BU340 managerial finance I assignment 8

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Ashworth College *

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340

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Accounting

Date

Apr 3, 2024

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Jennifer Egan AC0525806 BU340 Managerial Finance I Assignment 8 February 18, 2024 Part A a. To find the price of the bond if the bond matures in 5 years using a financial calculator, input 10 for N, 5% for I/Y, $40 for PMT, and 1,000 for FV. The PV equals $922.78 . To find the price of the bond if the bond matures in 10 years using a financial calculator, input 20 for N, 5% for I/Y, $40 for PMT, and 1,000 for FV. The PV equals $875.38 . To find the price of the bond if the bond matures in 15 years using a financial calculator, input 30 for N, 5% for I/Y, $40 for PMT, and 1,000 for FV. The PV equals $846.28 . To find the price of the bond if the bond matures in 20 years using a financial calculator, input 40 for N, 5% for I/Y, $40 for PMT, and 1,000 for FV. The PV equals $828.41 . b. The longer that the maturity of the bond is, the lower the cost of the bond. Part B To find what I should offer to buy the bond today or the present value, I used a financial calculator. Input 4 for N, 13% for I/Y, 2 for PMT, and 30 for FV. The present value equals $24.35 . The stock should be purchased at $24.35 today to reach $30 in 4 years time. Part C a. For Asset A, the expected return = (.35 x .04)+(.50 x .04)+(.15 x .04)= .04= 4%
For Asset B, the expected return = (.35 x .210)+(.50 x .080)+(.15 x -.010)= .116= 11.6% For Asset C, the expected return = (.35 x .300)+(.50 x .200)+(.15 x -.260)= .166= 16.6% b. For Asset A, variance= (.04-.04)^2 x .35 + (.04-.04)^2 x .50 + (.04-.04)^2 x .15= 0 + 0 + 0 = 0 . For Asset B, variance= (.210-.112)^2 x .35 + (.080-.112)^2 x .50 + (-.010-.112)^2 x .15 = .0033614 + .00512 + .0022326 = .006106 For Asset C, variance= (.300-.166)^2 x .35 + (.200-.166)^2 x .50 + (-.260-.166)^2 x .15= .0062846 + .000578 + .0272214 = .034084 c. For Asset A, the standard deviation = √0 = 0 = 0% For Asset B, the standard deviation = √.006106 = .0781 = 7.81% For Asset C, the standard deviation = √.034084 = .1846 = 18.46%
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