Chem103.M1ProblemSet
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Feb 20, 2024
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Chemistry Module 1 Review Question 1
Convert the following numbers from one form to another and explain your answer. 1.) 5.38 x 10
-3
= _____________ 2.) 623000000. = _____________ 1) 5.38 x 10
-3
= .00538 Since the exponent is negative, then the ordinary number is going to be <1 •
decimal moves 3 spots to the left 2) 623000000 = 6.23 x 10
8
The number is >1, so the exponent will be positive. •
decimal moves 8 spots to the left 1.) 5.38 x 10
-3
= negative exponent = smaller than 1, move decimal 3 places = 0.00538
2.) 623000000. = larger than 1 = positive exponent, move decimal 8 places = 6.23 X 10
8
Question 2
Complete the following conversions and show all work. Be sure to write your answer with the correct units. 1.) 25.3 g = __________ decigrams 2.) 56 ft = __________ in 1) 25.3 g = ? decigrams 25.3 x 10 decigrams/1 g = 253 decigrams
2) 56 ft = ? in 56 x 12 in/1 ft = 672 in 1.) 25.3 g x 10 dc / 1 g = 253 dg
2.) 56 ft x 12 in / 1 ft = 672 in
Question 3
Complete the following conversions and show all work. Be sure to write your answer with the correct units. 1.) 85 o
F = ___ o
C 2.) 412 o
K = ___ o
F
1) (85-32)/1.8 = 29.4
o
C
2) 412 - 273 = 139 o
C 139 x 1.8 + 32 = 282.2 o
F
1.) 85 o
F - 32 ÷
1.8 = 29.4 o
C
2.) 412 o
K - 273 = 139 o
C x 1.8 + 32 = 282.2 o
F
Question 4
Complete the following problems and show all work. Be sure to show the correct number of significant figures in each calculation and answer with the correct units. 1.) What is the volume of a sample of mercury (d = 13.6 g/ml) which weighs 1000. g? 2.) What is the density of 200. ml of bromine which weighs 620. grams? 1) v = m/d 1000/13.6 = 73.529 v = 73.529mL
2) d = m/v 620/200 = 3.1 d = 3.1 g/mL
1.) 13.6 g/ml = D 1000 g = M find V = M / D = 1000 / 13.6 = 73.5 ml
2.) 200 ml = V 620 g = M find D = M / V = 620 g / 200 ml = 3.10 g/ml
Question 5
Complete the following problems and show all work when necessary. Be sure to show the correct number of significant figures in each calculation and answer with the correct units. How many significant figures are there in each of the following numbers? 1.) 306.2 2.) 0.0231 3.) What is the mass of a sample of lead (d = 11.35 g/ml) which has a volume of 85.0 mL? 1) 4 2) 3 3) m = d x v 11.35 x 85.0 = 964.75 m = 965 g 1.) 306.2
contains 4 significant figures 2.) 0.0
231
contains 3 significant figures 3.) M = V x D = 85.0 mL x 11.35 g/ml = 965 g (multiplication, volume contains only 3 sig figs) Question 6
Describe each material below as an element, compound, solution or heterogeneous mixture and explain your answer. 1.) Sea water 2.) Aluminum 3.) Potassium bromide 4.) Vodka 5.) Raisin bread Your Answer: 1) sea water = heterogenous mixture
- when looking closely at seawater, you can sea different layers (salt, water, perhaps some other substances mixed in) 2) aluminum = element
- is found on the periodic table 3) potassium bromide = compound - contains two elements found on the periodic table 4) vodka = solution
- is not on the period table and contains no element names, appears as only one substance/layer 5) raisin bread = heterogeneous mixture - contains multiple substances/layers/colors when looking at it (dough, raisins, etc) Answers
1. Sea water
Not on periodic table (not element)
No element names (not compound)
Appears to be one substance = SOLUTION
2. Aluminum
Is found on periodic table = ELEMENT
3. Potassium bromide
Is not on periodic table (not element)
Has two element names = COMPOUND
4. Vodka
Is not on periodic table (not element)
No element names (not compound)
Appears to be one substance = SOLUTION
5. Raisin bread
Is not on periodic table (not element)
No element names (not compound)
Appears as more than one substance (bread, raisins) = HETEROGENOUS MIXTURE
Question 7
Classify the following as physical or chemical changes: 1. A pile of leaves is burned 2. Your hair is trimmed by a hairstylist
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3. Flour, water, eggs, butter and sugar are combined and baked to make a cake Your Answer: 1. chemical change 2. physical change 3. chemical change 1. A pile of leaves is burned = Chemical
2. Your hair is trimmed by a hairstylist (hair is still hair but shorter) = Physical
3. Flour, water, eggs, butter and sugar are combined (Physical) and baked to make a cake = Chemical
Question 8
Name the following compounds: 1.) Fe(OH)
3
____________________ 2.) MgCO
3 ____________________ 3.) PF
5
____________________ 4.) HNO
2
____________________ Your Answer: 1) iron (III) hydroxide 2) magnesium carbonate 3) phosphorus pentafluoride 4) nitrous acid NAMING COMPOUNDS
1.) Fe(OH)
3
= Iron (III) hydroxide
2.) MgCO
3
= Magnesium carbonate 3.) PF
5
= Phosphorus pentafluoride
4.) HNO
2
= Nitrous acid Question 9
Write the formula for each of the following chemical compounds below and then explain your answer by referring to the prefixes or suffixes or showing charges that were used to determine the formula. 1.) Aluminum sulfide _______________ 2.) Lead (IV) oxide _______________ 3.) Calcium cyanide _______________ 4.) Dinitrogen Trioxide _______________ 5.) Potassium bromide _______________ Your Answer: 1) Al
2
S
3
2) PbO
2
3) Ca(CN)
2
4) N
2
O
3
5) KBr WRITING FORMULAS
1. Al
+3
, S
-2
= Al
2
S
3
2. Pb
+4
, O
-2
= PbO
2
(need just 2 Os to balance Pb) 3. Ca
+2
, CN
-1
= Ca(CN)
2
4. Di-two N, Tri-three O = N
2
O
3
5. K
+1
, Br
-1
= KBr
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3
0/4vime b)
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Question 5 of 21
Attempt 4
Chemistry: Fundamentals and Principles
Davidson
presented by Macmillan Leaming
The mass of gemstones and pearls is usually expressed in units called carats. One carat is equal to exactly 200 mg. What is the
mass in grams of a 2.10-carat diamond ?
2.10-carat diamond =
} TOOLS
x10
Show All
2021 02 04 10 1..jpg
E Anticipation Gui. doc
chem20lec8hand.pdf
Module 3
MacBook Air
F12
FIL
F10
F7
吕口
F3
000
DO0 CA
F2
*
&
#
%2$
%
8
7
4
5
P
Y
E
R
K
F
G
H
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» Significant Figure Rules
01 >>
02 >>
03 >>
04 >>
05 >>
All nonzero digits are significant.
Zeros that appear between other
nonzero digits are always significant.
Zeros that appear in front of all of the
nonzero digits are called left-end zeros.
Left-end zeros are never significant.
Zeros that appear after all nonzero
digits are called right-end zeros.
Right-end zeros in a number that locks
a decimal point are not significant.
▬▬▬
美銀銀時
☐☐
Right-end zeros in a number with a
decimal point are significant.
This is true whether the zeros occur
before or ofter the decimal point.
237 has three significant figures.
1.897 has four significant figures.
39,004 has five significant figures.
5.02 has three significant figures.
0.008 has one significant figure.
0.000416 has three significant figures.
140 has two significant figures.
75,210 has four significant figures.
620.0 has four significant figures.
19.000 has five significant figures.
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Measured Value
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38.0 mL
Number of Significant Figures
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Write each of the following numbers in exponential or scientific notation. Write each number to two decimal places with only one non-
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7640
0.000125
0.000844
257000
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4
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Student name
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(1) 0.0044500 m
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(4) 1.00 x 10³ s
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O
Date:
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IN-LABORATORY WORKSHEET
1. Give the number of significant figures in each of the following numbers.
(1) 1,278.50
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(4) 0.0053567
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(7) 8.002
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3) Trailing zeros in a number are significant only If the
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100 has 1 significant figure.
4) Zeros in the beginning of a number whose only function
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5) Zeros following a decimal significant figure are
significant.
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Determine the number of significant figures in the following numbers.
1. 0.02
6. 5,000.
4.
2. 0.020
2.
7. 6,051.006
3. 501 3
8. 0.0005 1.
4. 501.0
9. 0.1020
5. 5,000
10. 10,001 5
Determine the location of the last significant place value by placing a bar over the digit.
Example: 1.700)
9,010.0
4.7x10-8
10,8 00,000
3.0Tx 1021
0.00410
1. 8040
6. 90,100
0.0300
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2,000X162
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