482196544-correction-09-11-copy2-docx

docx

School

St. John's University *

*We aren’t endorsed by this school

Course

2320

Subject

Chemistry

Date

Nov 24, 2024

Type

docx

Pages

Uploaded by vincentha96

Chapter 9 Q.4) Answer is : [d] Q.13) Option is not uploaded properly Q.13 Upload solution: UV Stabilizer Phenyl salicylate , 2-(2’- hydroxyl phenyl)benzotriazole , Resorcinol monobenzoate, 2-Hydroxy-4-methoxy benzophenone, 2,2’-Dihydroxy-4-methoxybenzophenone, & 1,3,5-Tris-(2-hydroxyphenyl)-triazine & o-Hydroxybenzophenone Heat Stabilizer Tribasic lead sulphate, Dibasic lead phosphite Antistatic agent Quaternary ammonium compounds, amines and their derivatives, phosphate esters, fatty acid polyglycol esters, and polyhydric alcohol derivatives such as glycerine and sorbitol. Flame reatrdents Alumina trihydrates; bromine compounds; chlorinated paraffins and cycloaliphatics; phosphorus compounds, notably phosphate esters; and antimony oxides Chapter 10 Q.12) Replace 10 Pa to 1000 Pa Q.16) Change Q.16 complete. Q.16) the yield stress for polyethylene is 4000 dyne/cm 2 . The required pressure difference for the polyethylene sample to start flow in a capillary viscometer of length 50cm and radius 1.2mm is ___ Mpa (Round off to 2 decimal place). [16][0.33-0.34] Pressure drop equation when stress is give: 1000 Pa

1 2 PR L    3 2 1 1.2 10 4000 2 0.50 3333333.33 / 0.33 P P dyne cm Mpa         Q.17) Solution change Changed with 1 4 57.34sec Sin Sin 4 Shear rate       Q.20) Replace solution [20][4134.10-4134.90] Capillary rheometery follows the Hagen Poiseuille's Equation: viscosity of fluid in a pipe: 4 8 R P LQ    Where, R = radius of capillary (m) ; L = length of capillary (m); P = pressure drop across the capillary (Pa) Q = volumetric flow rate (m 3 /s); 4 8 R P Q L    4 6 6 3 6 3 3 0.01 3.14 0.6 10 2 4.1345 10 / 8 89 .40 4.1345 10 / 4134.50 / Q m s Q m s mm s                    Q.22) Change in question

A rubber sample relaxation time is 42 days at 25°C in a maxwell model experiment. If the activation energy for relaxation is 45 KJ/mol, the relaxation time at 43°C will be___days. (Round off to 2decimal place). [Given: R =8.317 J/mol/K Change in solution 22][13.20-13.78] Polymer fluid follows the Arrhenius equation: 1 2 1 2 1 1 ln , a E R T T           1 2 1 273 25 298, 273 43 318, 42 T T days         2 2 45000 1 1 ln , 13.4067 8.317 298 318 42 days            Chapter 11 Q.5 Answer is [d] Q.19) [19][1.98-2.13] 2.091 N  1 tan ( ) p Flight angle D    p= pitch and D diameter of screw 1 95 tan ( ) 3.14 100 Flight angle    16.833    Total Flow in the extrusion: net D p Q Q Q   remove

Your preview ends here

Eager to read complete document? Join bartleby learn and gain access to the full version

Access to all documents
Unlimited textbook solutions
24/7 expert homework help

3 2 2 2 sin 1 sin cos 2 12            net πDH P Qπ D N H η l 2 5 6 3 2 5 2 3.14 0.1 0.007 sin 1 20 10 3.14 sin16.833cos16.833 0.007 2 12 2 10 16.833 6 10 0.1 2                   N 2.091 N  Q.20) An injection molding machine inject polymer material in a cylindrical tube having a diameter 20mm and length 150mm. The pressure drop across the mold is 120 Mpa observed. The Inject rate of the injection molding when viscosity of the polymer is 500 Pa-s, is ___L/s. ( round off to 2 decimal place). Add