Chapter 8, Problem 8.76P

In a railway system with a power source of 600 VDC, I need to achieve a load output of 120 VDC for railway lights. I found a DC-DC converter capable of stepping down 600 VDC to 125 VDC. To obtain 120 VDC from this converter, we can use a voltage divider with the following equation:​ [R2/(R2+R1)]=120/125=0.96=0.96However, using resistors to achieve the desired output voltage raises some concerns. Is it advisable to use railway-grade resistors for this application? I found some resistors in the range of 1-10k ohms, but I am unsure how they should be connected in the circuit with the lights (the load to be used). I would greatly appreciate any suggestions or schematic diagrams to clarify the best approach for connecting the resistors in this setup.

Find the valve of the voltage Vx using the THEVENIN equivalent circuit and redo the problem with the NORTON equivalent circuit. Show both the the vinen and Norton circuits. I 12V m 1 ww 3 23 + 43Vx 5 63 ми

Find the valve of V using the Thevenin Equivalent Circuit and then determine if the 8 ohm resistor allows maximum power transfer. If not, then what value should the 8 ohm resistor be changed to for maximum power transfer? ZA 6 6 + 22V 83 V 34 2 6 АААА АААА