SERIES AND PARALLEL CIRCUITS LAB

docx

School

ECPI University *

*We aren’t endorsed by this school

Course

120

Subject

Electrical Engineering

Date

Jan 9, 2024

Type

docx

Pages

Uploaded by JusticeEnergy11407

Name: Thi Huyen Trang Nguyen Date: 12/02/2023 SERIES AND PARALLEL CIRCUITS Introduction In today’s lab, you are going to investigate the characteristics of circuits with resistors in series and circuits with resistors in parallel. To investigate the characteristics, you are going to apply Ohm’s Law. Voltage (V) = Current (I) x Resistance (R) Purposes 1. To determine the equivalent resistance of resistors in series. 2. To determine the equivalent resistance of resistors in parallel. 3. To apply Ohm’s Law to simple circuits. Materials This lab requires you to create simulated circuits using the PhET Circuit Construction Kit Virtual Lab ( be sure you use the HTML5 version, not the Java version ). Part 1: Applying Ohm’s Law to a Simple Circuit Create the following simple circuit using the simulation. The simulation shows electrons flowing from the negative terminal of the battery (black end), through the resistor (light bulb) and the positive terminal (copper colored end). Change the current direction by selecting Conventional Current (in top right box). This shows the direction physicists thought current was flowing before the existence of the electron was discovered. 1

Name: Thi Huyen Trang Nguyen Date: 12/02/2023 Set the voltage and resistance in your circuit using the values in the table below that correspond to the first letter of your last name: First letter of Last Name Voltage Resistance A-C 5 V 5 Ω D-F 6 V 6 Ω G-I 7 V 7 Ω J-L 8 V 8 Ω M-O 9 V 9 Ω P-R 10 V 10 Ω S-U 11 V 11 Ω V-Z 12 V 12 Ω Change the setting on the battery and light bulb by clicking on the component and using the arrows and/or slider at the bottom of the simulation screen. Enter the values you are using in the table below: Voltage Resistance Current 9 V 9 Ω 1 A Using your assigned values of voltage (V) and resistance (R), use Ohm’s Law to calculate the current to demonstrate that the ammeter reading is correct. 9V/9Ohms = 1A Result of this calculation = 1 A Now double the voltage. Indicate the new values in the circuit in the following table: Voltage Resistance Current 18 V 9 Ω 2 A So when the voltage is doubled, the current is (put an X next to your choice) a ½ of what it was. b ¼ of what it was. c 4 times what it was. X d 2 times what it was. Do not change the voltage of the battery from the new value (listed above). Double the resistance. Indicate in the following table the values of the circuit after making the change. Voltage Resistance Current 9 V 18 Ω 0.5 A 2

Name: Thi Huyen Trang Nguyen Date: 12/02/2023 So when the resistance is doubled, the current is (put an X next to your choice) X a ½ of what it was. b ¼ of what it was. c 4 times what it was. d 2 times what it was. For part 2 and 3, set the battery voltage and the resistances in your circuit using the values in the table below that correspond to the first letter of your last name First letter of Last Name Voltage Resistance 1 Resistance 2 A-C 5 V 5 Ω 12Ω D-F 6 V 6 Ω 11Ω G-I 7 V 7 Ω 10Ω J-L 8 V 8 Ω 9Ω M-O 9 V 9 Ω 8Ω P-R 10 V 10 Ω 7Ω S-U 11 V 11 Ω 6Ω V-Z 12 V 12 Ω 5Ω Part 2: Resistors in Series In this part of the lab, you are going to create the following circuit with two resistors in series. . 3

Your preview ends here

Eager to read complete document? Join bartleby learn and gain access to the full version

Access to all documents
Unlimited textbook solutions
24/7 expert homework help

Name: Thi Huyen Trang Nguyen Date: 12/02/2023 The equivalent resistance of resistors in series is determined by adding all the resistor values. This is true because the current is the same flowing through each resistor. R eq = R 1 + R 2 Using the relationship for resistors in series, find the equivalent resistance in the circuit you’ve assembled and record in the table below: Resistor 1 Resistor 2 Equivalent Resistance 9 Ω 8 Ω 17 Ω Record the voltage and current of your circuit. Voltage Current 9 V 0.53 A Apply Ohm’s Law to your circuit to calculate the current to demonstrate that the ammeter reading is correct ( recall that now R is the equivalent resistance in the circuit ). 9V/17 Ohms = 0.53 A Result of this calculation = 0.53 A In a series circuit, the sum of the voltage drops across each resistor should equal the voltage of the battery. Using the voltmeter you will demonstrate that this is true for the circuit you’ve created. Record your results in the table below: R 1 Voltage R 2 Voltage Sum of R 1 + R 2 4

Name: Thi Huyen Trang Nguyen Date: 12/02/2023 4.76 4.24 9 Questions If you were to have three resistors in series, how would you determine the equivalent resistance of the circuit? The equivalent resistance of the circuit R= R 1 + R 2 + R 3 Make a statement regarding the voltage drop across each of the three resistors in your new circuit and how it would relate to the voltage of the battery. Each different resistor will have a different voltage drop. The higher resistance it has, the greater the voltage drop is. However, the sum of the voltage drops for all three resistors will equal the total voltage of the battery. Part 3: Resistors in Parallel In this part of the lab, you are going to explore the characteristics of a circuit with resistors in parallel. Use your assigned values for battery voltage and resistance to assemble the circuit shown below ( notice the use of additional ammeters ): In a parallel circuit, the voltage drops across each resistor should equal the voltage of the battery. Using the voltmeter you will demonstrate that this is true for the circuit you’ve created. Record your results in the table below: 5

Name: Thi Huyen Trang Nguyen Date: 12/02/2023 R 1 Voltage R 2 Voltage Battery Voltage 9 9 9 The current through each resistor is affected by the branching in the parallel circuit. In the table below, record the current coming out of the battery, the current going into each resistor and the current flowing back to the battery. Current Out of Battery Current to R 1 Current to R 2 Current Into Battery 2.12 1.0 1.12 2.12 Since the voltage across each resistor in a parallel circuit is the same, we approach finding the equivalent resistance from the sum of the currents. This gives the following relationship for calculating the equivalent resistance in a parallel circuit. 1 R eq = 1 R 1 + 1 R 2 Using the relationship for resistors in parallel, find the equivalent resistance in the circuit you’ve assembled and record in the table below: Resistor 1 Resistor 2 Equivalent Resistance 9 Ω 8 Ω 4.24 Ω Apply Ohm’s Law to your circuit to calculate the current to demonstrate that the ammeter reading is correct ( recall that now R is the equivalent resistance in the circuit ). 9V/4.24 Ohms = 2.12 A Result of this calculation = 2.12 A Questions If you were to have three resistors in parallel, how would you determine the equivalent resistance of the circuit? The equivalent resistance of the circuit: 6

Your preview ends here

Eager to read complete document? Join bartleby learn and gain access to the full version

Access to all documents
Unlimited textbook solutions
24/7 expert homework help

Name: Thi Huyen Trang Nguyen Date: 12/02/2023 1 R = 1 R 1 + 1 R 2 + 1 R 3 Make a statement regarding the voltage drop across each of the three resistors in your new circuit and how it would relate to the voltage of the battery. In a parallel circuit, the voltage drops across each of the three resistors is equal. Each resistor has the same voltage as the voltage of the battery. Make a statement regarding the current through each of the three resistors in your new circuit and how it would relate to the overall current. In a parallel circuit, the current through each different resistor will have a different value. The higher resistance it has, the lower the current is. However, the sum of the current for all three resistors will equal the overall current. 7

SERIES AND PARALLEL CIRCUITS LAB

Related Documents