AME 230-Midterm Exam 1-Fall 2023-Answers

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1 Fall 2023 AME 230 -Thermodynamics Midterm Exam # 1 Answers September 18, 2023 You will have about 50 Minutes for this exam. This is a closed-note and closed-book exam. Useful formulas, constants and tables are provided. Answers to problems 8 and 9 should use Use thermodynamics problem-solving method. Neatness is very important. If I cannot follow the solution, that problem will not be graded. I, ______________________________ (Print Name), with ID #___________________, Understand that I should NOT receive any unauthorized help from or give any unauthorized help to anyone else during this exam; otherwise, I will get an automatic “F” in this exam. < signature >____________________ Score
2 Midterm #1, AME 230, Fall 2023 Print Name (clearly) 1. Indicate whether the following statements are true or false (each 3 point) a) The specific volume is not the reciprocal of the density. A: True B: False b) Work is energy transfer for which the sole effect on everything external to the system could have been the raising of a weight. A: True B: False c) A system may contain energy in the form of heat. A: True B: False d) A change in the total energy of a system is described by the change in its internal, kinetic and potential energy. A: True B: False e) The temperature of a system can be changed by a heat transfer only. A: True B: False f) If a closed system undergoes a thermodynamic cycle, there can be no net work or heat transfer. A: True B: False g) Water in a glass with ice cubes consists of several phases. A: True B: False h) The work done by a system is taken as negative ( W < 0). A: True B: False i) Heat transfer from a system is taken as positive (Q > 0). A: True B: False j) Specific heat is the energy required to raise the temperature of the unit mass of a substance by one degree keeping volume or pressure constant A: True B: False
3 Midterm #1, AME 230, Fall 2023 Print Name (clearly) 2. Through a Venturi meter shown in picture below a steady flow of kerosene is established. As the kerosene flows from point a to point b does the pressure increase or decrease as the pipe diameter decreases? (4 point) Answer (one word, no explanation needed): decreases 3. What is The First Law of Thermodynamics (definition in your own words if understandable and the standard definition are both acceptable). (4 point) Answer: (a) energy is conserved or (a) energy can be neither created nor destroyed during a process; it can only change forms 4. For any particular application, energy transfer by heat can occur by one or more of three modes. List the three modes of energy transfer by heat and name the laws associated with each. (6 point) Answer: a. Conduction (Fourier’s law) b. Convection (Newton’s law of cooling) c. Radiation (Stefan-Boltzmann law) 5. What is the quality of the liquid-vapor mixture of H 2 O if its specific volume, υ = 1 m³/kg at 100°C, with v f = 1.0435 × 10 -3 m³/kg and v g = 1.673 m³/kg. (You do not need to Use thermodynamics problem-solving method, but you need to clearly show all relevant equations and calculations). (6 point) Since v = (1 – x ) v f + x v g ࠵? = ࠵? − ࠵? ! ࠵? " − ࠵? ! = 1 ࠵? # ࠵?࠵? − 1.0425 ×10 $# ࠵? # ࠵?࠵? 1.673 ࠵? # ࠵?࠵? − 1.0425 ×10 $# ࠵? # ࠵?࠵? = 0.597
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4 Midterm #1, AME 230, Fall 2023 Print Name (clearly) 6. A thermodynamic cycle is a sequence of processes that begins and ends at the same state. List three main thermodynamic cycles and provide their sketch, clearly indicating work and heat directions. (9 point) Answer: a. Power cycle b. Refrigeration cycle c. Heat pump cycle 7. Sketch p-T and T- υ diagram based on p- υ- T surface of H 2 O. Indicate, liquid (L), vapor (V), solid (S) and liquid-vapor (L-V) phases, where applicable. On p-T diagram indicate the triple and critical point and on T- υ diagram indicate the critical point. (8 point)
5 Midterm #1, AME 230, Fall 2023 Print Name (clearly) 8. A residential heat pump is used to provide heating during the winter months. The heat pump absorbs Q in =1500 Btu from the outside air and requires a work input of W cycle =400 Btu to operate. Determine the coefficient of performance for the heat pump cycle. Use the diagram you draw for heat pump cycle in question 6 and clearly mark the direction of heat and work. Use thermodynamics problem-solving method. (13 point) KNOWN : The heat input and net work input for a heat pump cycle are specified. FIND : Determine the coefficient of performance. SCHEMATIC AND GIVEN DATA : Q in = 1500 Btu W cycle = 400 Btu ENGINEERING MODEL : 1. The cycle is a heat pump cycle. 2. Energy transfers are positive in the directions of the arrows on the figure. ANALYSIS : For the heat pump cycle, ࠵? = % !"# & $%$&’ To get Q out we note that Δ E cycle = 0 , so W cycle = Q out Q in Q out = Q in + W cycle = 1500 + 400 = 1900 Btu Now, the coefficient of performance (COP) for the heat pump is: ࠵? = ࠵? ’() ࠵? *+*,- = 1900 ࠵?࠵?࠵? 400 ࠵?࠵?࠵? = 4.75
6 9. A total of 0.9 kg of superheated water vapor is in a piston-cylinder assembly, initially at 7 bar and 500 0 C. The water undergoes first a constant pressure process followed by a constant volume process. At the end of the constant volume process, the water is a two- phase liquid-vapor mixture with a quality of 0.6 and at the temperature of 150 0 C. Determine the final pressure, the work and heat transfer for each process, all in kJ and sketch T - v and p - v diagrams showing the key states and the processes. Use thermodynamics problem-solving method. (20 point) Midterm #1, AME 230, Fall 2023 Print Name (clearly) SOLUTION KNOWN : Water contained in a piston cylinder assembly undergoes two processes in series. FIND : Sketch the T - v and p - v diagrams and for each process determine Q, W and and final pressure. SCHEMATIC AND GIVEN DATA : Initial state: p = 7 bar, T = 500 0 C. Final state: x = 0.6, T = 150 0 C. ENGINEERING MODEL : 1. The water is a closed system. 2. Volume change is the only work mode. 3. Process 1-2 occurs at constant pressure and Process 2-3 occurs at constant volume. 4. Kinetic and potential energy effects can be neglected. ANALYSIS : First, we fix each state. State 1 is in the superheated vapor region. From Table A-4 at 7 bar and 500 o C: υ 1 = 0.5070 m 3 /kg and u 1 = 3126.8 kJ/kg. State 3 is in liquid-vapor region at T 3 = 150 o C and x 3 = 0.6. From Table 2 we can calculate specific volume and internal energy υ 3 = υ f3 + x 3 ( υ g3 ̶ υ f3 ) = 0.0010905(m 3 /kg) + 0.6(0.3928 ̶ 0.0010905)(m 3 /kg) = 0.2361 m 3 /kg and u 3 = u f3 + x 3 ( u g3 ̶ u f3 ) = 631.68(kJ/kg) + 0.6(2559.5 ̶ 631.68)(kJ/kg) = 1788.4 kJ/kg. For state 2 υ 3 = υ 2 = 0.2361 m 3 /kg, and from Table A-3 we see that υ 2 < υ g (7 bar). Thus, the quality at state 2 is x 2 = ( υ 2 ̶ υ f2 )/( υ g2 ̶ υ f2 ) = (0.2361 ̶ 0.0011080)/(0.2729 ̶ 0.0011080) = 0.8646 and u 2 = u f2 + x 2 ( u g2 ̶ u f2 ) = 696.44(kJ/kg) + 0.8646(2572.5 ̶ 696.44)(kJ/kg) = 2279.6 kJ/kg.
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7 ( )( )( ) 2 3 5 2 12 1 2 1 3 1 m 10 N/m 1kJ ( ) 0.9kg 7bar 0.2361 0.5070 170.7 kJ kg 1bar 10 N m W pdV mp v v = = - = - = - × ò Midterm #1, AME 230, Fall 2023 Print Name (clearly) ( )( ) ( ) 12 2 1 12 kJ ( ) 0.9kg 2279.6 3126.8 170kJ 932.48 kJ kg Q m u u W = - + = - + - = - ( )( ) 23 3 2 12 kJ ( ) 0.9kg 1788.4 2279.6 442.1 kJ kg Q m u u W = - + = - = - An energy balance reduces to give Now, for process 2-3, the volume is constant, thus W23 = 0. The energy balance reduces to give The final pressure from Table 2 is 4.758 bar. Now, we can calculate work from state 1 to 2:
8 Key equations
9 Conversion factors Constants
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