ECE486 - Lab5 Report

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University of Illinois, Urbana Champaign *

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Industrial Engineering

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Jan 9, 2024

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Lab 5 PD C ONTROL U SING A NALOG C OMPUTER & W IN C ON 1 of 6 Report By: Justin Habana Lab Partner: John Truong Lab TA: Usman Ahmed Syed Section: AB2 Part 1. ___/44 (A). Theoretical Performance Criterion. __/8 We note the following … ?(?) = 900𝑃 1 𝐾 𝑎?? 𝐾 ??? ? 2 + ?(5 + 900𝑃 2 𝐾 𝑎?? 𝐾 ?𝑎𝑐ℎ ) + 900𝑃 1 𝐾 𝑎?? 𝐾 ??? 𝜔 ? = √900𝑃 1 𝐾 𝑎?? 𝐾 ??? 𝜁 = 5 + 900𝑃 2 𝐾 𝑎?? 𝐾 ?𝑎𝑐ℎ 2𝜔 ? = 5 + 900𝑃 2 𝐾 𝑎?? 𝐾 ?𝑎𝑐ℎ 900𝑃 1 𝐾 𝑎?? 𝐾 ??? 𝑀 ? = { exp (− 𝜋𝜁 √1 − 𝜁 2 ) , 0 < 𝜁 < 1 0, 𝜁 ≥ 1 ? ? { 1.2 − 0.45𝜁 + 2.6𝜁 2 𝜔 ? , 0 < 𝜁 < 1.2 4.7𝜁 − 1.2 𝜔 ? , 1.2 ≤ 𝜁 < 3 ? ? { 0.5 𝜁𝜔 ? ln ( 1 − 𝜁 2 400 ) , 0 < 𝜁 ≤ 0.69 6.6𝜁 − 1.6 𝜔 ? , 0.69 < 𝜁 < 3 Table 1, Theoretical Values according to Fig 5.1 Gains 1 P1 = 0.15 P2 = 0 Gains 2 P1 = 0.25 P2 = 0.35 Gains 3 P1 = 0.1 P2 = 0.5 Gains 4 P1 = 0.88 P2 = 0.8 Σ 0.1101 0.4721 1.0086 0.5167 ω n 22.7082 29.3162 18.5412 55.0020 M p (%) 70.61% 18.59% 0 15.02% t r (s) 0.0521 0.0535 0.1829 0.0302 t s (s) 1.2007 0.2256 0.2727 0.1109 Total ___/90
Lab 5 PD C ONTROL U SING A NALOG C OMPUTER & W IN C ON 2 of 6 (B). Experimental Performance Criterion. __/12 Table 2, Experimental Values, Section I (Analog Computer) Gains 1 P1 = 0.15 P2 = 0 Gains 2 P1 = 0.25 P2 = 0.35 Gains 3 P1 = 0.1 P2 = 0.5 Gains 4 P1 = 0.88 P2 = 0.8 M p (%) 51.64% 0.94% 0.16% 3.47% t r (s) 0.0550 0.0720 0.2390 0.0400 t s (s) 0.2740 0.0980 0.3090 0.0550 Table 3, Experimental Values, Section II (WinCon) Gains 1 P1 = 0.15 P2 = 0 Gains 2 P1 = 0.25 P2 = 0.35 Gains 3 P1 = 0.1 P2 = 0.5 Gains 4 P1 = 0.88 P2 = 0.8 M p (%) 61.30% 1.83% 0.37% 5.90% t r (s) 0.0480 0.0640 0.1820 0.0340 t s (s) 0.3000 0.0860 0.2360 0.0780 Table 4, Experimental Values, Section III (WinCon with Friction Compensation) Gains 1 P1 = 0.15 P2 = 0 Gains 2 P1 = 0.25 P2 = 0.35 Gains 3 P1 = 0.1 P2 = 0.5 Gains 4 P1 = 0.88 P2 = 0.8 M p (%) 28.13% 5.47% 0.89% 3.52% t r (s) 0.0580 0.0560 0.1460 0.0400 t s (s) 0.9840 0.1180 0.2180 0.0440 Compare results from Section I with those from Section II ___/8 Compared to section II, the section I 𝑀 ? values appear lower overall, ? ? values appear higher, and no trend was for ? ? values. These differences are likely due to physical forces present in the relatively large physical components of the Analog Computer used in section I compared to mainly computational processes of Simulink used in section II.
Lab 5 PD C ONTROL U SING A NALOG C OMPUTER & W IN C ON 3 of 6 Compare results from Section II with those from Section III ___/16 We compare section II values with section III, then determine if the section II values are higher or lower. This is shown in the table below. Gains 1 P1 = 0.15 P2 = 0 Gains 2 P1 = 0.25 P2 = 0.35 Gains 3 P1 = 0.1 P2 = 0.5 Gains 4 P1 = 0.88 P2 = 0.8 M p (%) Much higher Lower Lower Higher t r (s) Lower Higher Higher Lower t s (s) Much Lower Lower Higher Higher We do not see a consistent trend of difference between section II and section III. We do not however, that Gains 1, with 𝐾 2 = 0 , that the presence of friction (section II) significantly increased percent overshoot and decreased settling time.
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Lab 5 PD C ONTROL U SING A NALOG C OMPUTER & W IN C ON 4 of 6 Part 2. ___/18 Compare performance of your design to the Specs ___/10 Our selected theoretical gains (Gains 4) did not meet the prelab specifications. However, through trial and error, 𝑃 1 = 0.9845 and 𝑃 2 = 0.625 produced gains that met the prelab specifications when using the Analog Computer. Gains of 𝐾 1 = 9.6 and 𝐾 2 = 6.5 met the prelab specifications using WinCon without friction compensation. Explain how unmodeled plant dynamics might cause problems ___/8 We acknowledge that there are dynamics not modeled in the pre-lab which may influence real world systems.
Lab 5 PD C ONTROL U SING A NALOG C OMPUTER & W IN C ON 5 of 6 Part 3. ___/16 Theoretical and measured E ss ___/8 We take note of the block diagram of the system shown below. In which 𝐸 𝑉 ? = 1 1 + 1 ? 𝐾 1 𝐾 ??? ?(?) , ?(?) = 𝐾 𝑎?? ?(?) 1 + 𝐾 2 𝐾 𝑎?? 𝐾 ?𝑎𝑐ℎ ?(?) , ?(?) = 18 1 + 0.2? 𝐸 𝑉 ? = 0.2? 2 + ( 18 𝐾 2 𝐾 𝑎?? 𝐾 ?𝑎𝑐ℎ + 1 )? 0.2? 2 + ( 18 𝐾 2 𝐾 𝑎?? 𝐾 ?𝑎𝑐ℎ + 1 )? + 18𝐾 1 𝐾 ??? 𝐾 𝑎?? lim ?→0 ?𝐸 = 1 18𝐾 1 𝐾 ??? 𝐾 𝑎?? , 𝐾 1 = 10𝑃 1 Gains 1 P1 = 0.15 P2 = 0 Gains 2 P1 = 0.25 P2 = 0.35 Gains 3 P1 = 0.1 P2 = 0.5 Gains 4 P1 = 0.88 P2 = 0.80 Theoretical 0.97% 0.58% 1.45% 0.17% Section I 2.11% 0.16% 9.49% 0.59% Section II 2.05% 1.17% 9.08% 0.29% Section III 4.39% 0.10% 1.56% 0.10% Table 5, Steady-state error What gain adjustments helped decrease steady-state error? ___/8 In general, steady state error increases as gain 𝐾 1 decreases.
Lab 5 PD C ONTROL U SING A NALOG C OMPUTER & W IN C ON 6 of 6 Part 4. ___/12 Friction Values ___/6 Friction Values Lab 4 Lab5, Section III full values Lab5, Section III Reduced values Coulomb Positive 0.0080300 0.00095 0.000375 Coulomb Negative 0.0095000 0.01000 0.010000 Viscous Positive 0.0000670 0.00101 0.000404 Viscous Negative 0.0000615 0.01100 0.011000 Table 6, Friction Values Discuss the Variation in the friction Values ___/6 To illustrate how much we reduced the friction values, the ratio of reduced values over full values are shown in the below table. Friction Values Ratio of reduced over full values Coulomb Positive 0.3947 Coulomb Negative 1.0000 Viscous Positive 0.4000 Viscous Negative 1.0000 Compared to lab four, both reduced and full lab 5 friction values are - Lower for coulomb positive - About the same for coulomb negative - Higher for viscous positive and negative
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