Lab #7Solar1-1

Name ______ N/A _______________ Section # _____ 5 ____ Introduction to Human-Environment Geography (GEOG 1050) Laboratory Lab #7: Solar Energy Introduction The primary energy source for the Earth’s climate system is solar radiation (i.e. shortwave, or visible light from the Sun). The amount of that radiation reaching the surface of the earth changes on a daily and seasonal basis due to the positioning of the earth relative to the sun, and climatic features such as cloud cover and atmospheric concentration. In determining the potential for solar energy to be used, practically, as a form of alternative energy, it is critical to know just how much solar radiation reaches the surface. Once measured, the amount of electricity the solar panel provides can be calculated, and an informed decision on if and/or where installing the panels can be made. In today’s lab, we will be measuring the incoming solar radiation at two locations on campus, then using those observations to determine a rough ‘feasibility’ figure, given average costs and efficiencies. The objectives of this lab are to: 1) Confidently measure solar radiation and interpret the observations 2) Calculate the electricity yield for a standard solar panel given those observations and within climatology 3) Run a cost-benefit analysis of installing a solar panel suite on campus Background Information/Further Reading Earth-Sun Relationships The four most important factors that determine the amount of incoming solar radiation reaches and is absorbed by the surface are: (1) the time of day (i.e. solar altitude), (2) the day of the year (i.e. solar declination; length of day light), (3) the percentage (and type) of cloud cover, and (4) surface albedo. (1) Over the course of the day, the sun’s angle above the horizon (solar altitude) changes as a function of Earth’s rotation on its axis. This influences the intensity of solar radiation, where the surface receives more energy from the sun at noon, compared to when the sun is rising or setting. Thus, energy from the sun is considered ‘most intense’ at noon. The maximum altitude of the sun depends on the time of year and latitude (2) The intensity of solar radiation varies substantially over the course of a year based on the Earth’s tilt and revolution around the sun. In Nebraska (approximately 41°N latitude), average daily radiation at the top of the atmosphere varies from 150 Watts per meter squared (W/m 2 ) in the winter, to 450 W/m 2 in the summer. (3) Clouds, particularly liquid-based clouds, reflect a portion of incoming radiation back to space, thus less radiation reaches the surface. Liquid-based clouds are more effective at reflecting solar radiation than ice-based clouds. (4) Based on the reflectivity, or albedo, of the surface, a percentage of incoming solar radiation is reflected away and a percentage is absorbed. Lighter surfaces have a higher albedo, thus reflect more incoming solar radiation and absorb less (typically making them cooler).. Darker surfaces on the other hand have a lower albedo, thus reflect less, and absorb more (typically making them warmer).

Solar Panels At its most basic, solar panels are a series of photovoltaic cells linked together that harness photons (particles of light) to generate electricity. As the photon hits the cells, electrons are excited and ‘freed’, then transported away via an established electric field within the cell, yielding electricity. These are the most commonly-used house-hold and commercial versions of solar power technology, but other forms, such as solar thermal and concentrated solar panels, also exist. There are a number of extending readings on these types of solar panels available online. Today’s solar panels are substantially more affordable than their previous versions from only a decade ago, however there are still upfront costs associated with installing these panels, and due to energy availability and efficiency concerns, they may or may not be a viable option for every location. Every solar panel has a maximum wattage rating, which indicates how much energy can be harnessed at ideal conditions. Naturally, conditions are not always ideal, and during these non-idealized times, the efficiency of the panel decreases. Warmer temperatures, older panels, and shaded conditions can all result in lower electricity yield. In the energy business, electricity is typically reported in kilowatt-hour (kWh). This is a measure of the amount of energy needed to power a 1,000-watt appliance for 1 hour. For example, a 100-watt light bulb would use 1 kWh of energy in 10 hours. So for our solar panels, we’ll need to convert our watts (W) to kWh. 1 kW = 1,000 W. 1 kWh is the production of 1kW continuously for a period of 1 hour. Here in Nebraska, we pay, on average, about 9.0 cents per kWh (which is one of the lowest rates in the country!). Measuring solar radiation To measure solar radiation, we will be using pyranometers. This instrument records the amount of solar radiation that enters the fixture, and shows the W/m 2 value in the display. These can be pointed in any direction. While they are relatively sturdy, they can break by dropping them, so please handle with care. Once you are done taking observations, please turn the sensor off! Questions Part 1 – Observing Solar Radiation 1. In your assigned teams, choose two locations in the surrounding area outside of lab, one should be in the shade (i.e. under a tree/awning or next to a building) while the other should be not obstructed (i.e. open area). Complete the table below. Location 1: Outside Durham Location 2: Grass outside Durham Site Description: Outside the entrance of Durham, there is little building obstruction in the spot where we collected the observations. Site Description: The grass is in complete shade due to the branches of the large tree above us. There were a couple buildings obstructing the sun because of its direction. Sky Cover Observation (see previous labs): Sky Cover Observation:

6. The data shown is the average across many years. Within a true calendar year, how might solar radiation actual change? How could a changing climate influence these solar radiation observations? Solar radiation decreases in fall and winter. The above information does not account for those factors, it is a generalization; the time of year impacts solar radiation levels. Climate change can increase the amount of radiation and our temperatures compared to other climatic factors. It can also influence cloud cover. Part 3 – Feasibility 7. The average Nebraska household uses approximately 33 kWh per day of electricity. Let’s assume that our typical solar panel generates 1.493 kWh of electricity per day. What percentage would our solar panel cover? 1.49kWh / 33kWh x100 = 4.51… or 4.5% 8. What is the minimum number of panels we would need to cover the entire demand calculated in #7? 23 Panels (33kWh/1.493 [22.1]) 9. A typical house roof is about 150 m 2 in area, but only about half is usable for panels. Let’s assume that the size of our solar panel is 1.0m wide and 2m tall. Given this, and the number of panels needed to cover the typical Nebraskan’s energy demand (i.e. #8), is there enough room on the roof? Show your work. 23 * 2m^2 = 46; Yes, there is enough room. 150/2= 75 0.0 100.0 200.0 300.0 400.0 500.0 600.0 0:00 1:00 2:00 3:00 4:00 5:00 6:00 7:00 8:00 9:00 10:00 11:00 12:00 13:00 14:00 15:00 16:00 17:00 18:00 19:00 20:00 21:00 22:00 23:00 Solar Radiation (Wh/m2) Time of Day

10. Say you’re a homeowner and decided to install 25 solar panels on your roof. Using your calculations from above, how much energy would the panels generate per day? Hint: Use 1.493 kWh for daily energy generated, but scale up to 25 panels. 1.492* 25 = 37.3 kWh 11. How much energy would the answer to #10 be for a 365-day year? 13,614.5 kWh 12. The cost of electricity is approximately 9.0 cents per kWh here in Nebraska. For a 365-day year, how much money would the electricity from your solar panels generate? 13,614.5 * .09 = $1,225.31 13. The cost of your 25-panel solar setup was $12,000. Assuming there are no other maintenance costs or changes to electricity pricing, how long would it take for you to make your money back on your initial investment? 10 years : 12,000/1,225.31= 9.793 or 9.8, then we round to the nearest whole number which is 10. 14. Let’s say you lived in Burlington, VT where electricity is approximately 16 cents per kWh. Hypothetically, Burlington receives the same amount of solar energy as Omaha, and you built the same solar array there as you did in Omaha. Recalculate questions 12 and 13 for Burlington, determining (a) the price of the electricity generated using Burlington prices, and (b) how long it would take you to make your money back in Burlington. a. 13614.5 * .16 = $2,178.32 b. $12,000/$2178.32 = 5.5 years