Air Pollution worksheet MD

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Florida International University *

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1001

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Chemistry

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Feb 20, 2024

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Air Pollution work Sheet Part A – Short Answer 1. Which is a greater health concern, outdoor or indoor air pollution? Provide evidence that backs up your answer. (2 pts) Indoor because people spend 70-98% of their time indoors, pollutants are higher concentrated indoors compared to outdoors, and you are more likely to find common pollutants inside homes and buildings instead of outdoors. 2. Assess Miami’s average air quality in comparison with other United States cities: do you think it is better or worse? Don’t just look up what it is at this moment – think about it in longer terms. What are some reasons that this might be the case? (2 pts) Miami seems to fare better than most US Cities, probably due to the amount of people that go outdoors to the beach, or park. Miami has fairly nice weather year round, and allows for more outdoor activities. 3. Explain two things that you or your household could do to reduce your contribution to outdoor air pollution. (2 pts) Get car exhaust inspections twice a year. Use mass transit, or bicycles for transportation. 4. Explain two things that you or your household could do to reduce your contribution to indoor air pollution. (2 pts) Do not buy products containing formaldehyde. Don’t store gas, solvents, and other hazardous chemicals inside the home or garage. Part B – Criteria Pollutants Use the EPA factsheets in this week’s module, or the information here , to fill out the below table on the sources, impacts on the body, and impacts on the environment of the six criteria air pollutants. (9 pts) Name of the Pollutant Sources of Pollutant Impacts on the body Impacts on the environment Lead (Pb) Ore and metals processing and piston-engine Can affect the nervous system, kidney function, immune system, reproductive and Decreased growth and reproduction of plants and animals, and neurological effects in Page 1 of 6
Name of the Pollutant Sources of Pollutant Impacts on the body Impacts on the environment aircraft operating on leaded aviation fuel. Waste incinerators, lead-acid battery manufacturers. developmental systems and cardiovascular system. Affects oxygen carrying capacity of blood. Learning deficits, lower IQ. vertebrates. Sulfur Dioxide (SO₂) Burning of fossil fuels by power plants and industrial buildings. Extracting metal from ore. Volcanoes. Vehicles and equipment that burn fuel with high sulfur content. Negatively affects respiratory system. Can worsen asthma. Damages foliage and decreases growth in tress and plants. Contributes to acid rain. Carbon Monoxide (CO) Cars, trucks, and vehicles or machinery that burn fossil fuels. Reduces oxygen in bloodstream. Causes dizziness, confusion, unconsciousness, and death. Chest pain. Contributes to climate change and global warming by adding to the amount of greenhouse gases. Particulate Matter (PM) Construction sites, unpaved roads, fields, smokestacks, fires. Pollutants from power plants, industries and vehicles. Premature death Heart attacks Asthma Decreased lung function Coughing Acidic bodies of water Contributes to acid rain Damages forests and farms Depletes nutrients in soil Affects diversity in ecosystems Nitrogen Dioxide (NO₂) Burning of fuel Cars, trucks, power plants Off road equipment Respiratory disease Asthma Coughing Wheezing Difficulty breathing Contributes to formation of particulate matter and ozone. Acid rain Air haziness Nutrient pollution Ground Ozone Created via chemical reactions between NOx and VOC. Irritates airways Coughing Sore, scratchy throat Difficulty breathing and pain Lung infection Asthma Death Reduces photosynthesis Slows plant growth Increases plant disease and damage Changes to habitat quality, water cycle, and plant assortment Page 2 of 6
Part C – Concentrations of Air Pollutants Estimate the concentration of pollutants in a (1) confined valley and an (2) unconfined valley under the two different scenarios provided for each. It is helpful if you first follow along with the example cases provided for both valleys. Case I - Confined Valley 1 km = 1000 m 1 metric ton = 1000 kg Volume= Length* Width * Depth m 3 Mass of the air= Volume* Density Concentration= Mass of the Pollutant Massof the Air Part per million (ppm) = mg of the pollutant kgof the Air Example Case I What is the concentration of the pollutant in a valley, if the total mass of pollutants discharged from the factory chimney (located on the bottom of the valley) is 40 metric tons. The dimensions of the valley are length is 1 km, width is 1 km, and depth is 1 km. The density of the air is 1.2 kg/m³. Express the answer in kg/kg and part per million by mass (ppm). Solution Volume (V) = Length* Width * Depth, so V = 1000 * 1000 * 1000= 1 x 10 9 m 3 Mass of the air = Volume * Density, so Mass of the air = 1 x 10 9 m 3 * 1.2 kg/m 3 = 1.2 x10 9 kg or 1,200,000,000 kg Concentration= Mass of the Pollutant Mass of the Air Concentration= 40,000 kg 1,200,000,000 kg = 0.0000333 = 3.3 x 10 -5 kg/kg = 33.3 ppm. Case I Exercises (4 pts) 1. What is the concentration of the pollutants in the valley, if the mass of pollutants that are discharged from the factory chimney, which is located on the bottom of the valley, is 20 tons? The dimensions of the valley are as follows: length is 2 km, width is 0.5 km, and depth is 1 km. The density of the air is 1.2 kg/m³. Express the answer in kg/kg and part per million by mass (ppm). 2. What is the concentration of the pollutants in the valley, if the mass of pollutants that are discharged from the factory chimney, which is located on the bottom of the valley, is 25 tons? The dimensions of the valley are as follows: length is 2 km, width is 1 km, and depth is 0.1 km. The density of the air is 1.2 kg/m³. Express the answer in kg/kg and part per million by mass (ppm). Page 3 of 6
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Question Show the concentration calculations and circle the answer 1 2 x 10^4kg / 1.2 x 10^9 kg = 1.67 / 10^5 16.7 / 10^6 16.7 2 2.5 x 10^4 / 2.4 x 10^8 = 2.5/2.4 = 1.04 1.04 / 10^4 multiply top and bottom by 10^2 to get 10^6 104 / 10^6 104 Page 4 of 6
Case II – Unconfined Mixing Volume of a hemisphere = 2 3 r 3 Mass of the air = Volume * Density Concentration= Mass of the Pollutant Massof the Air Example Case II What is the concentration of the pollutants in the air on the distance 500 m from the pipe (the radius is 500 m) if the mass of discharged pollutants is 40 metric tons. The density of the air is 1.2 kg/m 3 . Solution V = 2 3 * 3.14* (500) 3 so, V = 261,799,387.8 m 3 Mass of the air = V *Density, so Mass of the air= 261,799,387.8 m 3 * 1.2 kg/m 3 = 314,159,265.4 kg Concentration= Mass of the Pollutant Mass of the Air so, Concentration= 40,000 kg 314,159,265.4 kg = 0.000127324 = 1.27 x 10 -4 kg/kg = 127 ppm Case II Exercise (4 pts) 1. What is the concentration of the pollutants in the air at a distance 100 m from the pipe if the mass of discharged pollutants is 1 ton? The density of the air is 1.2 kg/m 3 . Express the answer in kg/kg and part per million by mass (ppm). 2. What is the concentration of the pollutants in the air at a distance 50 m from the pipe if the mass of discharged pollutants is 10 tons? The density of the air is 1.2 kg/m 3 . Express the answer in kg/kg and part per million by mass (ppm). Question Show the concentration calculations and circle the answer 1 100 / 2,513,274.12 = 0.000397887358184 = 3.97 x 10^-4 kg Turn the equation into division 3.97 / 10^4 multiply top and bottom by 10^2 to get 10^6 397 / 10^6 Page 5 of 6
397 ppm rounded . 2 10,000 / 314,159.253589793 = 0.03183099 = 3.183099 x 10^-2 Turn the equation into division 3.183099 / 10^2 multiply top and bottom by 10^4 31,831 / 10^6 31,831 rounded. Page 6 of 6
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