Determinants_ Properties and Applications_ Attempt review _ eClass

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3/27/24, 1:25 AM Determinants: Properties and Applications: Attempt review | eClass https://eclass.srv.ualberta.ca/mod/quiz/review.php?attempt=15149458&cmid=7601901 1/22 Started on Sunday, 17 March 2024, 12:58 AM State Finished Completed on Monday, 18 March 2024, 5:57 PM Time taken 1 day 16 hours Grade 101.00 out of 101.00 ( 100 %)
3/27/24, 1:25 AM Determinants: Properties and Applications: Attempt review | eClass https://eclass.srv.ualberta.ca/mod/quiz/review.php?attempt=15149458&cmid=7601901 2/22 Question 1 Correct Mark 5.00 out of 5.00 Properties of the Determinant Many of the properties below are discussed in the video Determinants: Properties and Applications 1 . You should know these properties. Many of these have a simple explanation, but for others the proof is more complicated, so most of these will be skipped. The video provides a partial proof of property (c) below. Theorem: Let be an matrix. (a) For any scalar , (b) For any matrix , (c) is invertible if and only if 0 . Furthermore, if is invertible, then (d) For the transpose of , we have (e) If contains a row or column of zeros, or if contains a row (resp. column) which is a scalar multiple of another row (resp.column) then 0 (f) If and are matrices such that , , and are identical except that the row (resp. column) of is the sum of the rows (resp. columns) of and , that is, then Proof: We will prove . Assume: is invertible, so that . ≠ 0
3/27/24, 1:25 AM Determinants: Properties and Applications: Attempt review | eClass https://eclass.srv.ualberta.ca/mod/quiz/review.php?attempt=15149458&cmid=7601901 3/22 by Property since . Note: The proof of Property (d) uses the Laplace Expansion Theorem. Note: We can generalize Property (b) to the product of an arbitrary number of matrices. If are matrices, then (b) ≠ 0 Correct Marks for this submission: 5.00/5.00.
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3/27/24, 1:25 AM Determinants: Properties and Applications: Attempt review | eClass https://eclass.srv.ualberta.ca/mod/quiz/review.php?attempt=15149458&cmid=7601901 4/22 Question 2 Correct Mark 7.00 out of 7.00 Properties of the Determinant: Examples Example: Let . By Property , . Let's compute directly to get a sense of why this property holds: 2 4 8 Example: Use Property (c) to determine whether the following matrix is invertible: Since -9 , the matrix invertible. (a) ≠ 0 is Correct Marks for this submission: 7.00/7.00.
3/27/24, 1:25 AM Determinants: Properties and Applications: Attempt review | eClass https://eclass.srv.ualberta.ca/mod/quiz/review.php?attempt=15149458&cmid=7601901 5/22 Question 3 Correct Mark 8.00 out of 8.00 Example: Let . Since column of is scalar multiple of column 1, we know by Property that 0 . Indeed, 0 (by cofactor expansion along column 3) Recall Property (f): If , , and are matrices which are identical except that then Example: Let . Note: Thus by Property 0 24 (see example directly above) 24 . 3 (e) (f) Correct
3/27/24, 1:25 AM Determinants: Properties and Applications: Attempt review | eClass https://eclass.srv.ualberta.ca/mod/quiz/review.php?attempt=15149458&cmid=7601901 6/22 Question 4 Correct Mark 11.00 out of 11.00 Marks for this submission: 8.00/8.00. Example: Assume , , and are matrices such that , , and . Evaluate the following determinants: (Enter as a/b, where applicable.) 1. -6 2. 81 3. 4 4. -128 5. 1/3 6. 3/4 7. 1/12 An example similar to no.8 below is provided in the video Determinants: Properties and Applications 1 starting at 12:20. 8. by Property by Property by Properties 24 (a) (b) (b), (c), and (d) Correct Marks for this submission: 11.00/11.00.
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3/27/24, 1:25 AM Determinants: Properties and Applications: Attempt review | eClass https://eclass.srv.ualberta.ca/mod/quiz/review.php?attempt=15149458&cmid=7601901 7/22 Question 5 Correct Mark 8.00 out of 8.00 Example: Is , for all matrices and ? Correct answer, well done. Marks for this submission: 1.00/1.00. Counterexample: Take and , where is the identity matrix. Thus 0 0 0 0 Correct answer, well done. Marks for this submission: 1.00/1.00. Then 0 ,but 1 1 2 Correct answer, well done. Marks for this submission: 1.00/1.00. Correct answer, well done. Marks for this submission: 1.00/1.00. Correct answer, well done. Marks for this submission: 1.00/1.00. Correct answer, well done. Marks for this submission: 1.00/1.00. Thus in this case, Correct answer, well done. Marks for this submission: 1.00/1.00. and hence in general. Correct answer, well done. Marks for this submission: 1.00/1.00. No A correct answer is: "No" A correct answer is . A correct answer is , which can be typed in as follows: 0 A correct answer is , which can be typed in as follows: 1 A correct answer is , which can be typed in as follows: 1 A correct answer is , which can be typed in as follows: 2 A correct answer is: "≠" A correct answer is: "≠"
3/27/24, 1:25 AM Determinants: Properties and Applications: Attempt review | eClass https://eclass.srv.ualberta.ca/mod/quiz/review.php?attempt=15149458&cmid=7601901 8/22 Question 6 Correct Mark 2.00 out of 2.00 Applications of the Determinant We have already discussed how the determinant of a square matrix \(A\) can be used to determine if \(A\) is invertible. Indeed, \(A\) is invertible if and only if \(\det(A) \) . This, in turn, gives us an application to linear transformations: a linear transformation \(T: \mathbb{R}^n \rightarrow \mathbb{R}^n\) is invertible if and only if the standard matrix \([T]\) of \(T\) is invertible if and only if \(\det([T]) \) . Determinants are useful in other ways. In this learning activity, we will discuss how determinants can be used to compute the inverse of an invertible matrix, as well as some applications of determinants to geometry, including the concept of the cross product of two vectors in \ (\mathbb{R}^3\). Later in Block 6, we will use determinants to compute what is known as the characteristic polynomial of a square matrix. ≠ 0 ≠ 0 Correct Marks for this submission: 2.00/2.00.
3/27/24, 1:25 AM Determinants: Properties and Applications: Attempt review | eClass https://eclass.srv.ualberta.ca/mod/quiz/review.php?attempt=15149458&cmid=7601901 9/22 Question 7 Correct Mark 5.00 out of 5.00 The Adjoint Formula for the Inverse of an Invertible Matrix The concept of the determinant gives us an alternative method for computing the inverse of an invertible matrix. For this method, we require the following definition: Definition: Let \(A\) be an \(n\times n\) matrix with cofactors \(C_{ij} = (-1)^{i+j} \det(A_{ij})\). The adjoint of \(A\), denoted \ (\operatorname{adj}(A)\), is the transpose of the matrix of cofactors of \(A\), that is, \[ \operatorname{adj}(A) = \left[\begin{array}{cccc}C_{11} & C_{12} & \dots & C_{1n} \\ C_{21} & C_{22} & \dots & C_{2n} \\ \vdots & \vdots & & \vdots \\ C_{n1} & C_{n2} & \dots & C_{nn} \end{array} \right]^{ \ T} = \left[\begin{array}{cccc}C_{11} & C_{21} & \dots & C_{n1} \\ C_{12} & C_{22} & \dots & C_{n2} \\ \vdots & \vdots & & \vdots \\ C_{1n} & C_{2n} & \dots & C_{nn} \end{array}\right] \] Theorem: Let \(A\) be an invertible \(n \times n\) matrix, then \[A^{-1}=\frac{1}{\det(A)}\; \operatorname{adj}(A)\] Example: Let \(A = \begin{bmatrix}a&b\\c&d\end{bmatrix}\) be an invertible \(2 \times 2\) matrix, then \(C_{11} = \) d \(C_{12} =\) -c Correct answer, well done. Marks for this submission: 1.00/1.00. Correct answer, well done. Marks for this submission: 1.00/1.00. \(C_{21} =\) -b \(C_{22} =\) a Correct answer, well done. Marks for this submission: 1.00/1.00. Correct answer, well done. Marks for this submission: 1.00/1.00. Thus, \(\operatorname{adj}(A) = \left[\begin{array}{cccc}C_{11} & C_{12} \\ C_{21} & C_{22} \end{array} \right]^T = \left[\begin{array}{cccc}C_{11} & C_{21} \\ C_{12} & C_{22} \end{array} \right] = \) d -b -c a Correct answer, well done. Marks for this submission: 1.00/1.00. and hence \[A^{-1}=\frac{1}{\det(A)}\; \operatorname{adj}(A) = \frac{1}{ad-bc}\begin{bmatrix}d&-b\\-c&a\end{bmatrix}\] So the formula for the inverse of a \(2 \times 2\) matrix that was given in Block 3 is, in fact, the adjoint formula for the inverse of a \(2 \times 2\) matrix. A correct answer is \( d \), which can be typed in as follows: d A correct answer is \( -c \), which can be typed in as follows: -c A correct answer is \( -b \), which can be typed in as follows: -b
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3/27/24, 1:25 AM Determinants: Properties and Applications: Attempt review | eClass https://eclass.srv.ualberta.ca/mod/quiz/review.php?attempt=15149458&cmid=7601901 10/22 A correct answer is \( a \), which can be typed in as follows: a A correct answer is \( \left[\begin{array}{cc} d & -b \\ -c & a \end{array}\right] \).
3/27/24, 1:25 AM Determinants: Properties and Applications: Attempt review | eClass https://eclass.srv.ualberta.ca/mod/quiz/review.php?attempt=15149458&cmid=7601901 11/22 Question 8 Correct Mark 6.00 out of 6.00 Example: Use the adjoint formula for the inverse of a matrix to find the inverse of the invertible matrix \[A = {\left[\begin{array}{ccc} 2 & 1 & 4 \\ 1 & 0 & -1 \\ 0 & 1 & 8 \end{array}\right]}\] Let's start by computing the adjoint of \(A\). Note: in the second line of this computation, "\(+\)" and "\( - \)" represent the sign of the cofactors \(C_{ij} = (-1)^{i+j}\det(A_{ij})\), which are determined by the term \((-1)^{i+j}\). \ (\operatorname{adj} (A)\) \ (=\) \( \left[\begin{array}{cccc}C_{11} & C_{12} & C_{13} \\ C_{21} & C_{22} & C_{23} \\ C_{31} & C_{32} & C_{33} \end{array} \right]^{ \ T}\) \ (=\) \( \left[\begin{array}{cccccc} +\begin{vmatrix}0&-1\\1&8\end{vmatrix}&& - \begin{vmatrix}1&-1\\0&8\end{vmatrix} && +\begin{vmatrix}1&0\\0&1\end{vmatrix}\; \; \\ - \begin{vmatrix}1&4\\1&8\end{vmatrix}& &+\begin{vmatrix}2&4\\0&8\end{vmatrix}& & - \begin{vmatrix}2&1\\0&1\end{vmatrix}\; \; \\ + \begin{vmatrix}1&4\\0&-1\end{vmatrix} && - \begin{vmatrix}2&4\\1&-1\end{vmatrix} && + \begin{vmatrix}2&1\\1&0\end{vmatrix} \; \; \end{array} \right]^{\ T}\) \ (=\) \( \left( \begin{array}{c}\hspace{0.1cm}\\ \\ \\ \\\end{array}\right.\) 1 -8 1 -4 16 -2 -1 6 -1 \ (\left. \begin{array}{c}\hspace{0.1cm}\\ \\ \\ \\\end{array}\right)^T\) Correct answer, well done. Marks for this submission: 3.00/3.00. \ (=\) 1 -4 -1 -8 16 6 1 -2 -1 Correct answer, well done. Marks for this submission: 1.00/1.00. Now, we will compute the determinant of \(A\): \(\det(A) = \) -2 Correct answer, well done. Marks for this submission: 1.00/1.00. Therefore, the inverse of \(A\) is
3/27/24, 1:25 AM Determinants: Properties and Applications: Attempt review | eClass https://eclass.srv.ualberta.ca/mod/quiz/review.php?attempt=15149458&cmid=7601901 12/22 \(A^{-1} = \dfrac{1}{\det(A)}\; \operatorname{adj}(A) = \) -1/2 2 1/2 4 -8 -3 -1/2 1 1/2 Correct answer, well done. Marks for this submission: 1.00/1.00. A correct answer is \( \left[\begin{array}{ccc} 1 & -8 & 1 \\ -4 & 16 & -2 \\ -1 & 6 & -1 \end{array}\right] \). A correct answer is \( \left[\begin{array}{ccc} 1 & -4 & -1 \\ -8 & 16 & 6 \\ 1 & -2 & -1 \end{array}\right] \). A correct answer is \( -2 \), which can be typed in as follows: -2 A correct answer is \( \left[\begin{array}{ccc} -\frac{1}{2} & 2 & \frac{1}{2} \\ 4 & -8 & -3 \\ -\frac{1}{2} & 1 & \frac{1}{2} \end{array}\right] \).
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3/27/24, 1:25 AM Determinants: Properties and Applications: Attempt review | eClass https://eclass.srv.ualberta.ca/mod/quiz/review.php?attempt=15149458&cmid=7601901 13/22 Question 9 Correct Mark 13.00 out of 13.00 Cross Product Definition: If \(\mathbf{u}= [u_1, u_2, u_3]\) and \(\mathbf{v}= [v_1, v_2, v_3]\) are vectors in \(\mathbb{R}^3\), then the cross product of \ (\mathbf{u}\) and \(\mathbf{v}\) is the vector in \(\mathbb{R}^3\) given by \[\mathbf{u}\times\mathbf{v}= [u_2v_3−u_3v_2,\, u_3v_1−u_1v_3,\, u_1v_2−u_2v_1]\] In determinant notation \[\begin{aligned}\mathbf{u}\times\mathbf{v} &= \left[ \, \begin{vmatrix} u_2 & u_3\\ v_2 & v_3 \end{vmatrix}, -\begin{vmatrix} u_1 & u_3\\ v_1 & v_3 \end{vmatrix}, \begin{vmatrix} u_1 & u_2\\ v_1 & v_2 \end{vmatrix} \, \right] \end{aligned}\] As explained later, the cross product \( \mathbf{u}\times\mathbf{v}\) is orthogonal to both \( \mathbf{u}\) and \( \mathbf{v}\). It has applications in mathematics and physics. Let \(\mathbf{e}_1, \mathbf{e}_2, \mathbf{e}_3\) be the standard basis vectors in \(\mathbb{R}^3\). A convenient way to remember this formula is to view it as the following determinant \[\begin{aligned} \mathbf{u} \times \mathbf{v} &=\left| \begin{array}{ccc} \mathbf{e}_1 & \mathbf{e}_2 & \mathbf{e}_3 \\ u_1 & u_2 & u_3 \\ v_1 & v_2 & v_3 \end{array} \right| \\ \\&= \begin{vmatrix} u_2 & u_3\\ v_2 & v_3 \end{vmatrix}\mathbf{e}_1 - \begin{vmatrix} u_1 & u_3\\ v_1 & v_3 \end{vmatrix} \mathbf{e}_2 + \begin{vmatrix} u_1 & u_2\\ v_1 & v_2 \end{vmatrix} \mathbf{e}_3 \\ \\ &= \left[ \, \begin{vmatrix} u_2 & u_3\\ v_2 & v_3 \end{vmatrix}, -\begin{vmatrix} u_1 & u_3\\ v_1 & v_3 \end{vmatrix}, \begin{vmatrix} u_1 & u_2\\ v_1 & v_2 \end{vmatrix} \, \right], \end{aligned}\] where we must use cofactor expansion along row 1. Viewing the cross product as this determinant not only provides us with a helpful way to remember the formula, but it will also enable us to use the properties of the determinant to understand the properties of the cross product, which will be presented in Question 12. Example: Let \(\mathbf{u} = [3,2,1]\) and \(\mathbf{v} = [-1,1,0]\). Compute \(\mathbf{u} \times \mathbf{v}\). \(\mathbf{u} \times \mathbf{v}\) \(= \det \) 2 1 1 0 \(\mathbf{e}_1 \; - \; \det \) 3 1 -1 0 \(\mathbf{e}_2 \; + \; \det \) 3 2 -1 1 \(\mathbf{e}_3\) Correct answer, well done. Marks for this submission: 1.00/1.00. Correct answer, well done. Marks for this submission: 1.00/1.00. Correct answer, well done. Marks for this submission: 1.00/1.00. \(=\) -1 \(\mathbf{e}_1 \; - \; \) 1 \(\mathbf{e}_2 \; + \; \) 5 \(\mathbf{e}_3\) Correct answer, well done. Marks for this submission: 1.00/1.00. Correct answer, well done. Marks for this submission: 1.00/1.00. Correct answer, well done. Marks for this submission: 1.00/1.00. \(=\) -1 -1 5
3/27/24, 1:25 AM Determinants: Properties and Applications: Attempt review | eClass https://eclass.srv.ualberta.ca/mod/quiz/review.php?attempt=15149458&cmid=7601901 14/22 \(\mathbf{u} \times \mathbf{v}\) Correct answer, well done. Marks for this submission: 1.00/1.00. Exercise: Calculate the following cross products. (a) \([1,2,3]\times[4,3,2]=\) -5 10 -5 Correct answer, well done. Marks for this submission: 2.00/2.00. (b) \([1,1,-1]\times[2,0,2]=\) 2 -4 -2 Correct answer, well done. Marks for this submission: 2.00/2.00. (c) \([2,0,2]\times[1,1,-1]=\) -2 4 2 Correct answer, well done. Marks for this submission: 2.00/2.00. A correct answer is \( \left[\begin{array}{cc} 2 & 1 \\ 1 & 0 \end{array}\right] \). A correct answer is \( \left[\begin{array}{cc} 3 & 1 \\ -1 & 0 \end{array}\right] \). A correct answer is \( \left[\begin{array}{cc} 3 & 2 \\ -1 & 1 \end{array}\right] \). A correct answer is \( -1 \), which can be typed in as follows: -1 A correct answer is \( 1 \), which can be typed in as follows: 1 A correct answer is \( 5 \), which can be typed in as follows: 5 A correct answer is \( \left[\begin{array}{ccc} -1 & -1 & 5 \end{array}\right] \). A correct answer is \( \left[\begin{array}{ccc} -5 & 10 & -5 \end{array}\right] \). A correct answer is \( \left[\begin{array}{ccc} 2 & -4 & -2 \end{array}\right] \). A correct answer is \( \left[\begin{array}{ccc} -2 & 4 & 2 \end{array}\right] \).
3/27/24, 1:25 AM Determinants: Properties and Applications: Attempt review | eClass https://eclass.srv.ualberta.ca/mod/quiz/review.php?attempt=15149458&cmid=7601901 15/22 Question 10 Correct Mark 6.00 out of 6.00 The Scalar Triple Product Definition: For \(\mathbf{u} = [u_1, u_2, u_3]\), \(\mathbf{v}= [v_1, v_2, v_3]\), and \(\mathbf{w}= [w_1, w_2, w_3]\), the number given by \ [\mathbf{u}\cdot(\mathbf{v}\times\mathbf{w})\] is called a scalar triple product of \(\mathbf{u}\), \(\mathbf{v}\), and \(\mathbf{w}\). Note: \[\begin{aligned} \mathbf{u}\cdot(\mathbf{v}\times\mathbf{w}) &= [u_1, u_2, u_3] \cdot \left( \left[ \, \begin{vmatrix} v_2 & v_3\\ w_2 & w_3 \end{vmatrix}, - \begin{vmatrix} v_1 & v_3\\ w_1 & w_3 \end{vmatrix}, \begin{vmatrix} v_1 & v_2\\ w_1 & w_2 \end{vmatrix} \, \right] \right) \; \; \; \text{(by definition of} \; \; \mathbf{v} \times \mathbf{w} )\\ &= u_1\begin{vmatrix} v_2 & v_3\\ w_2 & w_3 \end{vmatrix}- u_2\begin{vmatrix} v_1 & v_3\\ w_1 & w_3 \end{vmatrix} +u_3\begin{vmatrix} v_1 & v_2\\ w_1 & w_2 \end{vmatrix}\\ &= \begin{vmatrix} u_1 & u_2 & u_3 \\ v_1 & v_2 & v_3 \\ w_1 & w_2 & w_3 \end{vmatrix} \; \; \; \hspace{6cm}\text{(by cofactor expansion along row 1)}\end{aligned}\] Thus, we can compute \(\mathbf{u}\cdot(\mathbf{v}\times\mathbf{w})\) using the formula \[\mathbf{u}\cdot(\mathbf{v}\times\mathbf{w}) = \begin{vmatrix} u_1 & u_2 & u_3 \\ v_1 & v_2 & v_3 \\ w_1 & w_2 & w_3 \end{vmatrix}\] Example: Compute the following scalar triple product using the determinant formula above. \(\qquad [1,2,1]\cdot([2,0,3]\times[-1,1,0])=\) -7 . The scalar triple product gives us a geometric description of the determinant of \(3 \times 3\) matrices: Theorem: Let \(\mathbf{u}\), \(\mathbf{v}\) and \(\mathbf{w}\) be vectors in \(\mathbb{R}^3\). The volume \(\mathcal{V}\) of the parallelepiped in \(\mathbb{R}^3\) created by the vectors \(\mathbf{u}\), \(\mathbf{v}\) and \(\mathbf{w}\) is given by the absolute value of \ (\mathbf{u}\cdot(\mathbf{v}\times\mathbf{w})\), that is, \[\mathcal{V} = |\mathbf{u}\cdot(\mathbf{v}\times\mathbf{w})|\] Example: The volume \(\mathcal{V}\) of the parallelepiped formed by \(\mathbf{u}=[1,2,1]\), \(\mathbf{v}=[2,0,3]\), and \(\mathbf{w} = [-1,1,0]\) is \ (\mathcal{V} = |\mathbf{u}\cdot(\mathbf{v}\times\mathbf{w})| =\) 7 . This geometric interpretation of the scalar triple product gives us a method to test whether or not three vectors in \(\mathbb{R}^3\) lie in the same plane: Theorem: Let \(\mathbf{u}\), \(\mathbf{v}\) and \(\mathbf{w}\) be vectors in \(\mathbb{R}^3\).
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3/27/24, 1:25 AM Determinants: Properties and Applications: Attempt review | eClass https://eclass.srv.ualberta.ca/mod/quiz/review.php?attempt=15149458&cmid=7601901 16/22 Question 11 Correct Mark 1.00 out of 1.00 Then \(\mathbf{u}\), \(\mathbf{v}\) and \(\mathbf{w}\) lie in the same plane if and only if \(\mathbf{u}\cdot(\mathbf{v}\times\mathbf{w}) =\) 0 . Example: Do the vectors \(\mathbf{u} = [1,2,1]\), \(\mathbf{v} = [2,0,3]\) and \(\mathbf{w} = [-1,1,0]\) lie in the same plane? , since \(\mathbf{u}\cdot(\mathbf{v}\times\mathbf{w}) = \) -7 . No ≠ 0 Correct Marks for this submission: 6.00/6.00. Area of a Parallelogram in \(\mathbb{R}^2\) The determinant of a \(2 \times 2\) matrix also has a nice geometric interpretation. Theorem: Let \(\mathbf{u} = [u_1,u_2]\) and \(\mathbf{v} = [v_1, v_2]\) be vectors in \(\mathbb{R}^2\). Then the area \(\mathcal{A}\) of the parallelogram in \(\mathbb{R}^2\) determined by \(\mathbf{u}\) and \(\mathbf{v}\) is given by the absolute value of \(\det \begin{bmatrix}u_1 & u_2\\v_1&v_2\end{bmatrix}\), that is, \[ \mathcal{A} = \left| \, \det \begin{bmatrix}u_1 & u_2\\v_1&v_2\end{bmatrix} \, \right | \] Example: Find the area \(\mathcal{A}\) of the parallelogram in \(\mathbb{R}^2\) determined by the vectors \(\mathbf{u} = [-1,4]\) and \ (\mathbf{v} = [3,-2]\). \( \mathcal{A} = \left| \, \det \begin{bmatrix}-1&4\\3&-2\end{bmatrix} \, \right| =\) 10 Correct Marks for this submission: 1.00/1.00.
3/27/24, 1:25 AM Determinants: Properties and Applications: Attempt review | eClass https://eclass.srv.ualberta.ca/mod/quiz/review.php?attempt=15149458&cmid=7601901 17/22 Question 12 Correct Mark 8.00 out of 8.00 Properties of the Cross Product Recall: \[\begin{aligned} \mathbf{u} \times \mathbf{v} &=\left| \begin{array}{ccc} \mathbf{e}_1 & \mathbf{e}_2 & \mathbf{e}_3 \\ u_1 & u_2 & u_3 \\ v_1 & v_2 & v_3 \end{array} \right| \\ \\ &= \left[ \, \begin{vmatrix} u_2 & u_3\\ v_2 & v_3 \end{vmatrix}, -\begin{vmatrix} u_1 & u_3\\ v_1 & v_3 \end{vmatrix}, \begin{vmatrix} u_1 & u_2\\ v_1 & v_2 \end{vmatrix} \, \right], \end{aligned}\] When considering the properties of the cross product below, keep in mind the properties of the determinant. For the following statements, let \(\mathbf{u},\,\mathbf{v}\) and \(\mathbf{w}\) be vectors in \(\mathbb{R^3}\) and \(k\in\mathbb{R}\). (a) \((k\mathbf{u})\times\mathbf{v}=\) k \ ((\mathbf{u}\times\mathbf{v})=\mathbf{u}\times(k\mathbf{v})\). \ (\hspace{2cm}\) (What happens to the determinant above if one row is multiplied by the scalar \(k\)?) Correct answer, well done. Marks for this submission: 1.00/1.00. (b) \(\mathbf{u}\times(\mathbf{v}+\mathbf{w})= (\mathbf{u}\times\mathbf{v})+(\mathbf{u}\times\mathbf{w})\). (c) \((\mathbf{u}+\mathbf{v})\times\mathbf{w}= (\mathbf{u}\times\mathbf{w})+(\mathbf{v}\times\mathbf{w})\). (d) \(\mathbf{u}\times\mathbf{0}=\) 0 0 0 \ (=\mathbf{0}\times\mathbf{u}\). Correct answer, well done. Marks for this submission: 1.00/1.00. (e) \(\mathbf{u}\parallel\mathbf{v} \,\, \Leftrightarrow \,\, \mathbf{u}\times\mathbf{v}=\) 0 0 0 . (Recall: \(\mathbf{u}\parallel\mathbf{v} \) means that \(\mathbf{u}\) and \(\mathbf{v}\) are parallel.) (What happens to the determinant above if \(\mathbf{u}\) and \(\mathbf{v}\) are parallel?) Correct answer, well done. Marks for this submission: 1.00/1.00. (f) \(\mathbf{u}\cdot(\mathbf{u}\times\mathbf{v})=\) 0 and \ (\mathbf{v}\cdot(\mathbf{u}\times\mathbf{v})=\) 0 . Thus, \(\mathbf{u}\times\mathbf{v}\) is to both \ (\mathbf{u}\) and \(\mathbf{v}\). (What are the determinants of the associated 3x3 matrices for these scalar triple products?) Correct answer, well done. Marks for this submission: 1.00/1.00. Correct answer, well done. Marks for this submission: 1.00/1.00. Correct answer, well done. Marks for this submission: 1.00/1.00. (g) For \(\mathbf{u}\nparallel\mathbf{v}\) the ordered triple of vectors \((\mathbf{u},\mathbf{v},\mathbf{u}\times\mathbf{v})\) has right hand orientation . i.e. if using your right hand, you point your index finger in the direction of \(\mathbf{u}\) and your middle finger in the direction of \(\mathbf{v}\) then \(\mathbf{u}\times\mathbf{v}\) will point in the same direction as your thumb if you point it so that it is perpendicular to the plane made by your index and middle fingers. orthogonal
3/27/24, 1:25 AM Determinants: Properties and Applications: Attempt review | eClass https://eclass.srv.ualberta.ca/mod/quiz/review.php?attempt=15149458&cmid=7601901 18/22 In the diagram below, the observer is viewing the plane spanned by \(\mathbf{u}\) and \(\mathbf{v}\) from slightly above the plane. The direction of \(\mathbf{u}\times\mathbf{v}\) is in the same direction as the vector. (The red arrow is the one pointing upwards in the diagram, and the purple down.) Correct answer, well done. Marks for this submission: 1.00/1.00. (h) \(\mathbf{v}\times\mathbf{u}=\) \ ((\mathbf{u}\times\mathbf{v})\). \ (\hspace{3cm}\) (What happens to the determinant above if you interchange row 2 and row 3?) Correct answer, well done. Marks for this submission: 1.00/1.00. (i) The area \(\mathcal{A}\) of the parallelogram in \(\mathbb{R}^3\) determined by the vectors \(\mathbf{u}\) and \(\mathbf{v}\) is given by \[ \mathcal{A} = || \mathbf{u} \times \mathbf{v} ||\] Furthermore, if \(\theta\) is the angle between \(\mathbf{u}\) and \(\mathbf{v}\), then \ [\|\mathbf{u}\times\mathbf{v}\|=\|\mathbf{u}\|\,\|\mathbf{v}\|\,\sin\theta\] red - A correct answer is \( k \), which can be typed in as follows: k A correct answer is \( \left[\begin{array}{ccc} 0 & 0 & 0 \end{array}\right] \). A correct answer is \( \left[\begin{array}{ccc} 0 & 0 & 0 \end{array}\right] \). A correct answer is \( 0 \), which can be typed in as follows: 0 A correct answer is \( 0 \), which can be typed in as follows: 0 A correct answer is: "orthogonal" A correct answer is: "red" A correct answer is: "-"
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3/27/24, 1:25 AM Determinants: Properties and Applications: Attempt review | eClass https://eclass.srv.ualberta.ca/mod/quiz/review.php?attempt=15149458&cmid=7601901 19/22 Question 13 Correct Mark 9.00 out of 9.00 Example: Let \(\mathbf{u}\) and \(\mathbf{v}\) be vectors in \(\mathbb{R}^3\) and suppose \(\mathbf{u} \times \mathbf{v} = [2,1,-3]\). Compute \((4\mathbf{v} + \mathbf{u}) \times (2\mathbf{u})\). \((4\mathbf{v} + \mathbf{u}) \times (2\mathbf{u})\) \(= ((4\mathbf{v}) \times (2\mathbf{u})) + (\mathbf{u} \times (\mathbf{2u}))\) \(\big(\)by Property \(\big)\) Correct answer, well done. Marks for this submission: 1.00/1.00. \(=\) 8 \((\mathbf{v} \times \mathbf{u}) + 2 (\mathbf{u} \times \mathbf{u})\) \(\big(\)by Property \(\big)\) Correct answer, well done. Marks for this submission: 1.00/1.00. Correct answer, well done. Marks for this submission: 1.00/1.00. \(=\) -8 \((\mathbf{u} \times \mathbf{v}) + 2 (\mathbf{u}\times \mathbf{u}) \) \(\big(\)by Property \(\big)\) Correct answer, well done. Marks for this submission: 1.00/1.00. Correct answer, well done. Marks for this submission: 1.00/1.00. \(=\) -8 \((\mathbf{u} \times \mathbf{v}) + 2\) 0 0 0 \(\big(\)by Property \(\big)\) Correct answer, well done. Marks for this submission: 1.00/1.00. Correct answer, well done. Marks for this submission: 1.00/1.00. Correct answer, well done. Marks for this submission: 1.00/1.00. \(=\) -16 -8 24 Correct answer, well done. Marks for this submission: 1.00/1.00. (c) (a) (h) (e)
3/27/24, 1:25 AM Determinants: Properties and Applications: Attempt review | eClass https://eclass.srv.ualberta.ca/mod/quiz/review.php?attempt=15149458&cmid=7601901 20/22 Question 14 Correct Mark 5.00 out of 5.00 A correct answer is: "(c)" A correct answer is \( 8 \), which can be typed in as follows: 8 A correct answer is: "(a)" A correct answer is \( -8 \), which can be typed in as follows: -8 A correct answer is: "(h)" A correct answer is \( -8 \), which can be typed in as follows: -8 A correct answer is \( \left[\begin{array}{ccc} 0 & 0 & 0 \end{array}\right] \). A correct answer is: "(e)" A correct answer is \( \left[\begin{array}{ccc} -16 & -8 & 24 \end{array}\right] \). Exercise: Let \(\mathbf{u}=[3,-2,1]\), \(\mathbf{v}=[1,1,1]\) and \(\mathbf{w}=[2,-2,0]\). The area of the parallelogram formed by \(\mathbf{u}\) and \(\mathbf{v}\) is \(\mathcal{A}=\sqrt{\,}\) 38 . The volume of the parallelepiped formed by \(\mathbf{u},\,\mathbf{v}\) and \(\mathbf{w}\) is \(\mathcal{V}=\) 2 . Given that the volume of a parallelepiped is the area of its base times its height, the height of the parallelepiped formed by \ (\mathbf{u},\,\mathbf{v}\) and \(\mathbf{w}\) when its base is viewed as the parallelogram formed by \(\mathbf{u}\) and \(\mathbf{v}\) is \(h=\) 2 \(/\sqrt{\,}\) 38 . The parallelepiped formed by \(\mathbf{u}\) and \(\mathbf{v}\) and \(k\mathbf{u}\times\mathbf{v}\) will have the same volume as the parallelepiped formed by \(\mathbf{u},\,\mathbf{v}\) and \(\mathbf{w}\) if \(k=\pm1/\) 19 . Correct Marks for this submission: 5.00/5.00.
3/27/24, 1:25 AM Determinants: Properties and Applications: Attempt review | eClass https://eclass.srv.ualberta.ca/mod/quiz/review.php?attempt=15149458&cmid=7601901 21/22 Question 15 Correct Mark 7.00 out of 7.00 Using the Cross Product to Find the Equation of a Plane We know from Property (f) that the cross product \(\mathbf{u} \times \mathbf{v}\) is orthogonal to both of the vectors \(\mathbf{u}\) and \ (\mathbf{v}\). Therefore, if \(\mathbf{u}\) and \(\mathbf{v}\) are a pair of direction vectors for a plane, then \(\mathbf{u} \times \mathbf{v}\) is a normal vector for the plane. An example similar to, yet different from, the one given below can be found in the video Determinants: Properties and Applications 2 starting at 7:40. Example: Consider the plane \(\mathcal{P}\) in \(\mathbb{R}^3\) that contains the three points \(\mathbf{p_1}=[1,0,1]\), \(\mathbf{p_2}= [1,0,0]\) and \(\mathbf{p_3}=[0,1,0]\). Let \(\mathbf{u} = \mathbf{p_2}-\mathbf{p_1} = \) 0 0 -1 and let \(\mathbf{v} = \mathbf{p_3}-\mathbf{p_1} =\) -1 1 -1 . Correct answer, well done. Marks for this submission: 1.00/1.00. Correct answer, well done. Marks for this submission: 1.00/1.00. Since \(\mathbf{u}\) and \(\mathbf{v}\) scalar multiples of each other, they parallel and hence \(\mathbf{u}\) and \(\mathbf{v}\) serve as direction vectors for \(\mathcal{P}\). Correct answer, well done. Marks for this submission: 1.00/1.00. Correct answer, well done. Marks for this submission: 1.00/1.00. Using the cross product of the vectors \(\mathbf{u}\) and \(\mathbf{v}\), we obtain that a normal vector for this plane is \(\mathbf{n}= \mathbf{u} \times \mathbf{v} =\) 1 1 0 Correct answer, well done. Marks for this submission: 2.00/2.00. Now, using this and the fact that the point \(\mathbf{p_1}\) is in the plane we obtain that the general equation for this plane is x+y-1=0 Correct answer, well done. Marks for this submission: 1.00/1.00. (Use \(x, y, z\) as the variables in your computation for this equation.) There is yet another way to use the determinant to obtain the general equation of a plane in \(\mathbb{R}^3\). It essentially amounts to the same calculation as with the cross product above, but the argument is different: see the first half of the video Determinants: Properties and Applications 2 . are not are not
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3/27/24, 1:25 AM Determinants: Properties and Applications: Attempt review | eClass https://eclass.srv.ualberta.ca/mod/quiz/review.php?attempt=15149458&cmid=7601901 22/22 A correct answer is \( \left[\begin{array}{ccc} 0 & 0 & -1 \end{array}\right] \). A correct answer is \( \left[\begin{array}{ccc} -1 & 1 & -1 \end{array}\right] \). A correct answer is: "are not" A correct answer is: "are not" A correct answer is \( \left[\begin{array}{ccc} 1 & 1 & 0 \end{array}\right] \). A correct answer is \( y+x=1 \), which can be typed in as follows: y+x = 1
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