Whether the value of n equals to 138 is a bound state or not needs to be determined. If yes, the sort of state needs to be explained. Also, the radius of the orbit and number of revolutions taken by electron per second around the nucleus needs to be determined. Concept introduction: Bound state is defined as a quantum state of particle which is special as the particle in this state remains localized in one or more space regions. There may be external potential or due to another particle. If potential is due to the presence of another particle, a bound state is defined as a state that represents 2 or more particles having interaction energy more than the total energy of particles. The radius of the orbit can be calculated using the following relation: r n = n 2 h 2 4 π 2 m Z e 2 Here, n is principle quantum number, Z is atomic number , h is Planck’s constant, m is mass of electron and e is charge on electron. The revolutions make by the electrons around the nucleus can be calculated as follows: ω = n h 2 π m r 2 Here, n is principle quantum number, h is Planck’s constant, m is mass of electron and r is radius of the orbit.
Whether the value of n equals to 138 is a bound state or not needs to be determined. If yes, the sort of state needs to be explained. Also, the radius of the orbit and number of revolutions taken by electron per second around the nucleus needs to be determined. Concept introduction: Bound state is defined as a quantum state of particle which is special as the particle in this state remains localized in one or more space regions. There may be external potential or due to another particle. If potential is due to the presence of another particle, a bound state is defined as a state that represents 2 or more particles having interaction energy more than the total energy of particles. The radius of the orbit can be calculated using the following relation: r n = n 2 h 2 4 π 2 m Z e 2 Here, n is principle quantum number, Z is atomic number , h is Planck’s constant, m is mass of electron and e is charge on electron. The revolutions make by the electrons around the nucleus can be calculated as follows: ω = n h 2 π m r 2 Here, n is principle quantum number, h is Planck’s constant, m is mass of electron and r is radius of the orbit.
Solution Summary: The author explains if n equals 138 is a bound state and the radius of the orbit and number of revolutions taken by electron per second around the nucleus.
Definition Definition Number of protons in the nucleus of an atom. It uniquely identifies an element, as the number of protons determines the element's properties. The periodic table of elements is arranged based on increasing atomic numbers, allowing scientists to easily locate and study elements.
Chapter 8, Problem 106IAE
Interpretation Introduction
Interpretation:
Whether the value of n equals to 138 is a bound state or not needs to be determined. If yes, the sort of state needs to be explained. Also, the radius of the orbit and number of revolutions taken by electron per second around the nucleus needs to be determined.
Concept introduction:
Bound state is defined as a quantum state of particle which is special as the particle in this state remains localized in one or more space regions.
There may be external potential or due to another particle. If potential is due to the presence of another particle, a bound state is defined as a state that represents 2 or more particles having interaction energy more than the total energy of particles.
The radius of the orbit can be calculated using the following relation:
rn=n2h24π2mZe2
Here, n is principle quantum number, Z is atomic number, h is Planck’s constant, m is mass of electron and e is charge on electron.
The revolutions make by the electrons around the nucleus can be calculated as follows:
ω=nh2πmr2
Here, n is principle quantum number, h is Planck’s constant, m is mass of electron and r is radius of the orbit.
Can you please help mne with this problem. Im a visual person, so can you redraw it, potentislly color code and then as well explain it. I know im given CO2 use that to explain to me, as well as maybe give me a second example just to clarify even more with drawings (visuals) and explanations.
Part 1. Aqueous 0.010M AgNO 3 is slowly added to a 50-ml solution containing both carbonate [co32-] = 0.105 M
and sulfate [soy] = 0.164 M anions. Given the ksp of Ag2CO3 and Ag₂ soy below. Answer the ff:
Ag₂ CO3 = 2 Ag+ caq) + co} (aq)
ksp = 8.10 × 10-12
Ag₂SO4 = 2Ag+(aq) + soy² (aq) ksp = 1.20 × 10-5
a) which salt will precipitate first?
(b)
What % of the first anion precipitated will remain in the solution.
by the time the second anion starts to precipitate?
(c) What is the effect of low pH (more acidic) condition on the separate of the carbonate and
sulfate anions via silver precipitation? What is the effect of high pH (more basic)? Provide appropriate
explanation per answer
Part 4. Butanoic acid (ka= 1.52× 10-5) has a partition coefficient of 3.0 (favors benzene) when distributed bet.
water and benzene. What is the formal concentration of butanoic acid in each phase when
0.10M aqueous butanoic acid is extracted w❘ 25 mL of benzene
100 mL of
a) at pit 5.00
b) at pH 9.00
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Quantum Numbers, Atomic Orbitals, and Electron Configurations; Author: Professor Dave Explains;https://www.youtube.com/watch?v=Aoi4j8es4gQ;License: Standard YouTube License, CC-BY