Math 240 Final_SECOND ATTEMPT
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School
Ashworth College *
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Course
MA240
Subject
Mathematics
Date
Apr 3, 2024
Type
docx
Pages
10
Uploaded by remajors75
2
nd
Attempt – Final Grade 100%
[08] Module 8 Final Exam - Results
Attempt 2 of 2
Written Feb 23, 2024 1:22 PM - Feb 23, 2024 2:18 PM
ttempt Score
100 / 100 - 100
%
erall Grade (Highest Attempt)
100 / 100 - 100
%
uestion 1
5 / 5 points
Solve the equation using the quadratic formula: x
2 + 3
x
– 8 = 0.
Question options:
a) b) c) d) stio
5 / 5
poin
Solve the equation 2
x
2
+ 6
x
– 20 = 0.
Question options:
a) x
= 5, x
= 2
b) x
= –5, x
= 2
c) x
= 5, x
= –2
d) x
= –5, x
= –2
stio
5 / 5
poin
Solve. Give exact solutions.
x
2
+ 10
x
+ 25 = 14
Question options:
x
= 5 + , x
= 5 - x
= -5 + , x
= -5 - x
= , x
= x = 9
stion 5 / 5 points
The height of a triangle is 6 inches less than the length of the base. The area of the triangle is 56 in
2
. Find the base and height of the triangle. (Use .)
Question options:
a) h
= 7 in, b
= 13 in
b) h
= 7 in, b
= 16 in
c) h
= 8 in, b
= 14 in
d) h
= 9 in, b
= 15 in
stio
5 / 5
poin
Select the graph of f
(
x
) = –6(
x
– 8)
2
+ 5.
Question options:
a) b) c) d) stio
5 / 5
poin
An object is launched from the top of a building. Its height (in feet) x
seconds after being launched is given by f
(
x
) = –16
x
2
– 48
x
+ 160. How long does it take the object to reach the ground?
Question options:
a) 2 seconds
b) 3 seconds
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c) 5 seconds
d) 4 seconds
stio
5 / 5
poin
Without graphing, find the coordinates of the vertex of the function.
f(x) = (x + 8)
2
- 3
Question options:
(-8, -3)
(8, -3)
(-3, 8)
(8, 8)
stion 5 / 5 points
Determine the nature of the solutions of the equation.
5
x
2
- 5
x
- 7 = 0
Question options:
One real
Two nonreal
Two real
stion 5 / 5 points
Identify the quadratic equation with solutions x
= 9 and x
= –2.
Question options:
a) x
2
– 11
x
– 18 = 0
b) x
2
– 11
x
+ 18 = 0
c) x
2
+ 7
x
– 18 = 0
d) x
2
– 7
x
– 18 = 0
stion 5 / 5
poin
Find the x
-intercepts of the function f
(
x
) = x
2
– 7
x
+ 10.
Question options:
a) (2, 0) and (5, 0)
b) (–2, 0) and (5, 0)
c) (–2, 0) and (–5, 0)
d) (2, 0) and (–5, 0)
stion 5 / 5
poin
Solve the problem. Give the answer to the nearest tenth.
A ball is thrown downward from a window in a tall building. Its position at time t
in seconds is s
= 16
t
2
+ 32
t
, where s
is in feet. How long (to the nearest tenth) will it take the ball to fall 204 feet?
Question options:
a) 2.5 sec
b) 2.7 sec
c) 3.6 sec
d) 7.3 sec
stion 5 / 5
poin
Select the graph of f
(
x
) = x
2 + 4
x
– 5.
Question options:
a) b) c) d)
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stion 5 / 5
poin
Find the solutions of x
2
– 4
x
– 21 = 0.
Question options:
a) x
= 3, x
= 7
b) x
= 3, x
= –7
c) x
= –3, x
= 7
d) x
= –3, x
= –7
stion 5 / 5
poin
Find the vertex.
f(x) = 3x
2
- 12x + 15
Question options:
(2, 3)
(3, 2)
(-3, -2)
(-2, -3)
stion 5 / 5 points
Find the line of symmetry.
f(x) = x
2
- 20x + 100
Question options:
x = -10
x = 10
x = 6
x = -6
stion 5 / 5 points
Find the line of symmetry.
f(x) = -2x
2
+ 12x - 20
Question options:
x = -2
x = 2
x = 3
x = -3
stion 5 / 5 points
Solve the equation by completing the square: x
2 + 6
x
= 3.
Question options:
a) b) c) x
= –1, x
= –5
d) stion 5 / 5
poin
Solve. Round results to the nearest thousandth.
8x
2
+ 7x - 13 = 0
Question options:
x
= 0.901, x
= -0.026
x
= 0.026, x
= -0.901
x
= 0.910, x
= -1.785
x
= 1.785, x
= -0.910
stion 5 / 5 points
Without graphing, find the vertex.
f(x) = -(x + 4)
2
- 7
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Question options:
(4, 7)
(-4, -7)
(-4, 7)
(4, -7)
stion 5 / 5 points
Find the solutions of x
2
– 2
x
+ 9 = 0.
Question options:
a) b) c) d) Done