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Feb 20, 2024
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Lab 6: Interference and Diffraction
Introduction: Light passing through a single slit is called diffraction ; however light passing
through the double slit is called interferenc. Addtionally, these pattern varies in different
condition. Foe example, increasing or dreasing the slit width would affect both inteference,
and diffraction pattern. Further more, decreasing the slit width in a single slit increases the
width of the central maximum; however decreasing the slit width in a double slit would cause
the maxima(m=5/m=10) will be further apart.
Procedure:
Part 1:
The screen was covered with a piece of paper on the other side facing the laser. The slit was
adujusted to appropriate
slit width. The distance between the screen and the slit was measure. For
this experiment a single slit was used.
The diffraction pattern of the minima was marked on the
paper, and the distance between first orders and second orders was recored.
The same was repeated
with various slit width, and calculations were made at the end.
Part 2:
The screen was covered with a piece of paper on the other side facing the laser. The slit was
adujusted to appropriate
slit width. The distance between the screen and the slit was measure. For
this experiment a double slit was used.
The interferance pattern of the maxima was marked on the
paper, and the distance between the 5
th
orders and 10
th
orders was recored.
The same was repeated
with various slit width, and calculations were made at the end. Lastly, 0.04mm slit width and slit
seperation of 0.50 mm was used to the maxima for the green laser.
Results:
Screen distance(D): 0.62 m(+- 0.0005m)
Laser wavlength: 650 x10^-9m
Table 1: Diffraction of a single slit
Given slit width:
agiven=0.00004m
Given slit width:
agiven=0.00016m
Given slit width:
agiven=0.00008m
m=1
m=2
m=1
m=2
m=1
m=2
Distance between left and
rigth minima(2y) (m) (+-
0.0005m)
0.0285
0.045
0.005
0.01
0.02
0.03
Mean distance between
minma and center(y) (m)
(+- 0.0005m)
0.01125
0.0225
0.0025
0.005
0.01
0.015
Calculate slit width (acal)
(m) (+- 0.0005m)
3.58x10^-5
3.58x10^-5
1.612x10^-4
1.612x10^-4
4.03x10^-5
8.06x10^-5
Percent error acal, and
agiven (%)
10.4
10.4
0.75
0.75
49.6
0.75
Given slit seperation: 0.005m
Screen distance(D): 1.03m (+- 0.005m)
Laser wavlength: 650x10^-9m
Slit width=4x10^-5m
Table 2:
Intereferance of double slit (red laser)
m=5
M=10
Distance between left and
rigth minima(2y) (m) (+-
0.005m)
0.013
0.026
Mean distance between
minma and center(y) (m)
(+- 0.0005m)
0.0065
0.013
Calculate slit width (acal)
(m) (+- 0.000005m)
5.15x10^-5
5.15x10^-5
Percent error acal, and
agiven (%)
3
3
Given slit seperation: 0.005m
Screen distance(D): 0.62m(+- 0.5m)
Laser wavlength: 532x10^-9m
Slit width=4x10^-5m
Table 3:
Intereferance of double slit (green laser)
m=5
M=10
Distance between left and
rigth maxima(2y) (m) (+-
0.0005m)
0.008
0.018
Mean distance between
maxima and center(y) (m)
(+- 0.0005m)
0.004
0.009
Calculate slit width (acal)
(m) (+- 0.0005m)
4.123x10^-4
3.66x10^-4
Percent error acal, and
agiven (%)
17.54
26.7
Analysis:
Calculation (example):
slit width (acal)
a=mλD/y
a=1(650x10
^-9m)(0.62m)/0.01125
a=3.58x10^-5 m
Percent error:
Theoritical-experimental/theoriticalx100
0.00004m-3.58x10^-5m /0.00004mx100=10.4 %
Part 2(example):
dcal= mλD/a
dcal= 1(650x10
^-9m)(
0.103)/
0.0065m=5.15x10^-5m
Percent error:
Theoritical-experimental/theoriticalx100
0.00005m-5.15x10^-5m/0.00005mx100=3 %
For a single slit, a obvious pattern was observed. As the slit width increased, the distance
between the minima decreased. The calculated numbers, and numbers received experimentally
had a uncertainty of
+- 0.0005m
, due to the fact that the distance measured between the orders
were very small, and experimental distance was prone to error. This conclusion was made
based on various issues such as the tools used (ruler) on this experiment. The ruler was in cm,
so therefore it wasn’t precise enough since it had a lower amount of significant numbers.
Additionally, human error such as “not accounting” in all the numbers after the decimal point,
and also a possible mistake when marking the minima in the diffraction pattern could have also
impacted the final measurement. For a double slit
Conclusion:
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Questions:
Q1: Dark fringes on the screen on a single slit is caused by a destructive interference,
and the bright fringes on the screen on a single slit caused by constructive interference.
Q2:asintheta=mλ
Q3:tan(theta)=y/D
Q4 tan(theta)=y/D
tan(theta)=0.01m/1m
Theta=tan^-1(0.01m/1m)=0.57
Since theta is really small, it shouldn’t introduce significant amount of error.
Q5:y=mλD/a
a=mλD/y
Q6: : This equation is really similar to the one describing diffraction because the
condtions in a minima is same as the conditions in a maxima double slit
Q7: asintheta=mλ
Q8: :tan(theta)=y/D
Q9:dcal= mλD/a
Q10Q11: light fringes in a double slit is produced when two lights travel the same
distance to the screen; however dark fringle in a double slit is produced by lights
traveling out of phase(180 degreees).
Q11: Changing the slit width will affect the difraction pattern, and it depends wheather
the slit is widder or narrower. If the width is widder, the the diffraction pattern
decreases(closer), and if the slit was narrower the diffraction pattern will increase.
Increase in d=increase in sin(theta)=increase in theta
Q12: If slit seperation increases, the inference pattern decreases, and the slit seperation
is narrower the slit seperation increases
Q13: If slit width increases, the inference pattern decreases, and the slit width is
narrower the slit seperation increases
Q14: Increase in waevelength= increase in interference pattern
Decrease in waevelength= Decrease in interference pattern
Q15: If young’s experiment was done under the water, the fringes are closely spread.
Speed of the light decreases, so does the fringe with