CLIMATE 105 Assignment 2 Answer Key

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Geography

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Jun 4, 2024

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CLIMATE 105: Our Changing Atmosphere (Spring 2024) Assignment 2 Due Friday, May 24: please show all work! 1. Calculate the energy of photons with the following wavelengths: (10 points) E = ℎ𝑐 λ (Planck’s constant, h = 6.626 × 10 -34 m 2 kg/s; velocity of light, c = 3 x 10 8 m/s) a. 1 m E = (6.626 x 10 -34 x 3 x 10 8 / 1) J E = 1.987 x 10 -25 J b. 1 cm E = (6.626 x 10 -34 x 3 x 10 8 / 1) J E = 1.987 x 10 -23 J c. 0.5 μm E = (6.626 x 10 -34 x 3 x 10 8 / 0.5 x 10 -6 ) J E = 3.975 x 10 -19 J d. 250 nm E = (6.626 x 10 -34 x 3 x 10 8 / 250 x 10 -9 ) J E = 7.951 x 10 -19 J 2. Calculate the energy flux and peak wavelengths of the energy radiated from the following celestial objects: (10 points) 𝐹 = 𝜎 𝑇 4 λ = 2989 𝑇 (Stefan – Boltzmann constant, σ = 5.67 × 10 8 W m 2 K 4 ; a. The Sun’s photosphere or “surface”: T = 5700 K F = (5.67 × 10 −8 x 5700 4 ) W/m 2 F = 59852525.67 W/m 2 = 5.985 x 10 7 W/m 2 λ max = (2898 / 5700) μm λ max = 0.508 μm b. Neutron star: T = 600,000 K
F = (5.67 × 10 −8 x 600000 4 ) W/m 2 F = 7.348 x 10 15 W/m 2 λ max = (2898 / 600000) μm λ max = 0.00483 μm = 4.83 nm c. Supernova: T = 100 billion K F = (5.67 × 10 −8 x (100 x 10 9 ) 4 ) W/m 2 F = 5.67 x 10 36 W/m 2 λ max = (2898 / (100 x 10 9 )) μm λ max = 2.898 x 10 -8 μm d. Earth’s atmosphere: T = 290 K F = (5.67 × 10 −8 x 290 4 ) W/m 2 F = 401.028 W/m 2 λ max = (2898 / 290) μm λ max = 9.993 μm 3. Calculate the effective equilibrium surface temperature and magnitude of the greenhouse effect (rise in temperature) for the following moons of Jupiter (Jupiter orbits the sun at roughly 5 times the distance of Earth, i.e. 5 AU ). (10 points) S J = S o ( ) 2 𝑟𝑜 𝑟 (Solar constant at Earth, S o = 1370 W/m 2 ) S J = 1370 x (1/5) 2 S J = 54.8 W/m 2 a. Callisto : Albedo, A = 0.22; Actual surface Temperature T S = 134 K T e = [(1 – 0.22) x (54.8 / 4 x 5.67 x 10 -8 )] 1/4 K T e = 117.167 K ΔT g = 134 – 117.167 = 16.833 K b. Europa : Albedo, A = 0.67; Actual surface Temperature T S = 102 K
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