Motor Behaviour Lab Assignment 1 - Reaction Time and Error
.pdf
keyboard_arrow_up
School
University of Toronto *
*We aren’t endorsed by this school
Course
162
Subject
Chemistry
Date
Dec 6, 2023
Type
Pages
6
Uploaded by KidSwan3984
Reaction Time and Information Processing Efficiency Lab
Results
Record your mean RT values in the table below and then determine the durations of the
information processing stages of perception and response selection. (3 marks)
Table 1: Mean RTs For Each Condition
Condition
Mean RT (ms)
Simple RT
342.3
Choice RT
429.4
Go/no-go RT
420.7
Table 2: Data Processing For Perception and Response Selection Duration
Information Processing Stage
Calculation
Duration (ms)
Perception
= (Go/no-go RT – Simple RT)
= (420.7 ms - 342.3 ms)
78.4 ms
Response Selection
= (Choice RT – Go/no-go RT)
= (429.4 ms - 420.7 ms)
8.7 ms
Questions
1) Name the 3 main stages of information processing. Briefly discuss (1-2 sentences) what
occurs during each of these stages. (3 marks)
The three main stages of information processing are: stimulus identification (sensation and
perception), response selection (decision making), and response programming (action
planning).
2) Outline the logic of the method used here to determine the duration (efficiency) of a
processing stage. (2 marks)
The methodology isolated the duration of each processing stage by creating a set of conditions
that omit certain stages of information processing. The Simple RT attempted to omit the
response selection stage by only providing a single possible response. One can then determine
the duration of a specific processing stage by subtracting the condition with fewer stages from a
condition with the same stages, plus an additional stage. This difference is the additional time
that the additional stage added to the reaction process, thus determining the duration of a
specific processing stage.
3) What is the difference between sensation and perception? How are these two processes
distinguished between the Go/no-go RT and Simple RT tasks? What is the duration of
perception in your task performance? (3 marks)
The difference is that sensation involves sensing the existence of stimuli, while perception
involves the determination of what a stimulus is. This is reflected in the two RT tasks, where the
Simple RT task involves the sensing of the stimuli (i.e. the presence of a colored circle), and the
Go/no-go RT task requires the perception of the color of the circles. The duration of perception
in my task performance was 78.4 ms.
4) How are response selection processes distinguished between the Go/no-go RT and Choice
RT tasks? What is the duration of response selection in your task performance? (2 marks)
In the Go/no-go RT task, response selection is minimized because there is only one possible
reaction. After the perception stage of distinguishing between red and green, there is only one
possible action to be made if the circle is green. On the other hand, in the Choice RT task, after
the perception stage, there were two possible choices to be made of either pressing M or Z. The
duration of response selection in my task performance was 8.7 ms.
5) Why is it important that an “unanticipated” stimulus is used in these tasks? (1 mark)
An anticipated stimulus would add additional processes prior to the stages of sensation and
perception. Furthermore, it would provide additional time to complete the stages of response
selection and response programming before the stimulus is even given. An example of an
anticipated stimulus could be the counting down of a F1 race, where all response selection and
response programming is complete and the driver knows to go when the light turns green.
Thus, an anticipated stimulus would be unable to provide data regarding the information
processing stages of response.
6) Why is response selection not involved in the Simple RT task? (1 mark)
There was only one possible response to the visual stimulus, therefore response selection was
not involved in completing the Simple RT task.
Table 1: “Full Vision” Condition (Visible Square)
Trial
Target
X-Position
Target
Y-Position
Performance
X-Position
Performance
Y-Position
Constant Error
in X-position
Absolute Error
in
X-position
Difference in
Y-position
Difference
2
1
338
300
387
304
-1
1
4
16
2
446
300
448
304
2
2
4
16
3
740
300
737
304
-3
3
4
16
4
420
300
417
301
-3
3
1
1
5
78
300
76
304
-2
2
4
16
6
549
300
550
299
1
1
1
1
7
232
300
235
297
3
3
3
9
8
701
300
698
301
-3
3
1
1
Mean
438
300
443.5
301.75
-0.8
2.2
2.8
Sum
76
Sum/n
9.5
Sqrt
3.1
Table 2: “No Target” Condition (Disappearing Square)
Trial
Target
X-Position
Target
Y-Position
Performance
X-Position
Performance
Y-Position
Constant Error
in X-position
Absolute Error
in
X-position
Difference in
Y-position
Difference
2
1
638
300
641
293
3
3
7
49
2
501
300
503
299
2
2
1
1
3
499
300
509
297
10
10
3
9
4
208
300
216
300
8
8
0
0
5
663
300
700
305
37
37
5
25
6
697
300
670
296
-27
27
4
16
7
235
300
260
292
25
25
8
64
8
203
300
226
292
23
23
8
64
Mean
455.5
300
465.6
296.8
10.12
16.9
4.5
Sum
228
Sum/n
28.5
Sqrt
5.3
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
Related Questions
What is the purpose of a calibration curve in analytical chemistry?
arrow_forward
analyte
concentration(C)(mg/ml)
injection volume (ul)
elution time (time)
peak DAD signal(mAU)
caffeine
1
1
4.67
302.85
aspartame
5
1
7.53
15.83
benzoic acid
1
1
8.14
89.98
saccharin
1
1
1.91
84.86
mixture(add everything above with 1:1:1:1 ratio)
1
4.47
69.58
How to get the concentration of the mixture in this case?
arrow_forward
Sample
10 ppt
20 ppt
35 ppt
Temperature
(C)
22.1
22.1
22.1
Measured
Density (g cm¹³)
1.005
1.014
1.024
Theoretical
Density (g cm¹³)
Type response
Type response
Type response
arrow_forward
1-arr
In a study of the gas phase decomposition of phosphine at 120 °C
PH3(g)-
→1/4 P4(g) + 3/2 H2(g)
the concentration of PH3 was followed as a function of time.
It was found that a graph of In[PH3] versus time in seconds gave a straight line with a slope of -2.50×10² s1 and a y-intercept of -3.24.
Based on this plot, the reaction i v
O order in PH, and the half life for the reaction is
seconds.
zero
first
second
arrow_forward
In your own words and in no more than three sentences, briefly discuss the two methods of how AH reaction can be calculated
For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac).
BIUS
Paragraph
Arial
10pt
END
arrow_forward
Which of the following describes a gradient elution process?
stationary phase has varying concentration
stationary phase has static concentration
mobile phase has varying concentration
mobile phase has static concentration
arrow_forward
In a particular trial, a student got a value for R of 0.085. Calculate the percent deviation of this result. Enter a number without the % sign. The percent deviation should be reported as a positive value.
(R accepted 0.082006)
arrow_forward
Descriptives
Bronchial reactivity
95% Confidence Interval for
Mean
Mean
Std. Deviation
Std. Error
Lower Bound Upper Bound
Minimum
Maximum
Sulfur dioxide
6.806
5
18.840
9.6919
4.3344
30.874
5.1
30.1
Nitrous dioxide
6
6.617
3.9448
1.6105
2.477
10.757
2.2
11.9
Oxygen
4
4.975
3.4092
1.7046
-450
10.400
2.1
9.3
Total
15
10.253
8.6514
2.2338
5.462
15.044
2.1
30.1
ANOVA
Bronchial reactivity
Sum of
Squares
dr
Mean Square
F
Sig.
Between Groups
559.450
2
279.725
6.873
.010
Within Groups
488.408
12
40.701
Total
1047.857
14
arrow_forward
6) What is the difference between CI-MS and EI-MS?
What is CI and EI ?
arrow_forward
You are interested to know the Q10 value for mean heart rate (# of beats/10 sec) for a species of crab for the
temperature interval of 25°C - 35°C. To find this value, you collect data for these six temperatures and calculate mean
heart rate (# of beats/10 sec) for each temperature. Here is the data:
10°C
15°C
20°C
25°C
30°C
35°C
Mean Heart Rate (#
23.67
23.89
24.33
27
35.89
37.78
beats/10 sec)
What is the Q1o value for heart rate (# of beats/10 seconds) for the temperature interval of 25°C - 35°C? Round your
answer to two decimal places.
arrow_forward
THE Y-INTERCEPT FOR THE FOLLOWING GRAPH IS:
-35.0
In K#
-10749
-27
-35.2
-35.4
-35.6
-35.8
-36.0
-36.2
7.4
In K = -AH/RT+AS*/R
In K* = -10,749/T-27
R² = 0.974
7.6 7.8
974
NOT ENOUGH INFORMATION
8.2
8.0
(1/7)/10-4K-1
8.4 8.6
arrow_forward
Trial Conc. A (M) Conc. B (M) Rate
97.943
1
0.313
0.661
0.313
0.626
195.887
783.548
1.322
0.661
4
0.855
0.914
Given the information in the table above provide the following:
Order for A
Order for B
Overall order
The rate for Trial 4
Round all answers to the nearest whole number"
arrow_forward
What is instrumental analysis in chemistry?
arrow_forward
ESF X
empt/quiz_start_frame_auto.d21?ou=9739790&isprv=&qi=11007766&cfql=0&dnb=0&fromQB=0&inProgress=1
ystems
Question 5 (1 point)
Ben starts walking along a path at 3 mi hr¹. Amanda starts jogging along the same path 1 hour later at 5 mi hr. After how much
time jogging does Amanda catch up to Ben?
3.5 hr
2.5 hr
2 hr
16
arrow_forward
Use the calibration curve or linear regression equation to determine the concentration of
FD&C blue dye No. 1 in Kool-aid.
Food Coloring is 0.026 M in FD&C blue dye No. 1
7.5 x 10 -5 M is 29 mL -> 1000 mL
arrow_forward
The spectroscopic data in the table is generated with five solutions of known concentration.
Concentration (M)
0.0133
m=
0.0266
0.0532
0.106
0.213
Absorbance
0.1271
What is the intercept of the linear regression line?
0.08531
0.5388
1.069
Use a spreadsheet program, such as Microsoft Excel, to graph the data points and determine the equation of the best-fit line.
1.954
What is the slope of the linear regression line formed by these points?
M-1
arrow_forward
B Quizzes - SCH3UE-15-Chemistry- X
+
A tdsb.elearningontario.ca/d2l/Ims/quizzing/user/attempt/quiz_start_frame_auto.d2l?ou=19297865&isprv=&drc=1&qi=5956344&cfql=0&dnb=D0... 2
E TDSB Bookmarks
P Summary - PayPal
Steam Guard Mobil..
M Booter Panel ul Asylum Stresser - H..
A Free Stresser - The.
6 Str3ssed Booter - L.
O Home | IP Stresser 3 - Packages
>>
What can be added to a solution containing Sr2*(aq) ions to precipitate the ions from
the solution?
potassium sulfate
barium hydroxide
O lithium nitrate
Two of the above are correct.
(a). (b), and (c) are all correct.
围
i 11:15
arrow_forward
Molar concentration of the dye stock solution: 2.52e-5 mol/L
Operating Wavelength: 630 nm
Solutions(Dilutions)
Absorbance (A)(a.u.)
1
0.073
2
0.118
3
0.258
4
0.477
Using linear regression determine the absorbance/concentration relationship for the dye.
[dye] =_____ x A
arrow_forward
B Quizzes - SCH3UE-15-Chemistry- X
+
A tdsb.elearningontario.ca/d2l/Ims/quizzing/user/attempt/quiz_start_frame_auto.d2l?ou=19297865&isprv=&drc=1&qi=5956344&cfql=0&dnb=D0... 2
E TDSB Bookmarks
P Summary - PayPal
Steam Guard Mobil.
Booter Panel l Asylum Stresser - H.
A Free Stresser - The.
O Str3ssed Booter - .
O Home | IP Stresser 3 - Packages
>>
In testing for the presence of lead(II) ions in solution, Jamaal adds a solution of
sodium nitrate. What will be the conclusion of the test if no precipitate forms?
Lead(II) ions are not present in solution.
Lead(II) ions are present in the solution.
Lead(II) ions are present, but in a very small concentration.
More sodium nitrate solution needs to be added before a conclusion can be
made.
No conclusion can be made in this test.
围
1 11:14
arrow_forward
Q3-B) Determine the break point dosage of chlorine given the data below in table which was obtained from
experiment. What is the contact time required for chlorine to kill 99.9% from microorganisms?
Dosage (mg/L)
1
Residual Cl₂ (mg/L) 0.2
2
0.45
3
1.05
4
5
2.75 4.5
6
7
5.15 6.03
arrow_forward
Enzyme activity (Effect of temperature)
Research Question
How does temperature affect the activity
of the enzyme catalase?
Hypothesis
The higher temperature would increase
Catalase activity, leading to a faster reaction.
Temp (degrees Trial!
4
5.85
3.06
10
22
Ho
Results
Time to float disc
65t
4.00
1/29/24 Mini Lab #1
10.49
9.43
Trial a
5.70
2.86
5.26
7.86
11.36
Average
5.775
2.96
4.63
9.175
10.395
Rate
Class
average
arrow_forward
what is the concentration of the unknown sample using serial diluitions: 0.05M 1.7472nm, 0.025M 0.8569nm, 0.0125M 0.4167nm, 0.00625M 0.1958nm the epsilon value is 0.0101 and l is 1 cm
arrow_forward
Write the mass-action expression,
Qc, for the following chemical
reaction equations:
15
1)
CaCO3(s) CaO(s) +
CO2(g)
2)
CH4(g) + 202(g) CO2(g)
+ 2H20(1)
3) AgCI(s)
Ag* (aq) + Cl"
く->
(aq)
4)
Zn(s) + Cu2*(aq)
Zn2+
(aq) + Cu(s)
arrow_forward
B Quizzes - SCH3UE-15-Chemistry- X
+
A tdsb.elearningontario.ca/d21/Ims/quizzing/user/attempt/quiz_start_frame_auto.d2l?ou=19297865&isprv=&drc=1&qi=5956344&cfql=0&dnb=D0..
E TDSB Bookmarks
• Summary - PayPal
Steam Guard Mobil..
Booter Panel l Asylum Stresser - H..
A Free Stresser - The.
O Str3ssed Booter - L.
O Home | IP Stresser 3 - Packages
>>
What is the main difference between a qualitative analysis and a quantitative
analysis of a solution?
The two must be done independently of each other, as they are completely
unlike.
A qualitative analysis must always be done before a quantitative analysis.
A quantitative analysis must always be done before a qualitative analysis.
A qualitative analysis identifies the type of ion in solution and the quantitative
analysis will determine how much of this ion is present.
A quantitative analysis identifies the type of ion in solution and the qualitative
analysis will determine how much of this ion is present.
i 11:15
arrow_forward
Aime
Dater
Page No.
- lag (2x1)+log141
2X10
me
[4]
arrow_forward
Part A: Basic Laboratory Operations
Density of a Solid
TRIAL 1
TRIAL 2
Mass of solid (g)
19.761 g
19.763 g
Volume of water (cm³)
75.0 cm^3
75.0 cm^3
Volume of water and solid (cm³)
78.0 cm^3
78.0 cm ^3
Volume of solid (cm³)
3.0 cm^3
3.0 cm^3
Density of solid (g/cm³)
7.0 g / cm^3
7.0 g / cm^3
Average density of solid (g/cm³)
7.0 g / cm^3
Identity of solid
Zinc metal [Density =
7.133 g/cm^3]
1.
Density of Zinc: Consider the data and results from the density of zinc determination. Now
focus on the average absolute error associated with the calculated average density of
zinc. Which measurement contributes the most relative error to this value? Given that
measurement and its associated absolute error, is the calculated average absolute error
reasonable and why? What aspect of the experiment limited the measurements the most?
arrow_forward
Continued...
5.
Answer ALL parts of this question
The stability of chloramphenicol in eye drops is being
studied at different temperatures and times. The
concentration (in mg/L) of chloramphenicol at three
different temperatures over time is provided below.
Time (day)
-18°C
25°C
40°C
25
28
23
7
27
20
20
30
20
21
20
180
23
25
19
(a) Using the data in the tables below assess and
explain if the reaction time (after 1 hour of the
start of the reaction) was an important factor
affecting the yield of the reaction and provide the
null hypothesis of the statistical test carried out.
(b) The amount of chloramphenicol at -18 °C seems
to vary with some values appearing to be higher
than others. Explain what may be causing this
variation AND suggest a methodology to identify
if there was a systematic error in the
measurement.
||
arrow_forward
I 596420-7 x
The impo X IG what ma X
H PAP Cher X
Qchapter
x
ぐ
->
b ar-2903012.agilixbuzz.com/student/135113422/activity/9ff34d34-df47-4fas022
Mastery Assess It 7
PAP Chemistry-2903012-42100P-1/ Stoichiometry/Lesson 107
12. The combustion of glucose is represented by the following balanced equation: CGH12O6+6 0, 6 H20+6CO2.
Which reactant is the limiting reagent if there is 1 gram of both 0, Hy06 and 0,7
O a. CgHy06
O b. H20
O c. 0,
Od. CO,
arrow_forward
MindTap-Cengage Learning X
ISBN 9781305657571&nbld=3576712&snapshotld-3576712&id=1854206...
A
M
req
req
O
Search
X
Back
2310 g x
My Grades-Fall 2023 TTU Introd X
A
Submit Answer
References
237 g
Use the References to access important values if needed for this question.
A copy of your chemistry textbook is found to have a mass of 2310 grams.
Using unit analysis, show what the mass of this copy of your chemistry textbook is in
ounces.
12 oz
7. Unit Conversion: Metric/Standard: This is group attempt 1 of 5
Autosaved at 11:14 PM
Oz
Drag and drop your selection from the following list to complete the answer:
28.3 g
2.20 lb
+
()
16 oz
Q Search this course
454 g
Next
4x
X
C
11:14
10/8/2
arrow_forward
Drowser
Time Limit: 0:20:00
Time Left:0:15:19
Glenton Morris: Attempt 1
160
40
3.0
Page 1:
140 -
35
3.0
120
10
25
100
2.0
80
60
Z 10
Page 2:
05-
20
0
2.
Time is 10
Timetsk 10
Page 3:
Of all the graphs shown above, what plot type is correctly represented?
O second order
Page 4:
O no plot shown is valid
4.
1st order
3rd order
OL X (W) FON
arrow_forward
Data Collection
Kinetic Data Collection
Time, t (s)
Volume of added base (mL)
First addition
40
0.50
Second addition
101
1.00
Third addition
160
1.52
Fourth addition
224
1.99
Fifth addition
278
2.49
Sixth addition
334
3.01
Seventh additlon
389
3.48
Calculations
Concentration of NaOH stock solution:
0.01 M
Concentration of t-BuCl stock solution:
0.2 M
Volume of t-BuCl solution:
10 mL stock stock solution added to 25 mL acetone
Table view
List view
Kinetic Data
Volume of
Moles of Amount of
t-Bucl
(mol)
[-Buc]
In[-BuC
Time, t (s) added base added base
(mL)
(mol)
First
addition
40
0.50
Second
additlon
101
1.00
Third
addition
160
1.52
Fourth
addition
224
1.99
Flfth
additlon
278
2.49
Sixth
additlon
334
3.01
Seventh
addition
389
3.48
Use the data in the table above to plot In[t-BuC]]; vs time (s). Include labelled axis, a title, and a
linear trendline. Upload your plot here.
arrow_forward
The concentration of CH3NC was measured at a constant time interval of every 10 seconds over a 5.00 minute period for the isomerization of acetonitrile.
CH3CN(g) --> CH3CN(g)
The plot of ln[CH3NC] versus time in seconds produced the linear regression equation:
y= -6.3x10-3(x) - 1.366
How much time does it take to reach 50% of the initial concentraion for this reaction?
a.) 217 s
b.) 150 s
c.) 20.2 s
d.) 110 s
arrow_forward
Time(min) Concentration
(ug/L)
1,5
LO
5
7
3
10
20
6,24652317
2,807426345
2,281033905
1,68445587
0,947506391
0,386021122
help me calculate : kel, t1/2, AUC, CLtot and
Vd
arrow_forward
use analytical separation and analyses to outline analytical separation method protocols that can be employed to recover extremely high deposit of heavy metals and particulate matter in the river making wholesome for drinking in illegal mining communities .
arrow_forward
SEE MORE QUESTIONS
Recommended textbooks for you
Related Questions
- What is the purpose of a calibration curve in analytical chemistry?arrow_forwardanalyte concentration(C)(mg/ml) injection volume (ul) elution time (time) peak DAD signal(mAU) caffeine 1 1 4.67 302.85 aspartame 5 1 7.53 15.83 benzoic acid 1 1 8.14 89.98 saccharin 1 1 1.91 84.86 mixture(add everything above with 1:1:1:1 ratio) 1 4.47 69.58 How to get the concentration of the mixture in this case?arrow_forwardSample 10 ppt 20 ppt 35 ppt Temperature (C) 22.1 22.1 22.1 Measured Density (g cm¹³) 1.005 1.014 1.024 Theoretical Density (g cm¹³) Type response Type response Type responsearrow_forward
- 1-arr In a study of the gas phase decomposition of phosphine at 120 °C PH3(g)- →1/4 P4(g) + 3/2 H2(g) the concentration of PH3 was followed as a function of time. It was found that a graph of In[PH3] versus time in seconds gave a straight line with a slope of -2.50×10² s1 and a y-intercept of -3.24. Based on this plot, the reaction i v O order in PH, and the half life for the reaction is seconds. zero first secondarrow_forwardIn your own words and in no more than three sentences, briefly discuss the two methods of how AH reaction can be calculated For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac). BIUS Paragraph Arial 10pt ENDarrow_forwardWhich of the following describes a gradient elution process? stationary phase has varying concentration stationary phase has static concentration mobile phase has varying concentration mobile phase has static concentrationarrow_forward
- In a particular trial, a student got a value for R of 0.085. Calculate the percent deviation of this result. Enter a number without the % sign. The percent deviation should be reported as a positive value. (R accepted 0.082006)arrow_forwardDescriptives Bronchial reactivity 95% Confidence Interval for Mean Mean Std. Deviation Std. Error Lower Bound Upper Bound Minimum Maximum Sulfur dioxide 6.806 5 18.840 9.6919 4.3344 30.874 5.1 30.1 Nitrous dioxide 6 6.617 3.9448 1.6105 2.477 10.757 2.2 11.9 Oxygen 4 4.975 3.4092 1.7046 -450 10.400 2.1 9.3 Total 15 10.253 8.6514 2.2338 5.462 15.044 2.1 30.1 ANOVA Bronchial reactivity Sum of Squares dr Mean Square F Sig. Between Groups 559.450 2 279.725 6.873 .010 Within Groups 488.408 12 40.701 Total 1047.857 14arrow_forward6) What is the difference between CI-MS and EI-MS? What is CI and EI ?arrow_forward
- You are interested to know the Q10 value for mean heart rate (# of beats/10 sec) for a species of crab for the temperature interval of 25°C - 35°C. To find this value, you collect data for these six temperatures and calculate mean heart rate (# of beats/10 sec) for each temperature. Here is the data: 10°C 15°C 20°C 25°C 30°C 35°C Mean Heart Rate (# 23.67 23.89 24.33 27 35.89 37.78 beats/10 sec) What is the Q1o value for heart rate (# of beats/10 seconds) for the temperature interval of 25°C - 35°C? Round your answer to two decimal places.arrow_forwardTHE Y-INTERCEPT FOR THE FOLLOWING GRAPH IS: -35.0 In K# -10749 -27 -35.2 -35.4 -35.6 -35.8 -36.0 -36.2 7.4 In K = -AH/RT+AS*/R In K* = -10,749/T-27 R² = 0.974 7.6 7.8 974 NOT ENOUGH INFORMATION 8.2 8.0 (1/7)/10-4K-1 8.4 8.6arrow_forwardTrial Conc. A (M) Conc. B (M) Rate 97.943 1 0.313 0.661 0.313 0.626 195.887 783.548 1.322 0.661 4 0.855 0.914 Given the information in the table above provide the following: Order for A Order for B Overall order The rate for Trial 4 Round all answers to the nearest whole number"arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you