WS4Homework_fareed

xlsx

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Indiana Wesleyan University, Cleveland *

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ORGANIZATI

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Economics

Date

Feb 20, 2024

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xlsx

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Uploaded by BailiffScorpionMaster1953

Z Test of Hypothesis for the Proportion Data 0.795 Level of Significance 0.05 Number of Items of Interest 44 Sample Size 48 Intermediate Calculations Sample Proportion 0.9167 Standard Error 0.0583 Z Test Statistic 2.0880 Two-Tail Test Lower Critical Value -1.9600 Upper Critical value 1.9600 0.0368 Reject the null hypothesis Lower-Tail Test Lower Critical Value -1.6449 0.9816 Do not reject the null hypothesis Upper-Tail Test Upper Critical Value 1.6449 0.0184 Reject the null hypothesis Null Hypothesis p = p -Value p -Value p -Value

DIRECTIONS: Arrival Delay -32 -25 Enter the hypothesis test amount. (1 point) -26 Enter alpha value. (1 point) -6 Enter how many flights were on time. (1 point) 5 Enter the sample size. (1 point) -15 -17 -36 Access this helpful video: -29 -18 -12 State the results and interpret the results here: -35 ( 4 points) 2 -33 -5 0 0 -1 -33 -5 -14 -39 -21 -32 -5 -32 -13 -9 -19 49 -30 -23 14 -21 -32 11 -23 28 103 -19 -5 -46 13 On time flights. A flight is on time if it arrives no later than 15 minutes after the scheduled arrival time. Test the claim that made by CNN that 79.5% of flights are on time. Use a .05 significance level. Video Two-tail is rejected as th p-value is less than the level of significance and the Z test statistic does not fall within the upper or lower critical value. These 2 sections are not needed in this problem because it is an equality test with 2 tails.

-3 13 106 -34 -24

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(negatives mean it arrived early) How many flights are in this sample? 48 (1 point) How many flights were on time? 44 (1 point)

t Test for the Hypothesis of the Mean Data 0.986 Level of Significance 0.05 Sample Size 106 Sample Mean 98.2 Sample Standard Deviation 0.6229 Intermediate Calculations Standard Error of the Mean 0.0605 Degrees of Freedom 105 1606.8150 Two-Tail Test Lower Critical Value -1.9828 Upper Critical Value 1.9828 0.0000 Reject the null hypothesis Calculations Area For one-tailed tests: TDIST value 1.19E-232 1-TDIST value 1 Lower-Tail Test Lower Critical Value -1.6595 1.0000 Do not reject the null hypothesis Upper-Tail Test Upper Critical Value 1.6595 0.0000 Reject the null hypothesis Null Hypothesis m = t Test Statistic p -Value p -Value p -Value

DIRECTIONS: TEMP in F 98.6 98.6 Enter the hypothesis test amount. (1 point) 98 Enter alpha value. (1 point) 98 Enter the sample size. (1 point) 99 Enter the sample mean. (1 point) 98.4 Enter the sample standard deviation. (1 point) 98.4 98.4 Access this helpful video: 98.4 98.6 98.6 State the results and interpret the results here: 98.8 ( 3 points) 98.6 97 97 98.8 97.6 97.7 98.8 98 98 98.3 98.5 97.3 98.7 97.4 98.9 98.6 99.5 97.5 97.3 97.6 98.2 99.6 98.7 99.4 98.2 98 98.6 98.6 97.2 98.4 98.6 98.2 Calculate sample mean and standard deviation from sample data. Test the claim that mean body temperature of the population is 98.6 degrees as is commonly believed. Video The rejection of the null hypothesis in the two-tail test is warranted due to the observation that the p-value is lower than the specified level of significance, set at 0.05. These 2 sections are not needed in this problem because it is an equality test with 2 tails.

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98 97.8 98 98.4 98.6 98.6 97.8 99 96.5 97.6 98 96.9 97.6 97.1 97.9 98.4 97.3 98 97.5 97.6 98.2 98.5 98.8 98.7 97.8 98 97.1 97.4 99.4 98.4 98.6 98.4 98.5 98.6 98.3 98.7 98.8 99.1 98.6 97.9 98.8 98 98.7 98.5 98.9 98.4 98.6 97.1 97.9 98.8 98.7 97.6 98.2

99.2 97.8 98 98.4 97.8 98.4 97.4 98 97

What is the mean temperature? 98.2 (1 point) What is the standard deviation? 0.6200 (1 point)

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t Test for the Hypothesis of the Mean Data 12 Level of Significance 0.01 Sample Size 48 Sample Mean 10.46 Sample Standard Deviation 30.81 Intermediate Calculations Standard Error of the Mean 4.4475 Degrees of Freedom 47 -0.3466 Two-Tail Test Lower Critical Value -2.6846 Upper Critical Value 2.6846 0.7304 Do not reject the null hypothesis Calculations Area For one-tailed tests: TDIST value 0.36520524 1-TDIST value 0.63479476 Lower-Tail Test Lower Critical Value -2.4083 0.3652 Do not reject the null hypothesis Upper-Tail Test Upper Critical Value 2.4083 0.6348 Do not reject the null hypothesis Null Hypothesis m = t Test Statistic p -Value p -Value p -Value

DIRECTIONS: Departure Delay -2 -1 Enter the hypothesis test amount. (1 point) -2 Enter alpha value. (1 point) 2 Enter the sample size. (1 point) -2 Enter the sample mean. (1 point) 0 Enter the sample standard deviation. (1 point) -2 -3 -5 Access this helpful video: -4 2 -2 22 -11 7 0 -5 3 -8 8 -2 -8 State the results and interpret the results here: -3 -4 ( 2 points) 19 -4 -5 -1 -4 73 0 1 13 -1 -8 32 18 60 142 -1 -11 -1 On time flights. A flight is on time if it arrives no later than 15 minutes after the scheduled arrival time. Test the claim that the mean departure delay time for all flights is less than 12.0 minutes. Use .01 level of significance. Video This section is not needed in this problem because it is a lower tail test with 1 tail. alternative hypothesis is embraced as the p-value surpasses both the lower-critical value and the predetermined level of significance. The objective of the test is to assess flights with departure delays less than 12 minutes, and the lower test tail illustrates the values falling within the examined margin. Consequently, the statistical analysis indicates support for the claim that the mean departure delay time for all flights is less than 12.0 minutes. This section is not needed in this problem because it is a lower tail test with 1 tail.

47 13 12 123 1 4

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(negatives mean it arrived early) How many flights are in this sample? 48 (1 point) What is the mean? 10.46 (1 point) What is the standard deviation? 30.49 (1 point)

t Test for the Hypothesis of the Mean Data 1100 Level of Significance 0.05 Sample Size 10 Sample Mean 1130.20 Sample Standard Deviation 117.45 Intermediate Calculations Standard Error of the Mean 37.1402 Degrees of Freedom 9 0.8131 Two-Tail Test Lower Critical Value -2.2622 Upper Critical Value 2.2622 0.4371 Do not reject the null hypothesis Calculations Area For one-tailed tests: TDIST value 0.21856112 1-TDIST value 0.78143888 Lower-Tail Test Lower Critical Value -1.8331 0.7814 Do not reject the null hypothesis Upper-Tail Test Upper Critical Value 1.8331 0.2186 Do not reject the null hypothesis Null Hypothesis m = t Test Statistic p -Value p -Value p -Value

DIRECTIONS: Brain Volume 963 1027 Enter the hypothesis test amount. (1 point) 1272 Enter alpha value. (1 point) 1079 Enter the sample size. (1 point) 1070 Enter the sample mean. (1 point) 1173 Enter the sample standard deviation. (1 point) 1067 1347 1100 Access this helpful video: 1204 State the results and interpret the results here: ( 2 points) Brain volume. Test the claim that the mean brain volume for the population is equal to 1100 cm 2 . Video The null hypothesis is retained as the p-value in the two-tailed test falls within the range defined by the upper and lower categories. Additionally, the observed p-value surpasses the predetermined level of significance. This section is not needed in this problem because it is a 2-tail test. This section is not needed in this problem because it is a 2-tail test.

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(negatives mean it arrived early) How many readings are in this sample? 10 (1 point) What is the mean? 1130.20 (1 point) What is the standard deviation? 111.42 (1 point)

t Test for the Hypothesis of the Mean Data 120 Level of Significance 0.0500 Sample Size 40 Sample Mean 118.5000 Sample Standard Deviation 22.3893 Intermediate Calculations Standard Error of the Mean 3.5401 Degrees of Freedom 39 -0.4237 Two-Tail Test Lower Critical Value -2.0227 Upper Critical Value 2.0227 0.6741 Do not reject the null hypothesis Calculations Area For one-tailed tests: TDIST value 0.33704853 1-TDIST value 0.66295147 Lower-Tail Test Lower Critical Value -1.6849 0.3370 Do not reject the null hypothesis Upper-Tail Test Upper Critical Value 1.6849 0.6630 Do not reject the null hypothesis Null Hypothesis m = t Test Statistic p -Value p -Value p -Value

DIRECTIONS: Systolic blood pressure 122 120 Enter the hypothesis test amount. (1 point) 90 Enter alpha value. (1 point) 150 Enter the sample size. (1 point) 132 Enter the sample mean. (1 point) 88 Enter the sample standard deviation. (1 point) 100 114 94 Access this helpful video: 100 110 188 106 130 126 90 168 110 98 112 116 128 State the results and interpret the results here: 116 112 ( 2 points) 126 94 120 94 120 148 126 126 112 120 110 98 130 114 174 108 Blood pressure. Test the claim that the mean female population systolic blood pressure level is less than 120 mm Hg. Use a .05 level of significance. Video This section is not needed in this problem because it is a lower tail test with 1 tail. Lower-tail testing is accepted because the p-value is greater than the level of signficance. The alternative hypothesis is accepted, p-value is greater than the lower-critical value and level of signficance. The lower tail test is looking for values of female blood pressure less than 120 mm hg, concluding a greater level of significance based upon the p-value. This section is not needed in this problem because it is a lower tail test with 1 tail.

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(negatives mean it arrived early) How many readings are in this sample? 40 (1 point) What is the mean? 118.50 (1 point) What is the standard deviation? 22.1077 (1 point)

t Test for the Hypothesis of the Mean Data 120 Level of Significance 0.01 Sample Size 40 Sample Mean 123.7 Sample Standard Deviation 0.2404 Intermediate Calculations Standard Error of the Mean 0.0380 Degrees of Freedom 39 96.3578 Two-Tail Test Lower Critical Value -2.7079 Upper Critical Value 2.7079 0.0000 Reject the null hypothesis Calculations Area For one-tailed tests: TDIST value 2.6432E-48 1-TDIST value 1 Lower-Tail Test Lower Critical Value -2.4258 1.0000 Do not reject the null hypothesis Upper-Tail Test Upper Critical Value 2.4258 0.0000 Reject the null hypothesis Null Hypothesis m = t Test Statistic p -Value p -Value p -Value

DIRECTIONS: Voltage 123.8 123.9 Enter the hypothesis test amount. (1 point) 123.9 Enter alpha value. (1 point) 123.3 Enter the sample size. (1 point) 123.4 Enter the sample mean. (1 point) 123.3 Enter the sample standard deviation. (1 point) 123.3 123.6 123.5 Access this helpful video: 123.5 123.5 123.7 State the results and interpret the results here: 123.6 123.7 ( 2 points) 123.9 124.0 124.2 123.9 123.8 123.8 124.0 123.9 123.6 123.5 123.4 123.4 123.4 123.4 123.3 123.3 123.5 123.6 123.8 123.9 123.9 123.8 123.9 123.7 123.8 123.8 Voltage. Test the claim that the mean voltage is 120 volts. Use .01 level of significance. Video The null hypothesis is rejected in the two-tail test since the p-value falls below the specified level of significance of 0.01. This section is not needed in this problem because it is a 2-tail test. This section is not needed in this problem because it is a 2-tail test.

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(negatives mean it arrived early) How many readings are in this sample? 40 (1 point) What is the mean? 123.66 (1 point) What is the standard deviation? 0.24 (1 point)

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WS4Homework_fareed

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