Chapter 9.49, Problem 49.5E

A population that is uniformly distributed between a=0and b=10 is given in sample sizes ​50(   ​), ​100(   ​), ​250(   ​), and ​500(   ​). Find the sample mean and the sample standard deviations for the given data. Compare your results to the average of means for a sample of size​ 10, and use the empirical rules to analyze the sampling error. For each​ sample, also find the standard error of the mean using formula given below.   Standard Error of the Mean =sigma/Root  Complete the following table with the results from the sampling experiment. ​(Round to four decimal places as​ needed.) Sample Size Average of 8 Sample Means Standard Deviation of 8 Sample Means Standard Error 50       100       250       500

survey of 5050 young professionals found that they spent an average of ​$20.5620.56 when dining​ out, with a standard deviation of ​$11.4111.41. Can you conclude statistically that the population mean is greater than ​$2323​? Use a​ 95% confidence interval.       Question content area bottom Part 1 The​ 95% confidence interval is left bracket nothing comma nothing right bracketenter your response here, enter your response here. As ​$2323 is ▼     of the confidence​ interval, we ▼   can cannot conclude that the population mean is greater than ​$2323. ​(Use ascending order. Round to four decimal places as​ needed.)

1. vector projection. Assume, ER1001 and you know the following: ||||=4, 7=-0.5.7. For each of the following, explicitly compute the value. འབ (a) (b) (c) (d) answer. Explicitly compute ||y7||. Explain your answer. Explicitly compute the cosine similarity of and y. Explain your Explicitly compute (x, y). Explain your answer. Find the projection of onto y and the projection of onto .