H-Bridge simulation report
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Purdue University *
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Course
227
Subject
Electrical Engineering
Date
Apr 3, 2024
Type
Pages
4
Uploaded by CommodoreGazelle837
Aulden Boyd
ECET 227
Professor Nawrocki
Simulation 17 H-Bridge
1.
2.
This display verifies that the circuit is properly working with the current flowing left to right through the load. First, on probe 1, there is 1.56A flowing through it into the load, and on Probe 4 there is 1.56A flowing through the load into the probe to the ground. To verify no current is running through Q2 and Q3 look at probe 3 and probe 2 there is very little current running through Q2 and Q3 proving that the circuit is properly working. The V_left and V_right cause this behavior of the circuit by applying different voltages to the gates of the MOSFETs. V_left and V_right are set at 0V and 18V respectively. Applying 0V to Q1 turns it on allowing the 19V from VCC to flow into the load. Applying 0V to Q3 turns it off not allowing the voltage from VCC to flow to ground forcing the voltage from Q1 into the load. The 18V from V_right flows into Q4 turning it on allowing the voltage from the load to flow to ground. The 18V flowing from V_right into Q2 turns Q2 off not allowing the voltage from VCC to flow through it.
3.
Aulden Boyd
ECET 227
Professor Nawrocki
Simulation 17 H-Bridge
4.
This display verifies that the circuit is working properly flowing through the circuit from left to right through the load. First, Probe 2 is showing 1.56A flowing into the load from Q2. The current from Q2 flows through the load and into Q3, and this is shown by probe 3 reading 1.56A flowing through it. No current is flowing through Q1 and Q4 and this is shown by Probe 4 and Probe 1 reading almost no voltage flowing through them. The V_left and V_right cause this behavior of the circuit by applying different voltages to the gates of the MOSFETs. V_left and V_right are set at 18V and 0V respectively. Applying 0V to Q2 turns it on allowing the 19V from VCC to flow into the load. Applying 0V to Q4 turns it off not allowing the voltage from VCC to flow to ground forcing the voltage from Q2 into the load. The 18V from V_left flows into Q3 turning it on allowing the voltage from the load to flow to ground. The 18V flowing from V_left into Q1 turns it off not allowing the voltage from VCC to flow through it.
5.
Aulden Boyd
ECET 227
Professor Nawrocki
Simulation 17 H-Bridge
6.
7.
A. In the first simulation, the motor would be spinning slowly in one direction. In the second simulation, the motor would reverse direction.
B. To stop the motor turning the input duty cycle would have to be 50%. The waveform would be on 50% of the time and off 50% of the time. The voltage would be exactly half of the 18V so 9V.
C. The duty cycle would have to be changed to 25% to make the motor spin counterclockwise at 50% speed.
D. The light would get brighter, but no other change would happen.
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Aulden Boyd
ECET 227
Professor Nawrocki
Simulation 17 H-Bridge
E. In step B2 the LED would light up as normal, but in step B3 the led would not light due to the reverse direction of the diode.
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