 9.81 m s 2 = 203.874 kg m 3 p = γ liquid g = 2000 N m 3 9.81 m s 2 = 203.874 kg m 3 INCORRECT METHOD: p2 = (W * a)/g + p1 = a^2 - Ap – μ = 0 6.30. Oil for a hydraulic system (sg = 0.90) is flowing at 2.35 × 10−3 m3/s. Calculate the weight flow rate and mass flow rate. Page 2
Known values: Governing equations: Calculations: 6.39. When 2000 L/min of water flows through a circular section with an inside diameter of 300mm that later reduces to a 150mm diameter, calculate the average velocity of flow in each section. Known values: Volume flow rate Q = 2000 L min Diameter of first pipe D 1 = 300 mm = 0.3 m Diameter of second pipe D 2 = 150 mm = 0.15 Governing equations: Page 3
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Calculations: Convert Q Calculate the cross section area of the pipes A 1 = π D 1 2 4 6.53. From the list of standard hydraulic steel tubing in Appendix G.2, select the smallest size that would carry 2.80 L/min of oil with a maximum velocity of 0.30 m/s. Known values: Governing equations: Calculations: Page 4
Figure for 6.61 6.61. Water at 10 C is flowing from point A to point B through the fabricated section shown at the rate of 0.37 m 3 /s. If the pressure at A is 66.2 kPa, calculate the pressure at B. Known values: Governing equations: Page 5
Calculations: 6.88. What depth of fluid above the outlet nozzle is required to deliver 200 gal/min of water from the tank shown? The nozzle has a 3-in diameter. Known values: Governing equations: Page 6 Figure for 6.88
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Calculations: 7.4. A long DN 150 Schedule 40 steel pipe discharges 0.085 m3/s of water from a reservoir into the atmosphere as shown. Calculate the energy loss in the pipe. Known values: Flow rate Q = 0.085 m 3 s Height of fluid h = 10 m Governing equations: Page 7 Figure for 7.4
Calculations: 7.11. A submersible deep-well pump delivers 745 gal/h of water through a 1-in Schedule 40 pipe when operating in the system shown. An energy loss of 10.5 lb-ft/lb occurs in the piping system. (a) Calculate the power delivered by the pump to the water. (b) If the pump draws 1 hp, calculate its efficiency. Known values: Governing equations: Page 8 Figure for 7.11
Calculations: Page 9
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7.23. Calculate the power delivered to the hydraulic motor shown if the pressure at A is 6.8 MPa and the pressure at B is 3.4 MPa. The motor inlet is a steel hydraulic tube with 25mm OD × 1.50mm wall and the outlet is a tube with 50mm OD × 2.00mm wall. The fluid is oil (sg = 0.90) and the velocity of flow is 1.50 m/s at point B. Known values: Governing equations: Calculations: Page 10 Figure for 7.23
7.25. Calculate the power delivered by the oil to the fluid motor shown if the volume flow rate is 0.25 m 3 /s. There is an energy loss of 1.40 N∙m/N in the piping system. If the motor has an efficiency of 75 percent, calculate the power output. Known values: Governing equations: Calculations: Page 11 Figure for 7.25 .25