ohms law

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School

Florida Agricultural and Mechanical University *

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Course

2048L

Subject

Electrical Engineering

Date

Apr 3, 2024

Type

docx

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4

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Ohm's Law Written by: Sevaughn Clarington Partners: Jeniya Strobridge Jayme Colbert-Williams Due: February 19th, 2024
Abstract: This experiment served to calculate the Ohms by measuring the value of voltage and amperes throughout eight trials. The ohms were calculated using two equations.The first equation was voltage divided by amperes, and the second equation was the rise over run for the slope. The first equation resulted in R= 2.7175, and the second equation resulted in R= 2.66. Introduction: In this lab, we're exploring the basic principles of electrical resistance discovered by Ohm. Ohm found that when voltage changes across a resistor, the current through it changes, too. Ohm's groundbreaking discovery revealed that in a resistor, the current (I) flowing through it is directly proportional to the voltage (V) applied across it, while inversely proportional to the resistance (R), expressed mathematically as I = V/R. By conducting experiments with different resistors, we will investigate the relationship between current and voltage in Ohmic and non-Ohmic materials. Theory: In this experiment, the constant resistance (Ohms) was calculated by measuring the voltage and amperes throughout eight trials. Ohms was and calculated by this equation: (1) R= V/A. This equation translates to: Ohms is equal to voltage divided by amperes. The equation to find Ohms from slope is: (2) R= y/x. This translates to Ohms is equal to voltage 1 minus voltage 2, divided by ampere 1 minus ampere 2. Procedure: Using the diagram of the circuits, the assembly was made. The rheostat was adjusted to get the current on the voltameter at a minimum and the voltage and current. The rheostat was then adjusted to 50 mA and the voltage along with the current was recorded. Step three was then repeated for a total of eight times to get eight readings. The power supply was then turned off and the circuit disassembled. R x = V/I was then calculated for each trial (with error estimate) to find the average value of R x for all the trials. With the data gathered from the last step V vs. I was plotted and R x (with an error estimate) was found from the slope of the graph.
Results: Trial# Current Voltage R 1 0.1 0.15 1.5 2 0.1 0.3 3 3 0.2 0.5 2.5 4 0.25 0.7 2.8 5 0.3 0.9 3 6 0.35 1.1 3.14 7 0.4 1.2 3 8 0.5 1.4 2.8 Average R= 2.7175 Slope: y=3.1161x-0.0757
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Discussion: As a result, we calculated 2.7175 as the average Ohms after eight trials. The result of the Ohms calculated through slope was 3.1161x-0.0757. These results are close, with small uncertainty. There is a possibility of a systematic error, such as misreading either the voltage or ampere measurement. However, it would not affect the results drastically. Conclusion: In summary, this lab improved our comprehension of the fundamental differences between ohmic and non-ohmic materials as well as the connections between current, resistance, and voltage. We were able to obtain varied voltages and currents, observe our findings, and create graphs by applying a potential difference. Questions : 1. Compare the resistance, R x , found as an average value to the R x from the slope of the graph. - The resistance, R x was 2.7175 and the average value to the R x from the slope of the graph was 3.1161x-0.0757. 2. Does the resistor have a constant resistance? Why or why not? - Since the average and slope aren’t equal, the resistor didn’t have a constant resistance.