FUND OF ENG THERMODYN(LLF)+WILEYPLUS
9th Edition
ISBN: 9781119391777
Author: MORAN
Publisher: WILEY
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An air nozzle has an efficiency of .90 and is adiabatic. air enters at p1=200 kPa, T1=1300 K with negligible velocity. air exits at p2=130 kPa. use dead state variables of T0=293 k and P0= 100 kPa and a variable heat capacity. what is t2 and the rate of exergy destruction?
Example 7: Throttling
Water is throttled from 1 bar, 60 °C, to 0.5 bar, and to 0.1 bar. In
each case calculate the exit temperature and the entropy
generation.
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- I have already found the enthalpies for this problem I just need to find the mass flowrate for the air h1 = 317.549 kJ/kg h2 = 114.245 kJ/kg h3 = 0.0159723 kJ/kg h4 = 37.2487 kJ/kgarrow_forwardFast ,Do not hold. Two heat engines receive heat from a source at temperature of 550◦C. Heat engine "A" receives 200 kJ of heat and rejects the waste heat to a sink at 180◦C. Heat engine "B" receives 180 kJ of heat and rejects the waste heat to a sink at 120◦C.(a) Caclualte the generated entropy, Sgen, in both processes.(b) Based on your answer in part (a), identify the heat transfer that is more irreversible.arrow_forward20. If 10 kg/min of air are compressed isothermally from P1 = 96 kPa and Vi 7.65 m³/min to P2 = 620 kPa, find the work, change in entropy %3D for a non-flow process and a steady flow process with vị = 15 m/s and v2 = 60 m/s.arrow_forward
- Ht.7. An ideal gas , Cp=(5/2)R and Cv=(3/2)R, is changed from (P1=1 bar and V1t= 10m3) to (P2=10bar and V2t=1m3) by the following mechanically reversible processes: a. Isothermal compressionarrow_forwarda. Find an appropriate expression for the change in entropy in the following two cases: 1) S=S(TV) 2) S=S(TP) Where: S is entropy. T is temperature. V is volume, P is pressure b. Prove the following two thermodynamic property relationships ac Where: T. P. V are temperature, pressure and volume, respectively. C. and C, are specific heats at constant volume and constant pressure, respectively.arrow_forwardKJ 14. For certain ideal gas, R = 0.32 and c, 1160 kgm-K .(a) Find c, and k. (b) kgm-K* If 6 kgm of this gas undergo a reversible nonflows constant pressure process from V = 2.1 cu. m, P1 = 0.7 MPaa to a state where T2 = 830 K, find AH, ALĮ and Q and W. %3Darrow_forward
- p88#5. while the pressure remains constant at 689.5 kPa the volume of a system of air changes from 0.567m^3. what are the (a)internal energy,(b) enthalphy ,(c) Q, (d) entropy, (e) if the process is nonflow and internally reversible,what is work?arrow_forwardWrite legibly, provide manual step by step solution, and diagram for below given problem. A throttling calorimeter is connected to the superheated steam line supplying steam to the auxiliary feed pump on a ship. The line pressure measures 2.5 Mpa. The calorimeter pressure is 110 kpa and 150 deg C. Determine the entropy of the steam line. a. 6.8 KJ/kg-deg K c. 6.6 KJ/kg-deg Kb. 6.2 KJ/kg-deg K d. 7.5KJ/kg-deg Karrow_forwardReversible interactions reach 1.234 kg/s of 321 kJ / s with certain gases, but keepthe temperature constant at 29.67 ° C. For this gas, Cp = 2.232 and Cv = 1.713 kJ / kg.° K. P1 is 687 kPa. For both nonflow and steady flow (ΔP = 0, ΔK = 0) processes. Find(a) V1,V2, and, P2, (b) work (c) ΔS, ΔHarrow_forward
- a (a) Air in (b) (c) Diffuser Compressor Combustors 2 State State 1 80 State 2 3300 State 3 3200 State 4 400 State 5 80 wwww Pressure (kPa) 3 Turbine 4 Figure 1: Figure for Problem 2. In a modern jet engine, air passes through the following states from the inlet to the outlet, as shown in Figure 1: Product gases out 260 780 1500 900 640 K 5 > Nozzle justify them) to find the compressor specific work. Temperature (K) For this problem, you may neglect any heat transfer, as well as neglect kinetic energy except at the outlet (state 5). Use the tables for obtaining properties (do not assume constant specific heat). Assume air is an ideal gas with ideal gas constant of R = 0.287 kJ/kg-K. Use the appropriate conservation equations and make approximations (and In a similar manner, find the turbine specific work. And finally, using similar arguments, find the nozzle exit velocity.arrow_forwardQ.6.A. Oxygen enters a nozzle with a negligible velocity at 440 K and 12 bar, and leaves at 1.9 bar. Determine the volumetric flow rate of the oxygen at the nozzle entrance if the nozzle exit area is 2.5 cm2 and the ratio of inlet temperature to the outlet equal 1.69. (Cy = 718 J/kg K and Cp = 1005 J/kg K)arrow_forwardDerive the formula of efficiency of the following: d. Brayton Cycle in terms pressure ratio rp and specific heat ratio k.arrow_forward
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