EBK WATER RESOURCES ENGINEERING
3rd Edition
ISBN: 9781119493167
Author: Mays
Publisher: VST
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Q2) For a total rainfall of 44 mm, distributed as shown in the table (3), establish the o index of
the catchment area for a surface runoff of 19.5 mm.
Table (3) Rainfall intensity versus time.
Time
Rainfall intensity (mm/hr)
1
4
21
3
9.
4
6.
4
The streamflow data given in the table was produced by a storm of 1-hour duration
considered to have uniform intensiry over the catchment. If the catchment area is 5 km',
calculate the equivalent runoff depth for the catclument.
Q. Total
(n/s)
flow Q.
(n/s)
Time
Baseflow
(hr)
2.80
2.80
2.78
2.60
3
6.23
2.60
14.50
2.60
16.57
2.60
13.03
2.60
7.
9.35
2.60
5.95
2.60
4.25
2.60
10
2.97
2.60
2.12
2.12
12
1.70
1.70
13
1.53
1.53
14
1.53
1.53
a. Using the rainfall data provided in Table 1, the two-hour unit hydrograph given in Table 2, a
index of 0.5 cm/h, and a baseflow of 20 m/s:
Determine the surface runoff hydrograph from the 4-hour rainfall;
Compute the peak streamflow and hour of occurrence;
I.
Estimate the volume of stream occurring between the fourth and eight hours.
b. Use the two-hour Unit hydrograph to develop the five-hour unit hydrograph.
Table 1 Rainfall data
Time Interval (h)
0=2
2-4
Rainfall (cm)
3.5
2.5
Table 2 Unit hydrograph ordinates
Time (hr)
1
2
4
5
10
UH (m/s)
Activate
GOo Settir
3
11
18
26
24
17
3.
00
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- Net Storm Rainfall Example 2-1 Rain falls as shown in the rainfall hyetograph (intensity Vs. time) in Fig. E2-1 (a). The o index for the Storm is 0.5 in./hr and is constant over 5 hr. Plot the net rainfall on the hydrograph (flow vs. time) given in Fig. E2-1 (a). Determine the total volume of runoff and the watershed area. 1cfs = 1.008 ac-in/hr 2.0 1.5 1.0 0.5 1 3. 4 Time (hr) 700 600 500 400 300 200 100 4 8 12 16 20 24 Time (hr) Time (hr) Q (cfs) Volume (cfs-hr) 0-2 2-4 4-6 6-8 8-10 10-12 12-14 14-16 16-18 18-20 20-22 22-24 24-26 16 Q (cfs) iT (in./hr)arrow_forwardA catchment area has a time of concentration of 20 minutes, an area of 20 has. and a runoff coefficient of 0.25. Estimate the peak discharge corresponding to a 25-year period if the intensity-duration-frequency for the storm in the area can be expressed byarrow_forwardPhi-Index Method The mass curve of an isolated storm in a 500 ha watershed is as follows: Time (hr) 0 2 4 6 8 10 12 14 16 18 Cumulative rainfall (cm) 0 0.8 2.6 2.8 4.1 7.3 10.8 11.8 12.4 12.6 If the direct runoff produced by the storm is measured at the outlet of the watershed as 0.340M m3, Determine the total ER and infiltration in cm. Estimate the Φ-index of the storm and the duration of the rainfall excess. Plot the hyetograph showing the Φ-index. Plot the ER.arrow_forward
- Solve asaparrow_forwardQUESTION 3 10 A storm with 10 cm precipitation produced a direct surface runoff of 5.8 cm in the equivalent depth unit. The time distribution of the storm is given in Table below. Estimate the @-index of the storm and the excess rainfall hyetograph. Time from start (hr) Incremental 0.4 rainfall in each hr (cm) 4 6. 0.9 1.5. 3.3 T.7 1.6 1.0 0.5arrow_forwardFor the following rainfall rate, find the net runoff in cm, total rainfall and the value of W-index. Take Ø-index = 3. Time (min) 10 20 30 40 50 60 70 Rain rate (cm/hr) 2.5 2.5 10 7.5 1.25 1.25 5arrow_forward
- Subject: ( Hydrology and water Resources management )arrow_forwardA 0.10 mi2 parking lot has a runoff coefficient of 0.8 and a time of concentration of 40 minutes. For the following three rainstorms, determine the peak discharge (in ft3/s) using the Rational Method. a. 4.0 in/hr for 10 minutes b. 1.0 in/hr for 40 minutes c. 0.5 in/hr for 60 minutesarrow_forwardConsider the following storm event given below for a small catchment of 120 ha. For a baseflow of 0.05 m'/s, (a) compute the volume of direct runoff (in mm), (b) assuming the initial losses (abstractions) are 5 mm, determine the value of -index (in mm/hr), and (c) the corresponding effective rainfall intensity hyetograph (in mm/hr). Time (min) Cumulative rainfall 5 10 15 20 25 30 Depth (mm) Discharge (m/s) 5 20 35 45 0.05 0.05 0.25 0.65 0.35 0.15 0.05arrow_forward
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