
Foundation Design: Principles and Practices (3rd Edition)
3rd Edition
ISBN: 9780133411898
Author: Donald P. Coduto, William A. Kitch, Man-chu Ronald Yeung
Publisher: PEARSON
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A cantilever beam ABC is loaded as shown in Figure 1. A is a fixed support. Assume E= 200 GPa and I = 200 x 10^6 mm^4.
(a) Using the moment area method, determine the slope at B.
(b) Using the conjugate beam method, determine the vertical deflection at B.
(c) Using the virtual work method, determine the vertical deflection at C.
Compute for the stresses (initial, const and final stage)
and check for compliance in NSCP provisions.
Also compute the following:
1. Compute and check if the section is Uncracked,
Transition or Cracked as per NSCP.
2. Compute for its flexural capacity and check if it
could carry the given load.
BEAM SECTION
NOT TO SCALE
1400mm
300 $1098 400 */ 400*300*
300
200
300
100
ORIGINAL SECTION/PRECA
CAST-IN-PLACE (CIP) PART
PRECAST
LOADING AT SERVICE
M
• 21 KN (DEAD LOAD ONLY)
21KN
4.75m
9.25m
CIVEN DATA
STRANDS:
12-02 AT 120KN/STRAND (GOMM FROM BOTTOM)
8-2 AT 120HN/STRAND (120mm FROM BOTTOM)
fc 42.5 MPa (BEAM)
fc 38 MPa (CIP)
f'a = 80% or fa
fp-1860 MPa
ESTRANDS 1976Pa
OONG 23.6/m³
LOES 1-8%
Loss 18%
APPLY 3M LIVE LOAD AT CONST. PHASE
Please explain all your steps. Thank you.
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- مارت حولة ملانول 60 Design Deceleration tank and screen for W.W.T.P of flow-144000 m² day Design Data: D.T=1-3 min 1-3b, d=1-1.5 m 60 Design Data: velocity= 0.6: 1.5 m/sec . A-Qdfv=b.d, b=2d 233 Design Data: bars used circular of p= 1.5:3 cm. rec. of (1:2 cm) x (2:6 cm) spacing between bars 2.5:5.0 cm fine screen, 2.5 7.5 cm coarse screen Sloping angle on hz (6)=45:60 = depth of water depth in approaching channel=d = ⚫nbars nspacings +1 ⚫b=nbars xo+nspacings I spacing net inclined area = 2 Aapproach channel=nspacing. spacing. L. 1=d/ sin Check: = 1.13 C 2.56 1134(6.05 P. 45.30 *velocity just befor the screen=v₁ = Qa(m³/sec) screen-b.d ≥ 0.6 m/sec. * velocity through the screen=v2 16mm use 2 Qa(m³/sec) nscreens (spacings Spacing).d ≤1.5 m/sec IsP. 22-65 12²² head losses = Ah = 1.4 x ≤0.1 m 2g bav usp = Ubar Q 23.65 k 148.72arrow_forwardCan you please explain the steps of this problem especially the variables for Q when solving for the shear force? Thanks.arrow_forwardPlease show all your steps. Thank you.arrow_forward
- The solution to this problem is 10.5kip. Please explain all the steps.arrow_forwardQ1: Design of trickling filter system single-stage with 3m depth, effluent BOD, of 20 mg/l, influent BODs =250mg/l, flow = 2.63 m³/min and hydraulic flow rate or hydraulic loading rate 25 m/day, r=3arrow_forward04 Q4 A waste effluent of 1.25 m/s with BOD, 183 mg/L, DO=0 mg/L and T = 20 °C is to be discharged into a river of 8 m³/s flow, BOD, = 2mg/L, DO -9.14 mg/L and T= 15 °C. At 20 °C, (K₁) is 0.3/day and (K2) is 0.9/day. The average velocity of the river is 0.8 m/s. 1) Is DO min within the environmental limitations? 2) At what distance is the maximum deficit located. 3) Draw the oxygen sag curve? Given the saturation concentration at 15 °C and at mixed temperature = 10.15 mg/Larrow_forward
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