HW 5B - HW 5E Solutions (1)

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Apr 3, 2024

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HW5B (1): Name ______________________________ Class Number _________________ As in the class notes, a survey is conducted and tabulated below. Blood Typ e Total Ethnic Group O A B AB G1 225 250 200 50 725 G2 800 75 100 25 1000 G3 150 350 125 60 685 Total 1175 675 425 135 2410 A person from this survey is chosen at random. Answer the questions below. Do not reduce the fractions!! 1. P(G1) 2. P(Type A Blood) 3. P(Type B Blood G3) 4. P(G1 Type AB Blood) 5. P(Type A or Type O Blood) 6. P(The person is from group G2 and has Type AB Blood) 7. P(The person is not from group G2) 8. P(G1 G2)
HW5C (1): Name ______________________________ Class Number _________________ As in the class notes, a survey is conducted and tabulated below. Blood Typ e Total Ethnic Group O A B AB G1 225 250 200 50 725 G2 800 75 100 25 1000 G3 150 350 125 60 685 Total 1175 675 425 135 2410 A person from this survey is chosen at random. Answer the questions below. Do not reduce the fractions!! Since these are conditional probabilities, the denominators will not be 2410. Recall that when answering conditional probability questions we have 1. P(G1 | Type O Blood) 2. P(Type O Blood | G1) 3. P(Not Type AB Blood | G3) 4. P[(G1 G3) | Type B Blood] 5. P(G2 | Type A Blood)
6. P(Type A Blood | Type B Blood) HW5C (2): Name ______________________________ Class Number _________________ Data is collected on 1277 individuals from a large university that attended a clinic. Their person type and injury type are noted and tabulated below. (Same as HW3B) Injury Type Total Person Type Minor Fracture Severe Fractur e Minor Joint Severe Joint Male Athlete 123 29 225 46 423 Male Non-Athlete 131 16 238 18 403 Female Athlete 98 13 67 19 197 Female Non-Athlete 86 8 138 22 254 Total 438 66 668 105 1277 A person from this survey is chosen at random. Answer the questions below. Do not reduce the fractions!! a) P(Minor Fracture | Female Athlete) b) P(Female Athlete | Minor Fracture) c) P(Severe Joint | Male Non-Athlete) d) P(Male Athlete | Severe Fracture) e) P(Male | Minor Joint) f) P(Severe Joint | Female) g) P(Female | Severe Injury)
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h) P(Fracture | Male) The answers are left like this for instructional purposes. Be sure to actually add them for credit on a quiz or exam!! i) One of the male patients is awaiting a checkup. What is the probability that this patient has a fracture? Same as h. HW5C (3): Name ______________________________ Class Number _________________ 1. Data is gathered from a university graduate program. Data is collected from each person applying to the program. Of the 400 male applicants, 100 were accepted. Of the 400 female applicants 60 were accepted. Not accepted Accepted Total Male 300 100 400 Female 340 60 400 Total a) Determine P(Accepted | Male) b) Determine P(Accepted | Female) c) Comparing the answers in part a and b, do things seem a bit unfair at the university? YES 2. Data is gathered from a university graduate program in the School of Science. Of the 300 male applicants, 92 were accepted. Of the 100 female applicants 35 were accepted. Not accepted Accepted Total Male 208 92 300 Female 65 35 100 Total a) Determine P(Accepted | Male) b) Determine P(Accepted | Female) I am putting in decimal form for easy comparison. c) Comparing the answers in parts a and b, do things seem a bit unfair in the School of Science? NO 3. Data is gathered from a university graduate program in the School of Liberal Arts. Of the 100 male applicants, 8 were accepted. Of the 300 female applicants 25 were accepted. Not accepted Accepted Total Male 92 8 100 Female 275 25 300 Total a) Determine P(Accepted | Male) b) Determine P(Accepted | Female)
c) Comparing the answers in part a and b, do things seem a bit unfair in the Liberal Arts School? NO Note that if you “add” Table 2 and Table 3 together you get Table 1. It is interesting that the female probability is higher in each of the schools, but lower in the university as a whole. Simpson’s Paradox! HW5D (1): Name ______________________________ Class Number _________________ 1. Suppose that it is known that a certain disease occurs in 1% of the population. Suppose also that we have a certain medical test to determine if person has this disease. The test produces a positive reading on 99.4% of those infected with the disease. Suppose that this test gives a positive result in healthy patients 2% of the time. Assume we have 100,000 random individuals that follow the above information perfectly. a) Fill in the table. Has Disease Does Not Have Disease Total Test Positive 994 1980 2974 Test Negative 6 97020 97026 Total 1000 99000 100000 b) Determine c) Determine 0.00006184 2. Suppose that it is known that a certain disease occurs in 4% of the population. Suppose also that we have a certain medical test to determine if person has this disease. The test produces a positive reading on 99.4% of those infected with the disease. Suppose that this test gives a positive result in healthy patients 2% of the time. Assume we have 100,000 random individuals that follow the above information perfectly. a) Fill in the table. Has Disease Does Not Have Disease Total Test Positive 3976 1920 5896 Test Negative 24 94080 94104 Total 4000 96000 100000 b) Determine
0.67435550 c) Determine 0.00025504
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