Chapter N, Problem 1DE

In reference to Example 1, what is the probability that a person is right-handed?

To determine

To calculate: The probability that a person is a right-handed from the following graph.

Answer to Problem 1DE

Solution:

The probability that a person is right-handed, is $\underset{\_}{\frac{82}{100}}$.

Explanation of Solution

Given Information:

The number of people who are left-handed, right-handed or both in a survey shown in the graph,

Formula used:

The experimental probability of an event $E$ is the ratio of number of times $m$ the event occurs

to the number of trails of $n$, then, the formula used is,

$\begin{array}{c}P\left(E\right)=\frac{\text{Numbe of times the event occurs}}{\text{Total number of trials}}\\ =\frac{m}{n}\end{array}$

Calculation:

Consider the number of people who are right-handed is 82, the number who are left-handed is 17 and there is 1 person who is right hand as well as left hand.

Therefore, the total number of observationsare,

$\begin{array}{c}n=82+17+1\\ =100\end{array}$

The number of people who are right-handed is 82.

Now the probability that a person is right-handed is,

$\begin{array}{c}P\left(E\right)=\frac{m}{n}\\ =\frac{82}{100}\end{array}$

Therefore, the probability that a person is right-handed, is $\frac{82}{100}$.