Week 5 2

Question 2 1/ 1 point There is no prior information about the proportion of Americans who support Medicare-for-all in 2019. If we want to estimate 95% confidence interval for the true proportion of Americans who support Medicare- for-all in 2019 with a 0.3 margin of error, how many randomly selected Americans must be surveyed? Answer: (Round up your answer to nearest whole number) There is no prior information about the proportion of Americans who support Medicare-for-all in 2019. If we want to estimate 95% confidence interval for the true proportion of Americans who support Medicare-for-all in 2019 with a 0.3 margin of error, how many randomly selected Americans must be surveyed? Answer: (Round up your answer to nearest whole number) 11 v »» Hide question 2 feedback Z-Critical Value = NORM.S.INV(.975) = 1.96 p*q*Z2 ME? 5% .5%1.962 .32 Z-Critical Value = NORM.S.INV(.975) = 1.96 = I pxqx 2> ME? 5% .5%1.962 .32